STATISTIKA DESKRIPTIF LATIHAN SOAL NOTASI SIGMA DAN DASAR-DASAR STATISTIKA DESKRIPTIF NAMA = Caroline Marenta Simanjuntak NIM = 11140237 KELAS =11.2A.04

Diketahui : X1 = 3 X2 = 4 X3 = 6

  = = 3 + 4 + 6 = 13 1. X1 + X2 + X3   2. = 4 = 4 (4 + 6) = 4 (10) = 40 (X2 + X3 )

3 = n.k = 3 x 8 = 24 4 = (X1 + 3) + (X2 + 3) = (3 + 3) + (4 + 3)   = n.k = 3 x 8 = 24 3 4   = (X1 + 3) + (X2 + 3) = (3 + 3) + (4 + 3) = 6 + 7 = 13

5.   = (X1 - 2)2 + (X2 - 2)2 + (X3 - 2)2 = (3 - 2)2 + (4 - 2)2 + (6 - 2)2 = (1)2 + (2)2 + (4)2 = 1 + 4 + 16 = 21 6.   = (X12 – 2) + (X22 – 2) + (X32-2) = (32 – 2) + (42 – 2) + (62-2) = (9 – 2) + (16 – 2) + (36 – 2) = 7 + 14 + 34 = 55

7.   = (X1 + X2 + X3)2 - 2 = (3 + 4 + 6)2 - 2 = (13)2 - 2 = 169 – 2 = 167 8.   = n.k = 3.7 = 21

9. = 5 = 5 (3 + 4 + 6) = 5 (13) = 65 10. = X1+X2+X3 + 2(X1+X2+X3)   9. = 5 = 5 (3 + 4 + 6) = 5 (13) = 65 (X1 + X2 + X3) 10.   = X1+X2+X3 + 2(X1+X2+X3) = 3 + 4 + 6 + 2(3 +4 +6) = 13 + 2(13) = 13 + 26 = 39

Diketahui : Y1 = 4 Y2 = 1 X3 = 5

1. Y1 + Y2 + Y3 = = 4 + 1 + 5 = 10 2. = 4 (Y2 + Y3) = 4 (1 + 5)   = = 4 + 1 + 5 = 10 1. Y1 + Y2 + Y3   2. = 4 = 4 (1 + 5) = 4 (6) = 24 (Y2 + Y3)

3. = n.k = 3 x 8 = 24 4. = (Y1 + 3) + (Y2 + 3) = (4 + 3) + (1 + 3)   = n.k = 3 x 8 = 24 3. 4.   = (Y1 + 3) + (Y2 + 3) = (4 + 3) + (1 + 3) = 7 + 4 = 11

6. = (Y12 – 2) + (Y22 – 2) + (Y32-2) = (42 – 2) + (12 – 2) + (52-2) 5.   = (Y1 - 2)2 + (Y2 - 2)2 + (Y3 - 2)2 = (4 - 2)2 + (1 - 2)2 + (5 - 2)2 = (2)2 + (-1)2 + (3)2 = 4 + 1 + 9 = 14 6.   = (Y12 – 2) + (Y22 – 2) + (Y32-2) = (42 – 2) + (12 – 2) + (52-2) = (16 – 2) + (1– 2) + (25 – 2) = 14 + (-1) + 23 = 36

7. = (Y1 + Y2 + Y3)2 - 2 = (4 + 1 + 5)2 - 2 = (10)2 - 2 = 100 – 2 = 98   = (Y1 + Y2 + Y3)2 - 2 = (4 + 1 + 5)2 - 2 = (10)2 - 2 = 100 – 2 = 98 8.   = n.k = 3.7 = 21

  9. = 5 ( = 5 (4 + 1 + 5) = 5 (10) = 50 Y1 + Y2 + Y3) 10.   = (Y1 + Y2 + Y3) + 2 (Y1 + Y2 + Y3) = (4 + 1 + 5) + 2(4 + 1 + 5) = 10 + 2(10) = 10 + 20 = 30

TERIMA KASIH