Presentation is loading. Please wait.

Presentation is loading. Please wait.

II. Solution Concentration (p. 480 – 488)

Similar presentations


Presentation on theme: "II. Solution Concentration (p. 480 – 488)"— Presentation transcript:

1 II. Solution Concentration (p. 480 – 488)
Ch. 14 – Mixtures & Solutions II. Solution Concentration (p. 480 – 488)

2 A. Concentration The amount of solute in a solution
Describing Concentration % by mass - medicated creams % by volume - rubbing alcohol ppm, ppb - water contaminants molarity - used by chemists molality - used by chemists

3 SAWS Water Quality Report - June 2000
A. Concentration SAWS Water Quality Report - June 2000

4 substance being dissolved
A. Molarity Concentration of a solution substance being dissolved total combined volume

5 A. Molarity 2M HCl What does this mean?

6 B. Molarity Calculations
LITERS OF GAS AT STP Molar Volume (22.4 L/mol) MASS IN GRAMS MOLES NUMBER OF PARTICLES Molar Mass (g/mol) 6.02  1023 particles/mol Molarity (mol/L) LITERS OF SOLUTION

7 B. Molarity Calculations
How many grams of NaCl are required to make 0.500L of 0.25M NaCl? 0.500 L sol’n 58.44 g NaCl 1 mol NaCl 0.25 mol NaCl 1 L sol’n = 7.3 g NaCl

8 B. Molarity Calculations
Find the molarity of a 250 mL solution containing 10.0 g of NaF. 10.0 g NaF 1 mol NaF 41.99 g NaF = 0.95 M NaF .25 L sol’n

9 C. Dilution Preparation of a desired solution by adding water to a concentrate. Moles of solute remain the same.

10 C. Dilution What volume of 15.8M HNO3 is required to make 250 mL of a 6.0M solution? GIVEN: M1 = 15.8M V1 = ? M2 = 6.0M V2 = 250 mL WORK: M1 V1 = M2 V2 (15.8M) V1 = (6.0M)(250mL) V1 = 95 mL of 15.8M HNO3

11 D. Molality mass of solvent only 1 kg water = 1 L water

12 D. Molality Find the molality of a solution containing 75 g of MgCl2 in 250 mL of water. 75 g MgCl2 1 mol MgCl2 95.21 g MgCl2 0.25 kg water = 3.2m MgCl2

13 D. Molality How many grams of NaCl are req’d to make a 1.54m solution using kg of water? 0.500 kg water 1.54 mol NaCl 1 kg water 58.44 g NaCl 1 mol NaCl = 45.0 g NaCl

14 E. Preparing Solutions 1.54m NaCl in 0.500 kg of water
500 mL of 1.54M NaCl mass 45.0 g of NaCl add water until total volume is 500 mL mass 45.0 g of NaCl add kg of water 500 mL water 45.0 g NaCl 500 mL mark volumetric flask

15 E. Preparing Solutions Copyright © NT Curriculum Project, UW-Madison (above: “Filling the volumetric flask”)

16 E. Preparing Solutions Copyright © NT Curriculum Project, UW-Madison (above: “Using your hand as a stopper”)

17 E. Preparing Solutions 250 mL of 6.0M HNO3 by dilution
measure 95 mL of 15.8M HNO3 95 mL of 15.8M HNO3 combine with water until total volume is 250 mL 250 mL mark Safety: “Do as you oughtta, add the acid to the watta!” or AA – add acid! water for safety

18 Solution Preparation Mini-Lab
Turn in one paper per team. Complete the following steps: A) Show the necessary calculations. B) Write out directions for preparing the solution. C) Prepare the solution. For each of the following solutions: 1) mL of 0.50M NaCl 2) 0.25m NaCl in mL of water 3) mL of 3.0M HCl from 12.0M concentrate. (don’t actually prepare this one!)


Download ppt "II. Solution Concentration (p. 480 – 488)"

Similar presentations


Ads by Google