1. Before the Bell Rings Grab 1 Paper from the side table
Have your Conductivity Lab Sheet out to check.

2. ETD
Rank the conductivity of the following in solution, Draw + Explain your predictions.
Lithium Chloride
C6H12O6
Strontium Chloride

3. ETD 48 ANS
B. Rank the conductivity of the following in solution, Draw + Explain your predictions?
Lithium Chloride
C6H12O6
Strontium Chloride

4. ETD 48 ANS
B. Rank the conductivity of the following in solution, Draw + Explain your predictions?
Lithium Chloride
C6H12O6
Strontium Chloride

5. Learning Targets
I can explain qualitatively the different points on a solubility curve.
I can calculate the mass percentage of a solution.
I can calculate the molarity of a solution.

6. Notebook check next class
Numbers 31-45
All slides should be posted to my Google Classroom or Swift Site
3 points for each ETD- Total out of 45 in front, total out of 3 on each
1 for having the ETD number
1 for having the question
1 for having the answer

7. Notes on new things

8. Solubility Curves What does the word soluble mean?
What does this graph tell you about each of the chemicals?

9. Mass Percent By mass, the percent of the solution that is solute
= Mass of solute______ x 100
Total mass of solution
How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl?

10. Mass Percent By mass, the percent of the solution that is solute
= Mass of solute______ x 100
Total mass of solution
How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl?

11. Mass Percent By mass, the percent of the solution that is solute
= Mass of solute______ x 100
Total mass of solution
How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl?
20.5 % NaCl = (10.2g NaCl)(100)
(x)
(20.5)(x) = (10.2g NaCl)(100)
x = g of Solution
x = 49.8 g of Solution

12. Chemical representation of concentration M = moles of solute = mol
Molarity
Chemical representation of concentration
M = moles of solute = mol
liters of solution L

13. Try this Molarity Problem
1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make mL of solution. 
11.5 g of NaOH is the same as moles of NaOH mL equals 1.5 L. Therefore the molarity is moles/1.5 L = 0.19M
450 mL = L The problem is set up as x/0.450 L = M. X equals moles of NH4Cl moles of NH4Cl = 6.05 g of NH4Cl

14. 1. Ans Try these Molarity Problems
1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make mL of solution. 
11.5 g of NaOH is the same as moles of NaOH mL equals 1.5 L. Therefore the molarity is moles/1.5 L = 0.19M
450 mL = L The problem is set up as x/0.450 L = M. X equals moles of NH4Cl moles of NH4Cl = 6.05 g of NH4Cl

15. 1. Ans Try these Molarity Problems
1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make mL of solution. 
11.5 g of NaOH is the same as moles of NaOH mL equals 1.5 L. Therefore the molarity is moles/1.5 L = 0.19M
450 mL = L The problem is set up as x/0.450 L = M. X equals moles of NH4Cl moles of NH4Cl = 6.05 g of NH4Cl

16. Learning Targets
I can explain qualitatively the different points on a solubility curve.
I can calculate the mass percentage of a solution.
I can calculate the molarity of a solution.

17. Homework
Molarity #1 WS
Due next class
Notebook check 31-45