5 Problem 1 Find the OH- if the [H+] is 2.3 x 10 -3 M. Remember Kw= [H+] x [OH-]1x M2 = 2.3 x M x [OH-]Answer4.35 x M
6 Problem 2 Find the [H+] if the [OH-] is 7.31 x 10 -3M. Remember Kw= [H+] x [OH-]1x M2 = 7.31 x M x [H+]Answer1.37 x M
7 Problem 3 Find the pH if the [H+] is 8.91 x 10 -5 M. Remember pH = - log of [H+](-)Log of 8.91 x MAnswer4.05
8 Arrhenius Came up with theory of ionization. Stated that acids are compounds containing hydrogen that ionize to yield H+ in aqueous solution and bases are compounds that ionize yield OH- in aqueous solution.
9 IonizationWhen ions form from a covalent compound.
10 Lewis acidSubstance that can accept a pair of electrons to form a covalent bond.Acids are electron - pair acceptors.
11 Lewis baseSubstance that can donate a pair of electrons to form covalent bond.Bases are electron - pair donors.
12 Naming acids: Rule 1 If anion ends with ide. The acid is named with the prefix hydro, the root name of the anion, and the suffix ic.ide Hydro (base word) icEx: HCl - hydrochloric acid.
13 Naming acids: Rule 2 If the anion ends with ite. The acid named is formed from the root name of the anion with a suffix of ous or rous, which replace iteExample: H2SO3 - sulfurous acid . Anion was sulfite SO3-2.Ite (base word) ous
14 Naming acids: Rule 3 If the anion ends with ate. The acid named is formed from the root name of the anion with a suffix of ic or ric, which replace ate.Example: H2SO4 Sulfuric acid. Anion was sulfate SO4-2ate (base word) ic
15 Strong acid plus a weak base Will yield an aqueous salt and water.The ions in the salt are dissociated.
16 Problem 4 Find the pH if the [OH-] is 3.71 x 10 -8 M. Remember pH = - log of [H+] , but you have the [OH-] .Find the [H+] first.
17 Work 1 x 10 -14 M2 = 3.71 x 10 -8 M x [H+] [H+] = 2.70 x 10-7 M Take the –log of 2.70 x 10-7Answer =6.57
18 Problem 5 Find the pH if the [OH-] is 9.18 x 10 -5 M. Remember pH = - log of [H+] , but you have the [OH-] .Find the [H+] first.
19 Work 1 x 10 -14 M2 = 9.18 x 10 -5 M x [H+] [H+] = 1.09 x 10-10 M Take the –log of 1.09 x 10-10Answer =9.96
20 Problem 6Find the molarity of the sodium hydroxide solution if you have 57 g of sodium hydroxide dissolved in 800 ml of water.
21 Work57 g NaOH 1 mol NaOH =.8 L g NaOHAnswer1.78 M