People forget how fast you did a job but they remember how well you did it.

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People forget how fast you did a job but they remember how well you did it.

Acids and Bases Lesson 4

Anhydrides

Problem 1 Find the OH- if the [H+] is 2.3 x 10 -3 M. Remember
Kw= [H+] x [OH-] 1x M2 = 2.3 x M x [OH-] Answer 4.35 x M

Problem 2 Find the [H+] if the [OH-] is 7.31 x 10 -3M. Remember
Kw= [H+] x [OH-] 1x M2 = 7.31 x M x [H+] Answer 1.37 x M

Problem 3 Find the pH if the [H+] is 8.91 x 10 -5 M. Remember
pH = - log of [H+] (-)Log of 8.91 x M Answer 4.05

Arrhenius Came up with theory of ionization.
Stated that acids are compounds containing hydrogen that ionize to yield H+ in aqueous solution and bases are compounds that ionize yield OH- in aqueous solution.

Ionization When ions form from a covalent compound.

Lewis acid Substance that can accept a pair of electrons to form a covalent bond. Acids are electron - pair acceptors.

Lewis base Substance that can donate a pair of electrons to form covalent bond. Bases are electron - pair donors.

Naming acids: Rule 1 If anion ends with ide.
The acid is named with the prefix hydro, the root name of the anion, and the suffix ic. ide  Hydro (base word) ic Ex: HCl - hydrochloric acid.

Naming acids: Rule 2 If the anion ends with ite.
The acid named is formed from the root name of the anion with a suffix of ous or rous, which replace ite Example: H2SO3 - sulfurous acid . Anion was sulfite SO3-2. Ite  (base word) ous

Naming acids: Rule 3 If the anion ends with ate.
The acid named is formed from the root name of the anion with a suffix of ic or ric, which replace ate. Example: H2SO4 Sulfuric acid. Anion was sulfate SO4-2 ate (base word) ic

Strong acid plus a weak base
Will yield an aqueous salt and water. The ions in the salt are dissociated.

Problem 4 Find the pH if the [OH-] is 3.71 x 10 -8 M. Remember
pH = - log of [H+] , but you have the [OH-] . Find the [H+] first.

Work 1 x 10 -14 M2 = 3.71 x 10 -8 M x [H+] [H+] = 2.70 x 10-7 M
Take the –log of 2.70 x 10-7 Answer = 6.57

Problem 5 Find the pH if the [OH-] is 9.18 x 10 -5 M. Remember
pH = - log of [H+] , but you have the [OH-] . Find the [H+] first.

Work 1 x 10 -14 M2 = 9.18 x 10 -5 M x [H+] [H+] = 1.09 x 10-10 M
Take the –log of 1.09 x 10-10 Answer = 9.96

Problem 6 Find the molarity of the sodium hydroxide solution if you have 57 g of sodium hydroxide dissolved in 800 ml of water.

Work 57 g NaOH 1 mol NaOH = .8 L g NaOH Answer 1.78 M

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