EEM 486: Computer Architecture Lecture 3 Designing Single Cycle Control
Lec 3.2 The Big Picture: Where are We Now? Control Datapath Memory Processor Input Output
Lec 3.3 An Abstract View of the Implementation Data Out Clk 5 RwRaRb bit Registers Rd ALU Clk Data In Data Address Ideal Data Memory Instruction Address Ideal Instruction Memory Clk PC 5 Rs 5 Rt 32 A B Next Address Control Datapath Control Signals Conditions
Lec 3.4 Recap: A Single Cycle Datapath We have everything except control signals (underline)
Lec 3.5 Recap: Meaning of the Control Signals nPC_MUX_sel: 0 PC <– PC PC <– PC SignExt(Im16) || 00 Adr Inst Memory Adder PC Clk 00 Mux 4 nPC_MUX_sel PC Ext imm16
Lec 3.6 Recap: Meaning of the Control Signals ExtOp: “zero”, “sign” ALUsrc: 0 regB; 1 immed ALUctr: “add”, “sub”, “or” MemWr:1 write memory MemtoReg:0 ALU; 1 Mem RegDst:0 “rt”; 1 “rd” RegWr:1 write register
Lec 3.7 RTL: The Add Instruction addrd, rs, rt mem[PC]Fetch the instruction from memory R[rd] <- R[rs] + R[rt]The actual operation PC <- PC + 4Calculate the next instruction’s address oprsrtrdshamtfunct bits 5 bits
Lec 3.8 Instruction Fetch Unit at the Beginning of Add Fetch the instruction from Instruction memory: Instruction <- mem[PC] Same for all instructions Adr Inst Memory Adder PC Clk 00 Mux 4 nPC_MUX_sel imm16 Instruction 0 1
Lec 3.9 The Single Cycle Datapath During Add R[rd] <- R[rs] + R[rt]
Lec 3.10 Instruction Fetch Unit at the End of Add PC <- PC + 4 This is the same for all instructions except: Branch and Jump Adr Inst Memory Adder PC Clk 00 Mux 4 nPC_MUX_sel imm16 Instruction 0 1
Lec 3.11 The Single Cycle Datapath During Or Immediate R[rt] <- R[rs] or ZeroExt[Imm16] RegDst =
Lec 3.12 The Single Cycle Datapath During Or Immediate
Lec 3.13 The Single Cycle Datapath During Load R[rt] <- Data Memory [ R[rs] + SignExt[imm16] ]
Lec 3.14 The Single Cycle Datapath During Store Data Memory [ R[rs] + SignExt[imm16] ] <- R[rt]
Lec 3.15 The Single Cycle Datapath During Store
Lec 3.16 The Single Cycle Datapath During Branch if (R[rs] - R[rt] == 0) then Zero <- 1 ; else Zero <- 0
Lec 3.17 Instruction Fetch Unit at the End of Branch What is encoding of nPC_sel? Direct MUX select? Branch / not branch Instruction nPC_sel Adr Inst Memory Adder PC Clk 00 Mux 4 imm Zero nPC_MUX_sel
Lec 3.18 Step 4: Given Datapath: RTL -> Control ALUctr RegDstALUSrcExtOpMemtoRegMemWr Zero Instruction Imm16RdRsRt nPC_sel Adr Inst Memory DATA PATH Control Op Fun RegWr
Lec 3.19 Summary of Control Signals inst Register Transfer ADDR[rd] <– R[rs] + R[rt];PC <– PC + 4 ALUsrc = RegB, ALUctr = “add”, RegDst = rd, RegWr, nPC_sel = “+4” SUBR[rd] <– R[rs] – R[rt];PC <– PC + 4 ALUsrc = RegB, ALUctr = “sub”, RegDst = rd, RegWr, nPC_sel = “+4” ORiR[rt] <– R[rs] + zero_ext(Imm16); PC <– PC + 4 ALUsrc = Im, Extop = “Z”, ALUctr = “or”, RegDst = rt, RegWr, nPC_sel = “+4” LOADR[rt] <– MEM[ R[rs] + sign_ext(Imm16)];PC <– PC + 4 ALUsrc = Im, Extop = “Sn”, ALUctr = “add”, MemtoReg, RegDst = rt, RegWr, nPC_sel = “+4” STOREMEM[ R[rs] + sign_ext(Imm16)] <– R[rt];PC <– PC + 4 ALUsrc = Im, Extop = “Sn”, ALUctr = “add”, MemWr, nPC_sel = “+4” BEQif ( R[rs] == R[rt] ) then PC <– [PC + sign_ext(Imm16)] || 00 else PC <– PC + 4 nPC_sel = “Br”, ALUctr = “sub”
Lec 3.20 Summary of the Control Signals
Lec 3.21 Concept of Local Decoding Main Control op 6 ALU Control (Local) func N 6 ALUop ALUctr 3 ALU R-typeorilwswbeq RegDst ALUSrc MemtoReg RegWrite MemWrite Branch ExtO p ALUop x “R-type” Or Add x 1 x x 0 x x Sub op
Lec 3.22 Encoding of ALUop In this exercise, ALUop has to be 2 bits wide to represent: (1) “R-type” instructions “I-type” instructions that require the ALU to perform: -(2) Or, (3) Add, and (4) Subtract To implement the full MIPS ISA, ALUop has to be 3 bits to represent: (1) “R-type” instructions “I-type” instructions that require the ALU to perform: -(2) Or, (3) Add, (4) Subtract, (5) And, and (6) Xor Main Control op 6 ALU Control (Local) func N 6 ALUop ALUctr 3 R-typeorilwswbeq ALUop (Symbolic)“R-type”OrAdd Sub ALUop
Lec 3.23 Decoding of the “func” Field Main Control op 6 ALU Control (Local) func N 6 ALUop ALUctr 3 oprsrtrdshamtfunct R-type funct Instruction Operation add subtract and or set-on-less-than ALUctr ALU Operation And Or Add Subtract Set-on-less-than ALUctr ALU R-typeorilwswbeq ALUop (Symbolic)“R-type”OrAdd Sub ALUop
