S. Reda EN160 SP’07 Design and Implementation of VLSI Systems (EN0160) Lecture 17: Static Combinational Circuit Design (1/2) Prof. Sherief Reda Division.

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S. Reda EN160 SP’07 Design and Implementation of VLSI Systems (EN0160) Lecture 17: Static Combinational Circuit Design (1/2) Prof. Sherief Reda Division of Engineering, Brown University Spring 2007 [sources: Weste/Addison Wesley – Rabaey/Pearson]

S. Reda EN160 SP’07 How to convert an AND/OR to a NAND/NOR network? Sketch a 2 by 1 multiplexer design using AND, OR, and NOT gates.

S. Reda EN160 SP’07 Converting AND/OR networks to NAND/NOR networks Start with network of AND / OR gates Convert to NAND / NOR + inverters Push bubbles around to simplify logic –Remember DeMorgan’s Law

S. Reda EN160 SP’07 Compound gates Logical Effort of compound gates

S. Reda EN160 SP’07 Delay calculation example The multiplexer has a maximum input capacitance of 16 units on each input. It must drive a load of 160 units. Estimate the delay of the NAND and compound gate designs. H = 160 / 16 = 10 B = 1 N = 2

S. Reda EN160 SP’07 Solution: simple versus compound for the MUX case

S. Reda EN160 SP’07 Annotating design with transistor sizes Annotate your designs with transistor sizes that achieve this delay.

S. Reda EN160 SP’07 Parasitic modeling Our parasitic delay model was too simple –Calculate parasitic delay for Y falling If A arrives latest? 2  If B arrives latest? 2.33   If input arrival time is known –Connect latest input to inner terminal

S. Reda EN160 SP’07 Asymmetric gates Asymmetric gates favor one input over another Ex: suppose input A of a NAND gate is most critical –Use smaller transistor on A (less capacitance) –Boost size of noncritical input –So total resistance is same g A = g B = g total = g A + g B = Asymmetric gate approaches g = 1 on critical input But total logical effort goes up Asymmetric gates favor one input over another Ex: suppose input A of a NAND gate is most critical –Use smaller transistor on A (less capacitance) –Boost size of noncritical input –So total resistance is same g A = 10/9 g B = 2 g total = g A + g B = 28/9 Asymmetric gate approaches g = 1 on critical input But total logical effort goes up

S. Reda EN160 SP’07 Symmetric gates Inputs can be made perfectly symmetric

S. Reda EN160 SP’07 Skewed gates Skewed gates favor one edge over another Ex: suppose rising output of inverter is most critical –Downsize noncritical nMOS transistor Calculate logical effort by comparing to unskewed inverter with same effective resistance on that edge. –g u = 2.5 / 3 = 5/6 –g d = 2.5 / 1.5 = 5/3

S. Reda EN160 SP’07 Hi- and Lo-Skew Def: Logical effort of a skewed gate for a particular transition is the ratio of the input capacitance of that gate to the input capacitance of an unskewed inverter delivering the same output current for the same transition. Skewed gates reduce size of noncritical transistors –HI-skew gates favor rising output (small nMOS) –LO-skew gates favor falling output (small pMOS) Logical effort is smaller for favored direction But larger for the other direction

S. Reda EN160 SP’07 Catalog of skewed gates