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By: Mohsin Tahir (GL) Waqas Akram Rao Arslan Ali Asghar Numan-ul-haq

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Presentation on theme: "By: Mohsin Tahir (GL) Waqas Akram Rao Arslan Ali Asghar Numan-ul-haq"— Presentation transcript:

1 By: Mohsin Tahir (GL) Waqas Akram Rao Arslan Ali Asghar Numan-ul-haq
VOLUME OF A SURFACE By: Mohsin Tahir (GL) Waqas Akram Rao Arslan Ali Asghar Numan-ul-haq

2 Surface The surface is the outside of anything.
The earth, a basketball, and even your body have a surface. Surface

3 Volume Volume is the measure of the amount of space inside of a solid figure, like a cube, ball, cylinder or pyramid.

4 The Volume Of A Cylinder.

5 The formula for the volume of a cylinder is:
V =  r 2 h r = radius h = height. Calculate the area of the circle: A =  r 2 A = 3.14 x 2 x 2 A = cm2 Calculate the volume: V =  r 2 x h V = x 6 V = cm3

6 Sphere

7 Volume of a Cube

8 Volume of a cube = a × a × a = a³
where a is the length of each side of the cube. Example:- We want to find the volume of this cube in m3 According to formula: v= 2m x 2m x 2m v=8m The volume of the cube is 8 m³ (8 cubic meters)

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11  Volume Under a Surface  A double integral allows you to measure the volume under a surface as bounded by a rectangle. Definite integrals provide a reliable way to measure the signed area between a function and the x-axis as bounded by any two values of x. Similarly, a double integral allows you to measure the signed volume between a function z = f(x, y) and the xy-plane as bounded by any two values of x and any two values of y.

12 Double Integrals over Rectangles
double integrals by considering the simplest type of planar region, a rectangle. We consider a function ƒ(x, y) defined on a rectangular region R, R : a ≤ x ≤ b, c ≤ y ≤ d If the volume V of the solid that lies above the rectangle R and below the surface z = f(x, y) is:

13 Double Integrals as Volumes
dA= dy dx dA= dx dy

14 Fubini’s Theorem for Calculating Double Integrals
Suppose that we wish to calculate the volume under the plane Z = 4 - x - y over the rectangular region R: 0 ≤ x ≤ 2 , 0 ≤ y ≤ 1 in the xy-plane. then the volume is:

15 1 where A(x) is the cross-sectional area at x. For each value of x, we may calculate A(x) as the integral 2 which is the area under the curve Z = 4 - x - y in the plane of the cross-section at x. In calculating A(x), x is held fixed and the integration takes place with respect to y. Combining Equations (1) and (2), we see that the volume of the entire solid is:

16 If we just wanted to write a formula for the volume, without carrying out any of the integrations, we could write

17 Fubini’s Theorem If ƒ(x, y) is continuous throughout the rectangular region then: R : a ≤ x ≤ b, c ≤ y ≤ d

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19 Examples to Finding the volume using Double integral

20 Q#1 Solution:

21 Q#2 Solution:

22 Q#3 Calculate the volume under the surface z=3 + X2 − 2y over the region D defined by 0 ≤ x ≤ 1 and −x ≤ y ≤ x. Solution: The volume V is the double integral of z=3 + X2 − 2y over D.

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