Isolate an indicated variable in an equation. LITERAL EQUATIONS

Learning Goal for Focus 2 (HS.A-CED.A.1, 2 & 3, HS.A-REI.A.1, HS.A-REI.B.3): The student will create equations from multiple representations and solve linear equations and inequalities in one variable explaining the logic in each step In addition to level 3.0 and above and beyond what was taught in class, the student may: - Make connection with other concepts in math - Make connection with other content areas. The student will create equations from multiple representations and solve linear equations and inequalities in one variable explaining the logic in each step. - rearrange formulas to highlight a quantity of interest. -Graph created equations on a coordinate graph. The student will be able to solve linear equations and inequalities in one variable and explain the logic in each step. -Use equations and inequalities in one variable to solve problems. With help from the teacher, the student has partial success with solving linear equations and inequalities in one variable. Even with help, the student has no success with solving linear equations and inequalities in one variable.

Formulas There are many formulas that you have used so far in your math career. Here are a few: D = rt A = bh A = ½ h(b1 + b2) I = Prt V = LWH SA = 2LW + 2LH + 2WH Our goal is to be able to rearrange formulas to isolate a desired variable. Use the properties of algebra to do this “legitimately.” Image from

Isolate “u” in the following equations. Give a property to justify each step. 1 / 3 u – 8 = y 1 / 3 u = y + 8 u = 3(y + 8) ***That is the final answer. All you have to do is isolate the indicated variable. You will not SOLVE it.*** w = ux w – 9 = 14ux (w – 9) = u 14x This is the final answer. Addition Property (add 8) Multiplication Property (3) Subtraction Property (- 9) Division Property (÷ 14x) Image from

Isolate “w” in the following equations. Give a property to justify each step. y = 2x + w v vy = 2x + w vy – 2x = w w + x = y 3 w = y – x 3 w = 3(y – x) Multiplication Property (v) Subtraction Property (-2x) Subtraction Property (-x) Multiplication Property (3) Image from

Isolate “m” in the following equation. Give a property to justify each step. k = am + 3mx k = m(a + 3x) k = m a + 3x The “m” is in both terms. It is a factor of both terms. You will need to “factor it out of them.” This is the distributive property backwards. Distributive Property Division Property (÷ [a + 3x]) Image from