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People forget how fast you did a job but they remember how well you did it.

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Presentation on theme: "People forget how fast you did a job but they remember how well you did it."— Presentation transcript:

1 People forget how fast you did a job but they remember how well you did it.

2

3 Acids and Bases Lesson 4

4 Anhydrides

5 Problem 1 Find the OH - if the [H + ] is 2.3 x 10 -3 M. Remember K w = [H + ] x [OH - ] 1x 10 -14 M 2 = 2.3 x 10 -3 M x [OH - ] Answer 4.35 x 10 -12 M Find the OH - if the [H + ] is 2.3 x 10 -3 M. Remember K w = [H + ] x [OH - ] 1x 10 -14 M 2 = 2.3 x 10 -3 M x [OH - ] Answer 4.35 x 10 -12 M

6 Problem 2 Find the [H + ] if the [OH -] is 7.31 x 10 -3 M. Remember K w = [H + ] x [OH - ] 1x 10 -14 M 2 = 7.31 x 10 -3 M x [H + ] Answer 1.37 x 10 -12 M Find the [H + ] if the [OH -] is 7.31 x 10 -3 M. Remember K w = [H + ] x [OH - ] 1x 10 -14 M 2 = 7.31 x 10 -3 M x [H + ] Answer 1.37 x 10 -12 M

7 Problem 3 Find the pH if the [H + ] is 8.91 x 10 -5 M. Remember pH = - log of [H + ] (-)Log of 8.91 x 10 -5 M Answer 4.05 Find the pH if the [H + ] is 8.91 x 10 -5 M. Remember pH = - log of [H + ] (-)Log of 8.91 x 10 -5 M Answer 4.05

8 Arrhenius Came up with theory of ionization. Stated that acids are compounds containing hydrogen that ionize to yield H + in aqueous solution and bases are compounds that ionize yield OH - in aqueous solution. Came up with theory of ionization. Stated that acids are compounds containing hydrogen that ionize to yield H + in aqueous solution and bases are compounds that ionize yield OH - in aqueous solution.

9 Ionization When ions form from a covalent compound.

10 Lewis acid Substance that can accept a pair of electrons to form a covalent bond. Acids are electron - pair acceptors. Substance that can accept a pair of electrons to form a covalent bond. Acids are electron - pair acceptors.

11 Lewis base Substance that can donate a pair of electrons to form covalent bond. Bases are electron - pair donors. Substance that can donate a pair of electrons to form covalent bond. Bases are electron - pair donors.

12 Naming acids: Rule 1 If anion ends with ide. The acid is named with the prefix hydro, the root name of the anion, and the suffix ic. ide  Hydro (base word) ic Ex: HCl - hydrochloric acid. If anion ends with ide. The acid is named with the prefix hydro, the root name of the anion, and the suffix ic. ide  Hydro (base word) ic Ex: HCl - hydrochloric acid.

13 Naming acids: Rule 2 If the anion ends with ite. The acid named is formed from the root name of the anion with a suffix of ous or rous, which replace ite Example: H 2 SO 3 - sulfurous acid. Anion was sulfite SO 3 -2. Ite  (base word) ous If the anion ends with ite. The acid named is formed from the root name of the anion with a suffix of ous or rous, which replace ite Example: H 2 SO 3 - sulfurous acid. Anion was sulfite SO 3 -2. Ite  (base word) ous

14 Naming acids: Rule 3 If the anion ends with ate. The acid named is formed from the root name of the anion with a suffix of ic or ric, which replace ate. Example: H 2 SO 4 Sulfuric acid. Anion was sulfate SO 4 -2 ate  (base word) ic If the anion ends with ate. The acid named is formed from the root name of the anion with a suffix of ic or ric, which replace ate. Example: H 2 SO 4 Sulfuric acid. Anion was sulfate SO 4 -2 ate  (base word) ic

15 Strong acid plus a weak base Will yield an aqueous salt and water. The ions in the salt are dissociated. Will yield an aqueous salt and water. The ions in the salt are dissociated.

16 Problem 4 Find the pH if the [OH - ] is 3.71 x 10 -8 M. Remember pH = - log of [H + ], but you have the [OH - ]. Find the [H + ] first. Find the pH if the [OH - ] is 3.71 x 10 -8 M. Remember pH = - log of [H + ], but you have the [OH - ]. Find the [H + ] first.

17 Work 1 x 10 -14 M 2 = 3.71 x 10 -8 M x [H + ] [H + ] = 2.70 x 10 -7 M Take the –log of 2.70 x 10 -7 Answer = 6.57 1 x 10 -14 M 2 = 3.71 x 10 -8 M x [H + ] [H + ] = 2.70 x 10 -7 M Take the –log of 2.70 x 10 -7 Answer = 6.57

18 Problem 5 Find the pH if the [OH - ] is 9.18 x 10 -5 M. Remember pH = - log of [H + ], but you have the [OH - ]. Find the [H + ] first. Find the pH if the [OH - ] is 9.18 x 10 -5 M. Remember pH = - log of [H + ], but you have the [OH - ]. Find the [H + ] first.

19 Work 1 x 10 -14 M 2 = 9.18 x 10 -5 M x [H + ] [H + ] = 1.09 x 10 -10 M Take the –log of 1.09 x 10 -10 Answer = 9.96 1 x 10 -14 M 2 = 9.18 x 10 -5 M x [H + ] [H + ] = 1.09 x 10 -10 M Take the –log of 1.09 x 10 -10 Answer = 9.96

20 Problem 6 Find the molarity of the sodium hydroxide solution if you have 57 g of sodium hydroxide dissolved in 800 ml of water.

21 Work 57 g NaOH 1 mol NaOH =.8 L 40.01 g NaOH Answer 1.78 M 57 g NaOH 1 mol NaOH =.8 L 40.01 g NaOH Answer 1.78 M


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