Dilutions. A dilution occurs when water is added to a concentrated solution. Because only water is being added, the moles of solute is unchanged. When.

Slides:

Advertisements

Similar presentations

Solution Concentration. Calculations of Solution Concentration Mole fraction Mole fraction – the ratio of moles of solute to total moles of solution.

Advertisements

1 Chapter 10 Acids and Bases 10.10Dilutions. 2 Dilution Diluting a solution Is the addition of water. Decreases concentration. ConcentratedDilutedSolution.

Solution Concentration. Calculations of Solution Concentration: Mass Percent Mass percent Mass percent is the ratio of mass units of solute to mass units.

Dilutions and Percent Solutions

Topic: Dilution Do Now:

Examples-Molarity and Dilutions. Example What is the molarity of a solution that contains 4.5 moles of sucrose in L of water?

Solutions Calculations. Questions 1.What mass of NaOH is needed to make 350 mL of 0.45 mol/L NaOH solution? 2.What is the molarity if 25 g of KClO 3 is.

Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions.

MOLARITY A measurement of the concentration of a solution Molarity (M) is equal to the moles of solute (n) per liter of solution M = n / V = mol / L Calculate.

CONCENTRATION OF SOLUTIONS Day 4 CONCENTRATION  A measurement of the amount of solute in a given amount of solvent or solution (unit of measurement.

Thursday, March 6, 2008 Discussion of Molarity Lab Results Introduce Section 15.2b -- Dilutions Homework: Pg. 555, #31a-d, 32, 33, 34.

Molarity by Dilution Diluting Acids How to Calculate Acids in concentrated form are diluted to the desired concentration using water. Moles of acid before.

Molar Concentration. Measuring Concentration Molarity (M): the number of moles of solute in 1 liter solution. Example: 0.5 moles of NaCl dissolved in.

Solution Concentration Section 14.2 Concentration - amount of solute dissolved in a specific amount of solvent concentrated - a lot of solute dilute.

Preparing a Molar Solution

DETERMING CONCENTRATIONS OF SOLUTIONS. MOLAR Molar is mol solube/1 L solution Making molar solution 1)Add ½ of the total solvent 2)Add required amount.

Notes 15.2 Describing Solution Composition. Mass Percent Mass percent= mass of solute X 100 mass of solution = grams of solute X 100 grams of solute +

a measure of the amount of solute that is dissolved in a given quantity of solvent unit of measurement is Molarity (M) which is moles/liter can be dilute.

Molarity Molarity (M) = # moles of solute/ # liters of solution Calculate the molarity of 557 mL of solution containing mol HCl. Molarity(M) = #

How many grams of sodium sulfate would you need to make 100. mL of a 3.5 M solution?

Percent by mass, mole fraction, molarity, and molality

CONCENTRATION OF SOLUTIONS. Solute + The amount of solution can be expressed by: - mass m (g, kg) or - volume V (cm 3, mL, dm 3, L, m 3 ) m = V x  -

Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity.

Solutions Molarity.

Making Molar Solutions From Liquids (More accurately, from stock solutions)

DILUTION CALCULATIONS Molarity of Mixture = total moles of chemical in which we are interested total volume of mixture Dilute Solution – a solution with.

Dilution Problems. 2-step Molarity Problems Study them because that’s the process we need to go through if we are making a solution from a solid solute.

Stock Solutions Different experiments require solutions of various different molarities. It would not be practical to have multiple bottles of each type.

1 Learning Check If we dissolve 40.55g of FeCl 3 in enough water to make 500. mL of the solution, what is the molarity of the solution? Convert all unit:

PSC 4012 Ionic Phenomena: A study of an environmental problem.

Moles and Solutions - Concentrations

Making Solutions and Dilutions Unit 13 – PPT 2. Molarity  M = moles solute/liters of solution  Uses the symbol M  Example:  2 moles of glucose are.

Topic 8 Acids and Alkalis.

16-2. Dilution Calculations and Molar Solubility A. MOLAR SOLUBILITY : Think of molar solubility as the molarity of a saturated solution!! Moles per Litre.

CONCENTRATION AND DILUTIONS. Concentrations of Solutions ■a dilute solution contains only a small amount of solute ■concentrated solution contains a large.

WARM UP 1. Write the equation for the neutralization reaction between sulfuric acid (H 2 SO 4 ) and ammonium hydroxide (NH 4 OH).

Dilution Adding water to a solution. Dilution The number of moles of solute doesn’t change if you add more solvent! The # moles before = the # moles after.

Molarity & Dilution By: Wes Corkum. Molarity concentration is the measure of how much solute is dissolved in a given amount of solution. The main measure.

Titrations. The process of adding measured volumes of an acid or base of known concentrations to an acid or base of unknown concentration until neutralization.

Concentration of Solutions

Solution Concentration

H.W. # 19 Study pp (sec. 15.6) Study class notes

Making Dilutions from Solutions

DILUTING A STOCK SOLN To make a soln less concentrated: add solvent

Solutions Review What is the molarity of a solution made by dissolving 0.35 mol in 145 milliliters of solution?

Solutions and Molarity

To Do… OWL: due Wednesday (2/21) and Friday (2/23).

ICE Charts With Acid Base Reactions.

Molarity & Dilution.

Molarity and Dilution Solution Chemistry.

Solution Concentration

Unit 8: Concentration and Molarity (M)

Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7.

Concentration of Solute

ICE Charts With Acid Base Reactions.

Unit 2 Lesson 3 Molarity Video Disk Unit 6 Demo Magic Sand

Solution Concentration

Unit 3, Lesson 14: Dilutions

Which one of these is more concentrated?

Diluting Solutions Lesson 6.

1. Calculate the moles of B (limiting reactant) consumed based on 10

Unit 2 Lesson 3 Molarity Video Disk Unit 6 Demo Magic Sand

Dilutions M1V1=M2V2.

Solution Concentration

Concentration = # of moles volume (L) V = 1000 mL V = 1000 mL

Unit 2 Lesson 3 Molarity Video Disk Unit 6 Demo Magic Sand

Molarity (M): State the ratio between the number of moles of solute & the volume of solution (in liters). Molarity (M) =

Presentation transcript:

Dilutions

A dilution occurs when water is added to a concentrated solution. Because only water is being added, the moles of solute is unchanged. When the water is added, the concentration (molarity) of the solution will be reduced. Molarity = moles (stays the same) litres (gets larger) Mathematically, the molarity must get smaller. The moles are diluted.

What is the new concentration if 316cm 3 of a 0.417M solution of sulfuric acid is diluted up to a total volume of 906ml? M = moles litres Before: M = moles 0.316L moles = mol After: M = mol 0.906L M = M

The ratio of molarity and volume is the same before and after, because moles stays the same. Therefore, M = moles litres Could be written: M x litres = moles

If moles stays the same: before after M x litres = M x litres But we write it MV = M’V’ (.417)(.316) = M’(.906) M = 0.145M

Calculate the molarity of 0.856M of sulfuric acid in 450.0cm 3 of water that has 100.0cm 3 of water added to it. MV=M’V’ (0.856M)(0.450L) = M(0.550L) M = 0.700M

How much water must be added to make a 0.107M solution of nitric acid if the starting solution is 84.6ml of 0.932M nitric acid? MV = M’V’ (0.107)V = (0.0847)(0.932) V = 0.737L Total volume – Original volume = Must add 0.737L – L = 0.652L