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Published byEthan Henson Modified about 1 year ago

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Internal 3 Credits DO NOW: Convert the following: 1) cm 3 to mm 3 2) 728,955 mm 3 to cm 3 3) Write up the method you use for doing this.

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Area of rectangle = base x height (Unit are always to the power of 2 e.g. cm 2 ) Triangle = ½ base x height Trapezium = (a+b)/2 x h Circle = r 2

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The volume of an object is a measure of how much space it occupies. Volume of an object = area at the end x length Block of cheese = 4cm x 6cm x 20cm = 480cm 3 cm 1 x cm 1 x cm 1 = cm 3

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Calculate volume of cylinder. Volume = ? Volume = r 2 * h Calculate to 4 s.f. r = 1.9m h = 4.7m

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Do exercise page 162. 1 a, b 2 b 4 a 5 a, b, d, e 6 a, b 7 a, b 8 c 11

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l+w+h = 140 cm Volume = cross-sectional area x height. How to solve this problem?

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Not expected to remember the formulae but need to know how to use it. Pyramids and Cones: Volume = (area of base x height) Spheres: Volume = r 3

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Square based pyramid Triangular based pyramid pyramid Cone Find the volume of the pyramid with a square base of side 3cm and a height of 5 cm. Volume = (area of base x height) base = 3 x 3 = 9 cm 2 Volume = x 9 x 5 = 15 cm 3 Note that the height of the pyramid or cone is always the vertical height measured inside the shape and not the slant height, which is the distance from the top to the base on the outside of the shape.

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Go to page 165: Do exercise 1 and 5

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Volume = area of circular base x h = ? = r 2 h r = 3.2, h = 7.8 Volume = (3.2) 2 x 7.8 = cm 2

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Page 165: Do exercise 2 and 4

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Sphere is the same as a round ball, it only has one measurement, the radius (what is the plural of radius?). Volume = r 3 d = 230 mm Volume = ? = x x (115) 3 = mm 3 In cm 3 ?

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Read top of page 166. Do exercises 8, 9, 10 and 11 on page 166 & 167. How to deal with these sorts of problems?

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