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Bell Ringer 2. 2.5x – 1.8 = 8.2 + 1.8 + 1.8 2.5x = 10 2.5 2.5 x = 4 2525  Solve. 1. x + 3 = 7 - 3 - 3 x = 4 x = 10 2525 5252 5252..

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Presentation on theme: "Bell Ringer 2. 2.5x – 1.8 = 8.2 + 1.8 + 1.8 2.5x = 10 2.5 2.5 x = 4 2525  Solve. 1. x + 3 = 7 - 3 - 3 x = 4 x = 10 2525 5252 5252.."— Presentation transcript:

1 Bell Ringer 2. 2.5x – 1.8 = 8.2 + 1.8 + 1.8 2.5x = 10 2.5 2.5 x = 4 2525  Solve. 1. x + 3 = 7 - 3 - 3 x = 4 x = 10 2525 5252 5252..

2 Geometry: Perimeter and Area of Polygons

3 Geometry Standards  MEA 201: Estimate or calculate the length of a line segment based on other lengths given on a geometric figure  MEA 301: Compute the perimeter of polygons when all side lengths are given  MEA 302: Compute the area of rectangles when whole number dimensions are given  MEA 401: Compute the area and perimeter of triangles and rectangles in simple problems  MEA 501: Compute the area of triangles and rectangles when one or more additional simple steps are required  MEA 503: Compute the perimeter of simple composite geometric figures with unknown side lengths*

4 Honors: Additional Standards  PPF 502: Recognize Pythagorean triples*  PPF 601: Apply properties of 30°-60°-90°, 45°-45°-90°, similar, and congruent triangles  PPF 602: Use the Pythagorean theorem

5 Key Vocabulary  Perimeter – The distance around an polygon.  Area – The amount of space inside a two dimensional shape.

6 MEA 201  Estimate or calculate the length of a line segment based on other lengths given on a geometric figure. x 17 in 8 in 8 + x = 17 - 8 - 8 x = 9 in Easy!

7 MEA 301:  Compute the perimeter of polygons when all side lengths are given 8 in 7 in 8 in Add all the sides: 8 + 7 + 7 + 8 + 7 + 7 = 44 in

8 MEA 302:  Compute the area of rectangles when whole number dimensions are given. 25 in 6 in Area of Rectangle = Length Width A = L W A = 25 6 A = 150 in

9 MEA 401:  Compute the area and perimeter of triangles and rectangles in simple problems. Area of Triangles = 1/2 Base Height Base Height

10 MEA 401:  Tom mows lawns for $1.20 per square feet. How much did he charge to cut the lawn below? 23 ft 11 ft A = L W A = 23 11 A = 253 ft 2 Price = 253$1.20 Price = $303.60

11 MEA 401:  Tom also paints. He charges $1.50 per square feet. How much did he charge for the triangular wall below? 9 ft A = ½ B H A = ½ 9 12 A = 54 ft 2 Price = 54 $1.50 Price = $81 12 ft


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