Presentation is loading. Please wait.

Presentation is loading. Please wait.

Electric Drives1 ELECTRIC DRIVES Ion Boldea S.A.Nasar 1998.

Similar presentations


Presentation on theme: "Electric Drives1 ELECTRIC DRIVES Ion Boldea S.A.Nasar 1998."— Presentation transcript:

1 Electric Drives1 ELECTRIC DRIVES Ion Boldea S.A.Nasar 1998

2 Electric Drives2 14. LARGE POWER DRIVES

3 Electric Drives VOLTAGE SOURCE CONVERTER SYNCHRONOUS MOTOR DRIVES Figure A 3 level GTO inverter - SM drive

4 Electric Drives4 Figure A cycloconverter SM drive.

5 Electric Drives5 Figure Output voltage V a, and ideal current i a of the cycloconverter for unity power factor operation of SM Figure Input phase voltage and current of cycloconverters

6 Electric Drives VECTOR CONTROL IN VOLTAGE SOURCE CONVERTER SM DRIVES The d - q model equations for a salient pole cageless rotor SM is (chapter 10): (14.1) (14.2) (14.3) (14.4) (14.5) (14.6) (14.7)

7 Electric Drives7 Figure Space vector diagram of SM at steady state and unity power factor ( 1 = 0) During the vector control process the stator current space vector differs from the reference space vector. Consequently the actual current may be written in flux (M, T) coordinates: (14.8)

8 Electric Drives8 (14.9) The stator flux may be written as: (14.10) where: (14.11) is strictly valid for L d = L q. For L d = L q the torque from (14.6) is: (14.12) with(14.13) From (14.11) we may calculate: (14.14)

9 Electric Drives9 The stator flux has to be controlled directly through the field current control. But first the stator flux has to be estimated. We again resort to the combined voltage (in stator coordinates) and current model (in rotor coordinates): (14.15) (14.16) (14.17) For low frequencies the current model prevails while at high frequency the voltage model takes over. If only short periods of low speed are required, the current model might be avoided, by using instead the reference flux s * in stator coordinates: (14.18)

10 Electric Drives10 Figure Vector current control of SM fed from voltage source type (1 or 2 stages) P.E.Cs and unity power factor

11 Electric Drives11 Figure Voltage decoupler in stator flux coordinates and d.c. current controllers The voltage decoupler with d.c. current controllers is known to give better performance around and above rated frequency (speed) and to be less sensitive to motor parameter detuning. Flux control as done in figure proved to provide fast response in MW power motors due to the delays compensation by nonzero transient flux current reference i x *.

12 Electric Drives DIRECT TORQUE AND FLUX CONTROL (DTFC) Figure Flux and torque observer For unity power factor the angle between stator flux and current is Also a reactive torque RT is defined as: (14.22) where Q 1 is the reactive power and 1 the primary frequency.

13 Electric Drives13 The reactive torque RT may be estimated from (14.15) and works well for steady state and above 5% of rated speed. To make sure that the power factor is unity the should be driven to zero through adding or subtracting from reference field current (figure 14.9). Figure DTFC of voltage source PWM converter SM drives

14 Electric Drives Sensorless control We should notice that the rotor position is not present directly in the DTFC scheme but the rotor speed is. Consequently, for sensorless control, a rotor speed estimator is required. We may define rotor speed as: (14.23) where is the stator flux,, space vector speed and is flux vector angle with respect to rotor d axis. To a first approximation (L d = L q ) for cos 1 = 0 the torque is (14.9): (14.24) with(14.25)

15 Electric Drives15 So(14.26) i F and i s are measured and L dm has to be known. Consequently:(14.27) Equation (14.27) may represent an estimator for. On the other hand the stator flux speed is as shown in chapter 11: (14.28) where T is the sampling time. Using (14.28) in (14.27): (14.29)

