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Lab 2 Carbohydrates.

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Presentation on theme: "Lab 2 Carbohydrates."— Presentation transcript:

1 Lab 2 Carbohydrates

2 Carbohydrates are macromolecules, consists of Carbon, Hydrogen and Oxygen. H and O are found in same proportion as in water (H2O).

3 How carbohydrates can be form?
in the plant cells and tissues from their natural sources (CO2 and H2O) Photosynthesis CHLOROPLASTS + LIGHT carbohydrates 6H2O+6CO C6H12O6 +6O2

4 Biological Significance of Carbohydrates:
1- Carbohydrates are the major source of Energy. 2- Component of cellular membranes and organelles membranes). -cellulose of plant cell wall -cuticle of insects outer bodies 3- Stores in form of glycogen and starch

5 Carbohydrates in living organisms can be divided into 3 types:
Monosaccharides: The simplest form of carbohydrates. Molecular formula is (CH2O)n, where n is number of C atoms and =3,4,5,6 or 7. Monosaccharides exists in form of unbranched chain, or in cyclic form (ring).

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7 Monosaccharides are classified by the number of carbon atoms:
Triose =3 carbon atoms tetrose =4 carbon atoms pentose =5 carbon atoms Hexose =6 carbon atoms Heptose =7 carbon atoms The cyclic (ring) form can be either a pentose or hexose only. Glyceraldehyde (Triose) Ribose and deoxyribose (pentose) Glucose and fructose (hexoses(

8 Disaccharides: Maltose:
Formed by binding of 2 units of monosaccharides by glycosidic bond (-O-) . Molecular formula is C12H22O11. 2C6H12O H2O C21H22O11 Maltose: 2 units of glucose Sucrose: Glucose + fructose Lactose: Galactose + glucose

9 Polysaccharides can be divided chemically to:
Large molecules composed of repeating units of monosaccharides. Molecular formula is (C6H10O5)n, where n = number of monosaccharides units. Polysaccharides can be divided chemically to: 1- Homopolysaccharides: consists of one type of monosaccharides. 2- Heteropolysaccharides: consists of different types of monosaccharides, e.g. Hemicellulose- Hyaluronic acid.

10 2- Nutritional Polysaccharides 1- Structural Polysaccharides
Polysaccharides can be divided according to function to: 2- Nutritional Polysaccharides 1- Structural Polysaccharides Glycogen (animal starch) units of glucose linked by α- glycosidic bond. Branched. Cellulose units of glucose linked by β- glycosidic bond, unbranced and linear. Starch units of glucose linked by α- glycosidic bond. Unbranched and spiral (helical) called Amylose. Or banched called Amylopectine. Chitin units of acetyl-glucose amine. Forms the outer skeleton of insects and crustaceans.

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15 Nutritional Polysaccharides Glycogen in liver

16 Mucus in mucus gland

17 Mucus in intestine

18 Starch granules in potatoes

19 Detection of Carbohydrates
Detection of Monosaccharides: Detection of Glucose and Fructose 1- In test tube, put 5 ml of sucrose solution (1%) , add 5 drops of HCl 2- Heat mixture of sucrose preparation in boiling water for 5 minutes. 3- Add 1 ml of NaOH solution 4- To detect Glucose (Fehling reaction): In test tube mix 1 ml of Fehling A + 1 ml Fehling B, then add 5 drops of sucrose preparation and heat over flame for 5 minutes. 5- To detect fructose (Silvanof reaction) : In test tube put 5 drops of sucrose preparation + 2 ml of silvanof reagent Observation: Sucrose solution with Fehling’s: ………………………… Sucrose solution with Silvanof: …………………………..

20 Effect of Invertase enzyme on Sucrose Digestion and Hydolysis:
1- Prepare invertase enzyme extract by grinding 10 gm of yeast with 5 ml distilled water and table sugar. 2- In test tube, put 2 ml of sucrose solution (2%) + 2 ml of Fehling reagent (1ml of Fehling A and 1 ml of B), heat in boiling water bath for 6 min. 3- In new test tube, put 2 ml of sucrose solution + 2 ml of invertase extract and mix well. Then put in 37˚C for 15 min. Add 2 ml of Fehling reagent (A & B) , heat in boiling water bath for 10 min.


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