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1 Molarity

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2 Review of Converstions Fractions that = 1 Different units and numbers that equal each other Example: 1 in. = 2.54 cm Factors: 1 in. OR 2.54 cm 2.54 cm 1 in

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3 How many Liters are in 8,392 milliliters? Conversion factor 8,392 ml X 1 L = 8.392 L 1,000 ml 1,000 ml

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4 What is the number of moles in 20.0 grams of NaOH? Use a conversion factor. Converting Grams To Moles

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5 Molar mass of NaOH Na = 23.0 + 1 O =16.0 + 1 H = 1.0 total = 40.0 grams in 1 mole 2. Conversion factor 40.0 g 1 mole 3. Setup 20.0 g x 1 mole = 20.0 = 0.50 moles 40.0 g 40.0 Converting Grams To Moles

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6 What is the number of moles in 185 grams of CCl 4 ? Use a conversion factor. Converting Grams To Moles

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7 Molar mass of CCl 4 C = 12.0 + 4 Cl =142.0 total = 154.0 grams in 1 mole 2. Conversion factor 154.0 g 1 mole 3. Setup 185 g x 1 mole = 185 = 1.2 moles 154.0 g 154.0 Converting Grams To Moles

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8 Concentration of Solutions Mass Percentage = Mass of Solute Total Mass of Solution. (Water + Solute) Molarity (M) = Moles of Solute Liters of Solution 1000 ml = 1 Liter

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9 Steps to Finding Molarity 1. First convert grams of solute into moles. 2. Convert volume to Liters of solution. 3. Divide Moles of Solute by Liters of Solution.

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10 What is the Molarity of 20.0 grams of Ca(OH) 2 dissolved into 250 ml of solution? Use a conversion factor to find moles. Practice

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11 Molar mass of Ca(OH) 2 Ca = 40.1 +2 O =32.0 + 2 H = 2.0 total = 74.0 grams in 1 mole 2. Setup 20.0 g x 1 mole = 20.0 = 0.27 moles 74.0 g 74.0 3. Volume = 250 ml x 1 Liter = 0.25 L 1,000 ml 4. Molarity = 0.27 moles = 1.08 or 1.1 0.25 L Molarity of 20.0 g Ca(OH) 2 in 250 ml solution

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12 What is the molarity of 185 grams of CrCl 4 dissolved into 500 ml of solution? Use a conversion factor. Calculate the Molarity

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13 Molar mass of CCl 4 Cr = 52.0 + 4 Cl =142.0 total = 194.0 grams in 1 mole 2. Setup 185 g x 1 mole = 185 = 0.95 moles 194.0 g 194.0 3. Volume 500 ml x 1 Liter = 0.5 Liter 1,000 ml 4. Molarity = 0.95 moles = 1.9 M 0.500 L Calculate the Molarity of 185 g of CrCl 4 in 500 ml of solution

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14 THE END – GOOD BYE!

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