16 Electric Drives LARGE MOTOR DRIVES: WORKING LESS TIME PER DAY IS BETTER Large power drives do not work, in general, 24 hours a day, but many times they come close to this figure. Let us suppose that a cement mill has a 5MW ball mill drive that works about 8000 hours / year, that is about 22 hours / day (average) for 365 days and uses 45000MWh of energy. A 16MW drive would work for 4000 hours to consume about 44000MWh (not much less). However the 16MW drive may work only off peak hours. The energy tariffs are high for 6 hours (0.12$/kWh), normal for 8 hours (0.09$/kWh) and low for 10 hours (0.04$/kWh). As the high power drive works an average of 11hours / day / 365days (or 12hours / day excluding national holidays) it may take advantage of low tarrif for 10 hours and work only 2 hours for normal tarrif.. The lower power drive however has to work at least 4 peak tariff hours. Though the energy consumption is about the same, the cost of energy may be reduced form $3,700,000 to $1,700,000 per year, that is less than 50%. As investment costs are not double for doubling the power (on 60% more) and the maintenance costs are about the same, the revenue time is favorable to the higher power drive working for less time per day.

17 Electric Drives RECTIFIER - CURRENT SOURCE INVERTER SM DRIVES - BASIC SCHEME Figure Basic scheme of Rectifier - CSI SM drive

18 Electric Drives RECTIFIER - CSI - SM DRIVE - STEADY STATE WITH LOAD COMMUTATION Figure Ideal stator current waveforms

19 Electric Drives19 As the commutation process is rather fast - in comparison with the current period - the machine behaves approximately according to the voltage behind subtransient inductance principle (figure 14.12). The voltage behind the subtransient inductance L, V 1, is in fact, the terminal voltage fundamental if the phase resistance is neglected. The no load (e.m.f.) voltage E 1 is also sinusoidal. The space vector (or phasor) diagram may be used for the current fundamental I 1 for L - L with L as synchronous inductance and L the subtransient inductance along the dq axes (figure 14.13) [7]. Figure Equivalent circuit under mechanical steady state

20 Electric Drives20 Figure Space vector (or phasor) diagram for the voltage behind subtransient inductance (14.30) (14.31) In general the machine may have salient poles (L d L q ) and, definitely, damper windings (L d << L d, L q << L q ). The currents induced in the damper windings due to the nonsinusoidal character of stator currents are neglected here. During commutation intervals the machine reacts with the subtransient inductance. An average of d - q subtransient inductances L d and L q is considered to represent the so called commutation inductance L c given by: (14.32)

21 Electric Drives Commutation and steady state equations To study the commutation process let us suppose that, at time zero, phases a and c are conducting (Figure 14.14) - (T 1 T 2 in conduction): (14.33) During this commutation process phases +a and +b are both conducting (in parallel) with phase -c continuing conduction (figure 14.15). The loop made of phases a, b in parallel (figure 14.15) has the equation: (14.34) (14.35) Figure Stator m.m.f. (60 0 jump from T 1 T 2 to T 2 T 3 conduction)

22 Electric Drives22 Figure Equivalent circuit for commutation At the end of the commutation interval (t = t c ) phase b is conducting: (14.36) Eliminating i b from (14.34) - (14.35) yields: (14.37)

23 Electric Drives23 For successful commutation the current in phase a should decrease to zero during commutation interval (di a /dt < 0). Consequently the line voltage V ab1 should necessarily be positive when the current switches from phase +a to phase +b (figure 14.16). Before V ab1 goes to zero a time interval t off ( off / r ) is required with i a = 0 to allow the recombination of charges in the thyristor T 1. According to figure the phasing of V ab1 is: (14.38) Figure The commutation process

24 Electric Drives24 Integrating (14.38) from t = 0 to t c = u / r, we obtain: (14.39) The angle u corresponds to the overlapping time of currents i a and i b. For I d = 0, u = 0 and should be greater than u for successful commutation. Ideally - u = off should be kept constant so both and u should increase with current. The rms phase current fundamental is related to the d.c. current I d by: (14.40) The inverter voltage V I is made of line voltage segments disturbed only during the commutation process: (14.42) (14.43) Finally, making use of (14.37) - (14.43), we obtain the average inverter voltage V Iav : (14.44)