Lec 3.24 Truth Table for ALUctr R-typeorilwswbeq ALUop (Symbolic) “R-type”OrAdd Sub ALUop funct Instruction Op add subtract and or set-on-less-than
Lec 3.25 Logic Equation for ALUctr ALUctr = !ALUop & ALUop + ALUop & !func & func & !func ALUopfunc bit ALUctr 0x1xxxx1 1xx xx10101 This makes func a don’t care
Lec 3.26 Logic Equation for ALUctr ALUopfunc bit 000xxxx1 ALUctr 0x1xxxx1 1xx xx xx10101 ALUctr = !ALUop & !ALUop + !ALUop & ALUop + ALUop & !func & !func
Lec 3.27 Logic Equation for ALUctr ALUopfunc bit ALUctr 01xxxxx1 1xx xx10101 ALUctr = !ALUop & ALUop + ALUop & !func & func & !func & func + ALUop & func & !func & func & !func
Lec 3.28 ALU Control Block ALU Control (Local) func 3 6 ALUop ALUctr 3 ALUctr = !ALUop & ALUop + ALUop & !func & func & !func ALUctr = !ALUop & !ALUop + !ALUop & ALUop ALUop & !func & !func ALUctr = !ALUop & ALUop + ALUop & !func & func & !func & func + ALUop & func & !func & func & !func
Lec 3.29 Step 5: Logic For Each Control Signal nPC_sel <= if (OP == BEQ) then “Br” else “+4” ALUsrc <=if (OP == “Rtype”) then “regB” else “immed” ALUctr<= if (OP == “Rtype”) then funct elseif (OP == ORi) then “OR” elseif (OP == BEQ) then “sub” else “add” ExtOp <= _____________ MemWr<= _____________ MemtoReg<= _____________ RegWr:<=_____________ RegDst:<= _____________
Lec 3.30 Step 5: Logic for Each Control Signal nPC_sel <= if (OP == BEQ) then “Br” else “+4” ALUsrc <=if (OP == “Rtype”) then “regB” else “immed” ALUctr<= if (OP == “Rtype”) then funct elseif (OP == ORi) then “OR” elseif (OP == BEQ) then “sub” else “add” ExtOp <= if (OP == ORi) then “zero” else “sign” MemWr<= (OP == Store) MemtoReg<= (OP == Load) RegWr:<= if ((OP == Store) || (OP == BEQ)) then 0 else 1 RegDst:<= if ((OP == Load) || (OP == ORi)) then 0 else 1
Lec 3.31 “Truth Table” for the Main Control Main Control op 6 ALU Control (Local) func 3 6 ALUop ALUctr 3 RegDst ALUSrc :
Lec 3.32 “Truth Table” for RegWrite RegWrite = R-type + ori + lw = !op & !op & !op & !op & !op & !op (R-type) + !op & !op & op & op & !op & op (ori) + op & !op & !op & !op & op & op (lw) R-typeorilwswbeq RegWrite11100 op
Lec 3.33 PLA Implementation of the Main Control.....
Lec 3.34 Putting it All Together: A Single Cycle Processor
Lec 3.35 Recap: An Abstract View of the Critical Path (Load) Critical Path (Load Operation) = PC’s Clk-to-Q + Instruction Memory’s Access Time + Register File’s Access Time + ALU to Perform a 32-bit Add + Data Memory Access Time + Setup Time for Register File Write + Clock Skew Clk 5 RwRaRb bit Registers Rd ALU Clk Data In Data Address Ideal Data Memory Instruction Address Ideal Instruction Memory Clk PC 5 Rs 5 Rt 16 Imm 32 A B Next Address
Lec 3.36 Worst Case Timing (Load) Clk PC Rs, Rt, Rd, Op, Func Clk-to-Q ALUctr Instruction Memory Access Time Old ValueNew Value RegWrOld ValueNew Value Delay through Control Logic busA Register File Access Time Old ValueNew Value busB ALU Delay Old ValueNew Value Old ValueNew Value Old Value ExtOpOld ValueNew Value ALUSrcOld ValueNew Value MemtoRegOld ValueNew Value AddressOld ValueNew Value busWOld ValueNew Delay through Extender & Mux Register Write Occurs Data Memory Access Time
Lec 3.37 Drawback of this Single Cycle Processor Long cycle time: Cycle time must be long enough for the load instruction: PC’s Clock -to-Q + Instruction Memory Access Time + Register File Access Time + ALU Delay (address calculation) + Data Memory Access Time + Register File Setup Time + Clock Skew Cycle time for load is much longer than needed for all other instructions
Lec 3.38 Single cycle datapath => CPI=1, CCT => long 5 steps to design a processor 1. Analyze instruction set => datapath requirements 2. Select set of datapath components & establish clock methodology 3. Assemble datapath meeting the requirements 4. Analyze implementation of each instruction to determine setting of control points that effects the register transfer. 5. Assemble the control logic Control is the hard part MIPS makes control easier Instructions same size Source registers always in same place Immediates same size, location Operations always on registers/immediates Summary Control Datapath Memory Processor Input Output