 # MOLARITY – Ch 13, p. 412 Quantifies the concentration of a solution.

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MOLARITY – Ch 13, p. 412 Quantifies the concentration of a solution.
Molarity (M) = mol solute = n = mol volume solution V L Read as “moles solute per liter of solution” Variables Units

MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as
“0.2 molar sodium chloride solution.”

MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as
“0.2 molar sodium chloride solution.” This means 1 L of the solution contains 0.2 moles NaCl.

MOLARITY – Ch 13 Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given:

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown:

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M

Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M Need:

MOLARITY – Ch 13 Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M Need: molar mass NaCl

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl g/mol M = n = g V

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V g

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V g

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V L g

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol M V L g

MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol M V L g

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH.

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given:

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need:

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n V

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n  V

MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n  n = M•V V

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M
Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 M

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M
Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 mol L

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 mol L

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 mol L L

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 mol L L

MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M Unknown: n, mol NaOH Need: M = n  n = M•V V 0.250 mol L mol L

MOLARITY – Ch 13 Example 4: Calculate the volume of 0.50 M HCl that would contain 2.0 mol HCl. YOU TRY IT!

MOLARITY – Ch 13 Example 4: Given: n = 2.0 mol HCl molarity = 0.50 M
Unknown: V Need: M = n  V = n V M 2.0 mol L L 0.50 mol

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? YOU TRY IT!

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 M

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown:

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown: V2 =

MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2  C1V1 = V2 C2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown: V2 =

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