1. Making Molar Solutions From Liquids (More accurately, from stock solutions)

2. Making molar solutions from liquids Not all compounds are in a solid form Acids are purchased as liquids (“stock solutions”). Yet, we still need a way to make molar solutions of these compounds. Now we use the equation M 1 V 1 = M 2 V 2 1 is starting (concentrated conditions) 2 is ending (dilute conditions)

3. Dilution Problems Using 10x Tris/Glycine/SDS Buffer stock solution, prepare 200 mL a solution of 1x Tris/Glycine/SDS Buffer. 1.Calculate the volume of stock solution needed: 10x (V 1 ) = 1x (200ml) V 1 = 1x (200ml) 10x V 1 = 20 ml 2.Determine the amount of water to add to the solution to make the 200 mL needed 200ml - 20ml = 180ml

4. Using a 1.50 M sodium chloride stock solution, prepare 50 mL a solution of.6 M sodium chloride. 1.Calculate the volume of stock solution needed: 1.5M (V 1 ) =.6M (50ml) V 1 =.6M (50ml) 1.5 M V 1 = 20 ml 2.Determine the amount of water to add to the solution to make the 50 mL needed. 50ml – 20ml = 30ml