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Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7.

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Presentation on theme: "Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7."— Presentation transcript:

1 Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7

2 mol L mol L M = M = A. Dilutions Dilutions
lowers concentration, or molarity but… total moles of solute does not change mol L mol L M = M =

3 A. Dilutions 6 mol in 100 mL 6 mol in 200 mL same # of mol

4 A. Dilutions

5 A. Dilutions Dilutions initial Molarity Molarity of dilute solution
initial Volume Molarity of dilute solution Volume of dilute solution

6 B. Calculations V1 = (0.400 M) x (100 mL) = (2.00 M) (2.00 M) x V1 =
Finding Volume (V1) How many mL of 2.00 M MgSO4 must be diluted to prepare 100 mL of M MgSO4? V1 = (0.400 M) x (100 mL) = (2.00 M) V1 M1 V2 M2 (2.00 M) x V1 = (0.400 M) x (100 mL) bleach 20.0 mL

7 B. Calculations M2 = (10.0 M) x (200 mL) = (500 mL)
Finding Molarity (M2) 200 mL of 10.0 M NaOH is diluted to 500 mL, what is the molarity of the dilute solution? M2 = (10.0 M) x (200 mL) = (500 mL) V1 M1 V2 M2 (10.0 M) x (200 mL) = M2 x (500 mL) 4.00 M


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