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III. Molarity Topic 9 The Mole. A. Molarity Concentration of a solution. total combined volume substance being dissolved.

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Presentation on theme: "III. Molarity Topic 9 The Mole. A. Molarity Concentration of a solution. total combined volume substance being dissolved."— Presentation transcript:

1 III. Molarity Topic 9 The Mole

2 A. Molarity Concentration of a solution. total combined volume substance being dissolved

3 A. Molarity 2M HCl What does this mean? You would read this as Hydrochloric acid with a Molarity of 2.

4 molar mass (g/mol) 6.02  10 23 (particles/mol) MASS IN GRAMS MOLES NUMBER OF PARTICLES LITERS OF SOLUTION Molarity (mol/L) Aqueous solution molar mass (g/mol) 6.02  10 23 (particles/mol) molar mass (g/mol) MOLES NUMBER OF PARTICLES MASS IN GRAMS Conversion Factors: We are really just adding one more of them.

5 Ex 1). What is the molarity of a solution containing 0.32 moles of NaCl in 3.4 liters? molarity =0.32 moles NaCl 3.4 L =0.094 M NaCl

6 Ex 2). Find the molarity of a 250 mL solution containing 10.0 g of NaF. 10.0 g 1 mol 41.99 g = 0.238 mol NaF 0.238 mol 0.25 L M == 0.95M NaF

7 Ex 3). How many grams of NaCl are required to make 0.500L of 0.25M NaCl? 0.500 L0.25 mol 1 L = 7.3 g NaCl 58.44 g 1 mol

8 How would you prepare 400. ml of 1.20 M solution of sodium chloride? Remember:1.20 M NaCl =1.20 moles NaCl 1.00 L solution0.400 L solution x1.20 moles NaCl 1.00 L solution=0.480 moles NaCl0.480 moles NaCl x58.5 g NaCl 1 mole NaCl=28.1 g NaCl Dissolve 28.1 g NaCl in enough water to make 400 mL of solution.


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