25 Electric Drives25 Figure Fundamental phase current and voltage phasing So the commutation process produces a reduction in the motor terminal voltage V 1 by for a givenV Iav. Neglecting the power losses in the CSI and in the motor: (14.45) As expected, the simultaneous torque T e (t) is: (14.46)

26 Electric Drives26 Figure Inverter voltage V I (t) and motor torque pulsations during steady state

27 Electric Drives Ideal no load speed To calculate the ideal no load speed (zero I d, zero torque) we have to use all equations in this section (from (14.30) - (14.31)) to obtain: (14.47) Finally from (14.39) - (14.44): (14.48) Also the rectifier voltage V r is related to inverter voltage V I : (14.49)

28 Electric Drives Speed control options To vary speed we need to vary the ideal no load speed. The available options are: inverter voltage variation through rectifier voltage variation up to maximum voltage available; reducing the field current i F (flux weakening); modify the control angle 0. As 0 may lay in the 0 to 60 0 interval, this method is not expected to produce significant speed variations. However varying (or 0 ) is used to keep the power factor angle 1 rather constant () or off = cons. for safe commutation. Example A rectifier - CSI - SM drive is fed from a V L = 4.8 kVa.c. (line to line, rms), power source, the magnetisation inductance L dm = 0.05H and rated field current (reduced to the stator) i Fn = 200A. Determine: The maximum average rectifier voltage available; The ideal no load speed r0 for 0 = 0; For L c / L dm = 0.3, = 45 0 and I d = 100A, r / r0 = 0.95, calculate the fundamental voltage V 1 and the overlapping angle u

29 Electric Drives29 Solution: The fully controlled rectifier produces an average voltage V r (chapter 5, equations (5.54)): (14.50) So(14.51) The ideal no load speed (14.48) is: (14.52) The voltage fundamental V 1 becomes (14.44): (14.53) Now from (14.39) the overlapping angle u is found: (14.54) The overlapping angle u is small indicating an unusually strong damper winding. Higher values of u are practical.

30 Electric Drives Steady state speed - torque curves Figure Steady state curves (V Iav = cons., i F = cons.) a.) for constant 0 (position sensor); b.) for constant (terminal voltage zero crossing angle) Figure Steady state curves (V Iav = cons.), i F - variable, 1 = cons. = - u / 2

31 Electric Drives Line commutation during starting As already mentioned, at low speeds (below 5% of rated speed), the e.m.f. is not high enough to produce leading power factor ( 1 < 0) and thus secure load commutation (the resistive voltage drop is relatively high). For starting either line commutation or some forced commutation (with additional hardware) [4] is required. When the commutation of phases is initiated both thyristors conducting previously are first turned off by applying a negative voltage at machine terminals through increasing the rectifier delay angle to about To speedup the d.c. link current attenuation to zero the d.c. choke is short-circuited through the starting thyristor (figure 14.10).

32 Electric Drives Drive control loops Figure Speed control system (rectifier - CSI - SM drive) A PI speed controller is, in general, used: (14.55) with(14.56) The current controller may also be of PI type: (14.57) with(14.58)

33 Electric Drives33 As expected T ii 4T ii. The advance angle * will be increased with the load current as suggested in the previous section: (14.59) The initial angle provides for safety margin as required by slow, standard (low cost), thyristors: (14.60) To improve (speed up) the current response at high speeds an e.m.f. V c compensator may be added to the d.c. link current controller. The e.m.f. may be based on the flux behind the commutation inductance L c : (14.62) (14.63) Above 5% of rated speed the calculator is good enough even if based only on the voltage model.

34 Electric Drives Direct torque and flux control (DTFC) of rectifier - CSI - SM drives Figure Tentative DTFC system for CSI - SM drives

35 Electric Drives35 Figure CSI - current space vectors A hysteresis angle may be allowed at the boundary between sectors to reduce the switching frequency. The hysteresis band of the torque controller may be increased with speed to avoid PWM of current at high speeds.

