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Vehicle Motion Human Factors
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Homework Chapter 2: #3, 6, 7
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Human Factors Rational Design of goods and services for people
Primary human requirements increased speed increased range increased capacity Secondary safety, comfort & convenience, status
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Environment Where workspace is located
effects person’s performance lighting, noise, vibration, climate, pollutants Man - Machine - Environment interaction want to optimize
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Human Variation Design is based on 90% of people
Top and bottom 5% not in design who’s not included? Adaptation & Instruction want to limit instructions How is a car laid out? Where are the important components Commonality
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Human Contact Physical, Physiological, Biochemical
Size Reach Strength Body Composition Perception - Reaction P-R, Info Processing, Motor Performance Cognitive and Social
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Pedestrians Important piece of urban design Crosswalk placement
Social distance Personal distance Intimate distance
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Pedestrians How does personal space change ? Transit airplanes
waiting areas cars
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How big is a pedestrian?
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Visual Acuity Contrast, brightness, illumination, relative motion
Acuity decreases with increased visual angle
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Perception Reaction Time
Time from stimulus to response Depends on complexity of info P-R seconds depending on event type Wake Up
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Fig 2.2 pg 22 P-R times Expectancy
Continuity – experiences of the immediate past are expected to continue Event – Events that have not happened previously will not happen Temporal – for cyclic events the longer a given state is observed the more likely it will change
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Distance covered during P-R time Pedestrians
1.47Vt Pedestrians ~ 3.5fps, elderly pop ~3.0 fps just changed Table 2.3 DWI - Figure 2.3
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Lateral Displacement Driver moves away from objects on the side of the road Want to maintain a comfort zone between car and objects
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Lateral Displacement Closer objects is to pavement edge the more lateral displacement 3.3 ft for 8 ft lane 1.8 ft for 12 ft lane Can estimate lateral displacement need l, v, dQ/dt
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Lateral Displacement Critical rate of change in visual angle
if dQ/dt is less than critical assume collision l = a cotQ dl/dt = -acsc^2QdQ/dt dQ/dt = va/(a^2+l^2)
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Lateral Displacement A vehicle traveling 40 mph was observed to displace laterally when it was 300 feet from a bridge abutment placed 6 feet to the right of the path. At what longitudinal distance from the same abutment would you expect the same driver to displace laterally when traveling 60 mph?
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Lateral Displacement What is critical rate of change (dQ/dt)
dQ/dt = {(40*1.47)*6}/(6^ ^2) = rad/sec For 60mph = {(60*1.47)*6}/(6^2 + L^2) L = 368 feet
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Forces Acting on a Vehicle
Propulsive (M) Resistance (R) Centrifugal (C) Weight (T) ma Supporting Forces (S)
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Resistance Inherent Grade Curvature
vehicle is moving through something R is a function of T and V Grade adds resistance or increases speed Curvature from centrifugal force can be eliminated w/ banked curves
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Grade
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Curvature
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Vehicle Motion Superelevation e is the amount of banking in ft/ft on a curve e + f = v2/gr depends on speed Table 2.4 – Values for f to negate f (no hands) e = v2/gr v in fps e= v2 /15R v in mph
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Vehicle Motion v=dx/dt a = dv/dt a=(dv/dx)v vdv = adx v =at + v0
x = v0t +1/2(at2)
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Braking Distance Db= (v2-v02)/2g(f+G)
f = 11.2fps^2/32.2 = used for design Not Brake type dependent – why? NOT Weight dependent - why? Does not account for reaction time
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Safe Stopping Distance
Time to perceive and respond + time to brake to a stop P-R time =2.5s want to be conservative SSD = 1.47V(2.5) + (v2-v02)/2g(f+G)
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Decision Sight Distance
Time to perceive and respond + time to brake to a stop P-R time =2.5s want to be conservative SSD = 1.47V(decision time) + (v2-v02)/2g(f+G)
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Example How long does it take a vehicle to brake to a stop from 60 mph
On a 5% downgrade On a 5% up grade On ice on a 5% upgrade
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Dilemma Zones Area around intersection - can’t stop can’t go –occurs when Yellow time is too short Need proper Y P-R time
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Dilemma Zones a2 is comfortable deceleration rate
4- 5 fps standing 8 -10 fps seated xo > xc no problem xo <= xc dilemma Cannot cross intersection in Y+AR
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Dilemma Zones Can find minimum amber needed to eliminate dilemma zone
Amber should be not more than 5 seconds Amber time = D/1.47V Assume 1s P-R time for signal
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Dilemma Zones How long should the amber interval be for the following:
Design Speed = 35mph Intersection = 30 feet wide Vehicle length = 15 feet P-R time = 1 s Stopping distance = 1.47*35*1 + (35^2-0^2)/[30(0.0348)] = 169 feet Amber = 169/(1.47*35) = 3.28s
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Dilemma Zones How long should the amber interval be for the following:
Design Speed = 35mph Intersection = 30 feet wide Vehicle length = 15 feet P-R time = 1 s Distance thru intersection= = 213 ft Amber = 213/(1.47*35) = 4.13s can use 3.28s Y + 1s AR
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