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**MOLARITY – Ch 13, p. 412 Quantifies the concentration of a solution.**

Molarity (M) = mol solute = n = mol volume solution V L Read as “moles solute per liter of solution” Variables Units

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**MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as**

“0.2 molar sodium chloride solution.”

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**MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as**

“0.2 molar sodium chloride solution.” This means 1 L of the solution contains 0.2 moles NaCl.

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MOLARITY – Ch 13 Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given:

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown:

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M

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Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M Need:

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MOLARITY – Ch 13 Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution. Given: mass = g V = mL Unknown: M Need: molar mass NaCl

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl g/mol M = n = g V

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V g

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V g

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol V L g

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol M V L g

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**MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g**

V = mL = L Unknown: M Need: molar mass NaCl M = n = g mol M V L g

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH.

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given:

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need:

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n V

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n V

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MOLARITY – Ch 13 Example 3: Calculate the moles of NaOH present in mL of M NaOH. Given: V = mL molarity = M Unknown: n, mol NaOH Need: M = n n = M•V V

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M**

Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 M

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M**

Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 mol L

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L**

molarity = M Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 mol L

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L**

molarity = M Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 mol L L

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L**

molarity = M Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 mol L L

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**MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L**

molarity = M Unknown: n, mol NaOH Need: M = n n = M•V V 0.250 mol L mol L

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MOLARITY – Ch 13 Example 4: Calculate the volume of 0.50 M HCl that would contain 2.0 mol HCl. YOU TRY IT!

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**MOLARITY – Ch 13 Example 4: Given: n = 2.0 mol HCl molarity = 0.50 M**

Unknown: V Need: M = n V = n V M 2.0 mol L L 0.50 mol

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? YOU TRY IT!

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 M

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown:

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown: V2 =

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MOLARITY – Ch 13 Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated 12 M HCl? Use C1V1 = C2V2 C1V1 = V2 C2 Given: C1 = 0.50 M V1 = 100mL C2 = 12 Unknown: V2 =

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Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemistry Properties of Solutions.

Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemistry Properties of Solutions.

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