36 Electric Drives SUB AND HYPERSYNCHRONOUS IM CASCADE DRIVES Limited speed control range for lower P.E.Cs ratings Limited speed control range is required in many applications such as high power pumps, fans, etc. Low motor speed range control, ( % around rated speed) implies frequency control. Stator frequency control, in either SMs or IMs, no matter the speed control range, requires full motor power P.E.Cs. So it is costly for the job done. It is very well known that the power balance in the wound rotor of IMs is characterised by the slip formula: (14.64) Neglecting for the time being the rotor winding loss (P Co2 = 0), the electric power injected into the rotor at slip frequency f 2 = Sf 1, is: (14.65)

37 Electric Drives37 The speed control range is defined through the minimum speed, rmin, or the maximum slip, S max, : (14.66) So the maximum active electric power injected in the wound rotor is: (14.67) For a 20% speed control range S max = 0.2 and thus the P.E.C. required to handle the rotor injected power P rmax is rated to S max, that is 20% - 30% of motor rated power. Figure Sub and hypersynchronous IM cascade system

38 Electric Drives38 In essence P r may be positive or negative and thus sub or hypersynchronous operation is feasible but the rotor side P.E.C. has to be able to produce positive and negative sequence voltages as: (14.68) For S < 0, f 2 < 0 and thus negative sequence voltages are required. As the machine is reversible both motoring and generating should be feasible, provided that a bi - directional power flow is allowed for through the rotor side P.E.Cs. Also, a smooth transition through S = 0 is required. For S = 0 (stator produced synchronism) f 2 = 0 and thus d.c. current (m.m.f) should be injected into the rotor. These challenging constraints restrict the types of P.E.Cs to be used for direct a.c. - a.c. conversion. Cyclo or matrix converters and two back to back voltage source PWM inverters are adequate for the scope.

39 Electric Drives Sub and hyper operation modes The induction machine equations in stator field (synchronous) coordinates are (chapter 8, equations (8.50) - (8.52)): (14.69) (14.70) (14.71) (14.72) For steady state (d/dt = 0) equation (14.70) becomes: (14.73) The ideal no load speed r0 is obtained for zero rotor current: (14.74)

40 Electric Drives40 From (14.69) with and d/dt = 0: (14.75) Neglecting r s (r s = 0): (14.76) From (14.74) with (14.76): (14.77) For ideal no load the stator and rotor voltages (in synchronous coordinates) are, for steady state, d.c. quantities. They may be written as: (14.78) (14.79) For V ro > 0 (zero phase shift) (and V s0 > 0), r0 0), r0 > 1 the hypersynchronous operation is obtained.

41 Electric Drives41 On the other hand multiplying (14.73) by 3/2i r * and extracting the real part we obtain: (14.80) As known is the electromagnetic (airgap) power transferred through the airgap from stator to rotor: (14.81) The definition of slip frequency 2 : (14.82) Also multiplying (14.73) by 3/2i r *, but extracting the imaginary part, we obtain: (14.83) (14.84)

42 Electric Drives Sub and hyper IM cascade control The power structure of the sub and hyper IM cascade drive is as shown in figure The control system is related to controlling the speed and, eventually, the stator reactive power for motoring and active and reactive stator power for generating. As the electromagnetic power P elm is obtained at fixed stator frequency, the torque T e is: (14.85) But the torque may be estimated from stator flux as: (14.86) Now we may define for stator a reactive torque: (14.87) (14.88) (14.89)

43 Electric Drives43 As the value of f 1 ( 1 ) is rather large the stator flux estimation may be performed through the voltage model: (14.90) (14.91) In essence the reference stator current has to be reproduced. What we need to control, in fact, is the rotor current : (14.92) where is the main flux magnetising current. Only approximately: (14.93) is still in synchronous coordinates. It has to be transformed into rotor coordinates: (14.94)

44 Electric Drives44 Figure Fixed stator frequency motor - generating control with sub and hypersynchronous IM cascade


Download ppt "Electric Drives1 ELECTRIC DRIVES Ion Boldea S.A.Nasar 1998."

Similar presentations


Ads by Google