Presentation on theme: "Synchronous Machines (AC Generators)"— Presentation transcript:
1Synchronous Machines (AC Generators) Muhammad Abdul MajidSlides part 2
2Induced voltage: Example Example : The peak flux density of the rotor magnetic field in a simple 2-pole 3-phase generator is 0.2 T; the mechanical speed of rotation is 3600 rpm; the stator diameter is 0.5 m; the length of its coil is 0.3 m and each coil consists of 15 turns of wire. The machine is Y-connected.What are the 3-phase voltages of the generator as a function of time?What is the rms phase voltage of the generator?What is the rms line/terminal voltage of the generator?
3Phasor diagram of a synchronous generator A phasor diagram of a synchronous generator with a unity power factor (resistive load)Lagging power factor (inductive load): a larger than for leading PF internal generated voltage EA is needed to form the same phase voltage.Leading power factor (capacitive load).For a given field current and magnitude of load current, the terminal voltage is lower for lagging loads and higher for leading loads.
6Measuring parameters of synchronous generator model
7ExampleA 2300-V 1000-kVA 0.8-PF-lagging 60-Hz two pole Y-connected synchronous generator has asynchronous reactance of 1.1 Ω and an armature resistance of 0.15 Ω.At 60 Hz, its friction and windage losses are 24 kW, and its core losses are 18 kW. The field circuit has a dc voltage of 200 V, and the maximum IF is 10 A. The resistance of the field circuit is adjustable over the range from 20 to 200 Ω
8Example The OCC is shown in Figure on next slide (a) How much field current is required to make VT equal to 2300 V when the generator is running at noload?(b) What is the internal generated voltage of this machine at rated conditions?(c) How much field current is required to make VT equal to 2300 V when the generator is running at ratedconditions?(d) How much power and torque must the generator’s prime mover be capable of supplying?
10Related ExampleAssume that the field current of the generator in above Problem has been adjusted to a value of 4.5 A.(a) What will the terminal voltage of this generator be if it is connected to a -connected load with animpedance of 20 ∠ 30 °Ω?(b) Sketch the phasor diagram of this generator.(c) What is the efficiency of the generator at these conditions?(d) Now assume that another identical ∆-connected load is to be paralleled with the first one. Whathappens to the phasor diagram for the generator?(e) What is the new terminal voltage after the load has been added?(f) What must be done to restore the terminal voltage to its original value?
11Measuring parameters of synchronous generator model
12Measuring parameters of synchronous generator model An approximate method to determine the synchronous reactance XS at a given field current:Get the internal generated voltage EA from the OCC at some value of field current.Get the short-circuit current IA,SC at that field current from the SCC.Find XS
13Measuring parameters of synchronous generator model: Ex Example : A 200 kVA, 480 V, 50 Hz, Y-connected synchronous generator with a rated field current of 5 A was tested and the following data were obtained:VT,OC = 540 V at the rated IF.IL,SC = 300 A at the rated IF.When a DC voltage of 10 V was applied to two of the terminals, a current of 25 A was measured.Find the generator’s model at the rated conditions (i.e., the armature resistance and the approximate synchronous reactance).
14Measuring parameters of synchronous generator model: Ex
15Measuring parameters of synchronous generator model The approximate value of synchronous reactance varies with the degree of saturation of the OCC.The value is more accurate in unsaturated portion only.
16The Synchronous generator operating alone The behavior of a synchronous generator varies greatly under load depending on the power factor of the load and on whether the generator is working alone or in parallel with other synchronous generators.Although most of the synchronous generators in the world operate as parts of large power systems, we start our discussion assuming that the synchronous generator works alone.Unless otherwise stated, the speed of the generator is assumed constant.
17The Synchronous generator operating alone Effects of load changes(7.34.1)
18The Synchronous generator operating alone The behavior of a synchronous generator varies greatly under load depending on the power factor of the load and on whether the generator is working alone or in parallel with other synchronous generators.Although most of the synchronous generators in the world operate as parts of large power systems, we start our discussion assuming that the synchronous generator works alone.Unless otherwise stated, the speed of the generator is assumed constant.
19The Synchronous generator operating alone Effect of increasing inductive load
20How to compensate the increase in Load Increase the field current, that increases flux and in turn EA causing the VT to remainsame.
23The Synchronous generator operating alone: Example Example : A 500 V, 60 Hz, Y-connected six-pole synchronous generator has a per-phase synchronous reactance of 1.0 . Its full-load armature current is 60 A at 0.8 PF lagging. Its friction and windage losses are 1.5 kW and core losses are 1.0 kW at 60 Hz at full load. Assume that the armature resistance can be ignored. The field current has been adjusted such that the no-load terminal voltage is 500 V.What is the speed of rotation of this generator?What is the terminal voltage of the generator ifIt is loaded with the rated current at 0.8 PF lagging;It is loaded with the rated current at 1.0 PF;It is loaded with the rated current at 0.8 PF leading.c. What is the efficiency of this generator (ignoring the unknown electrical losses) when it is operating at the rated current and 0.8 PF lagging?d. How much shaft torque must be applied by the prime mover at the full load?how large is the induced countertorque?e. What is the voltage regulation of this generator at 0.8 PF lagging? at 1.0 PF? at 0.8 PF leading?
24The Synchronous generator operating alone: Example Since the generator is Y-connected, its phase voltage isVT(no load) = 500V = EA (line, no load)Vφ = VT/(3)1/2 = = EA (phase, no load)At no load, IA = 0 and EA = V and it is constant since the field current was initially adjusted that way.a. The speed of rotation of the synchronous generator isnm = 120fe/P = 120(60)/6 =1200 rpm1200 rpm =125.7 rad/s
26Example continued 0.8 lagging PF (288.6)2 = (Vφ + (1.0)(60.0)(Sin 36.87))2 +(60( 1.0) Cos 36.87)2V φ = 248VY connected thereforeVT = (3)1/2 Vφ = 430 V
27Example continued UNITY PF E2A = (Vφ)2 +(XSIA)2(288.6)2 = (Vφ)2 +((1.0)60)2Vφ =282.VY connected thereforeVT = (3)1/2 Vφ = 488 V
28Example continued 0.8 leading PF E2A = (Vφ - XSIASin θ)2 +(XSIA Cosθ)2V φ =320 v
29Terminal characteristics of synchronous generators A typical speed vs. power plotA typical frequency vs. power plotshaft speed is linked to the electrical frequency asfe = nmP/120the power output from the generator is related to its frequency:P = SP (fnl – fsys)Slope of curve, W/HzOperating frequency of the system
30Terminal characteristics of synchronous generators A similar relationship can be derived for the reactive power Q and terminal voltage VT. When adding a lagging load to a synchronous generator, its terminal voltage decreases. When adding a leading load to a synchronous generator, its terminal voltage increases.
31Terminal characteristics of synchronous generators When a generator is operating alone supplying the load:The real and reactive powers are the amounts demanded by the load.The governor of the prime mover controls the operating frequency of the system.The field current controls the terminal voltage of the power system.