Presentation is loading. Please wait.

Presentation is loading. Please wait.

4/16/13 Have out: Bellwork: Solve the system of equations. A

Similar presentations


Presentation on theme: "4/16/13 Have out: Bellwork: Solve the system of equations. A"— Presentation transcript:

1 4/16/13 Have out: Bellwork: Solve the system of equations. A
pencil, red pen, highlighter, notebook, calculator 4/16/13 Have out: Bellwork: Solve the system of equations. A 2x – y + 3z = –4 B x + 2y – 5z = 11 x + 3y – 2z = 5 C Pick any two equations to eliminate a variable. Let’s eliminate x. Choose B and C x + 2y – 5z = 11 B x + 2y – 5z = 11 +1 –1(x + 3y – 2z) = –1(5) x + 3y – 2z = 5 –x – 3y + 2z = –5 C +1 – y – 3z = 6 D Label the new equation D. total:

2 Pick another pair of equations to eliminate the x–term. A and B
2x – y + 3z = –4 B x + 2y – 5z = 11 – y – 3z = 6 D x + 3y – 2z = 5 C Pick another pair of equations to eliminate the x–term. A and B 2x – y + 3z = –4 2x – y + 3z = –4 A +1 –2x – 4y + 10z = –22 –2(x + 2y – 5z) = –2(11) x + 2y – 5z = 11 B –5y + 13z = –26 E +1 Label the new equation E. +1 –5(– y – 3z) = –5(6) – y – 3z = 6 D 5y + 15z = –30 – y – 3(–2) = 6 –5y + 13z = –26 E –5y + 13z = –26 – y + 6 = 6 +1 – y = 0 28z = –56 y = 0 x + 3y – 2z = 5 z = –2 +1 +1 +1 x + 3(0) – 2(–2) = 5 (1, 0, –2) x = 5 x = 1 +1 +1

3 Yesterday we solved systems of equations in 3 variables.
Today we are going to look at the cases where there is no solution or infinitely many solutions. Infinitely Many Solutions No Solution  planes intersect in a line  planes intersect in the same plane  planes have no point in common

4 Example #1: Infinitely Many Solutions
Solve the system of equations. 4x – 6y + 4z = 12 A 6x – 9y + 6z = 18 B 5x – 8y + 10z = 20 C Eliminate x using A and B. 3(4x – 6y + 4z) = 3(12) 4x – 6y + 4z = 12 A 12x – 18y + 12z = 36 –2(6x – 9y + 6z) = –2(18) 6x – 9y + 6z = 18 B –12x + 18y – 12z = –36 0 = 0 The equation 0 = 0 is always true. This indicates that the first two equations represent the same plane. ALWAYS check to see if this plane intersects the third plane.

5 Example #1: Infinitely Many Solutions
Solve the system of equations. 4x – 6y + 4z = 12 A 6x – 9y + 6z = 18 B 5x – 8y + 10z = 20 C Eliminate x using A and B. 3(4x – 6y + 4z) = 3(12) 4x – 6y + 4z = 12 A 12x – 18y + 12z = 36 –2(6x – 9y + 6z) = –2(18) 6x – 9y + 6z = 18 B –12x + 18y – 12z = –36 0 = 0 4x – 6y + 4z = 12 5(4x – 6y + 4z) = 5(12) A 20x – 30y + 20z = 60 –4(5x – 8y + 10z) = –4(20) 5x – 8y + 10z = 20 C –20x + 32y – 40z = –80 2y – 20z = –20 Since we have an equation, the planes interest in the line. Therefore, there are infinitely many number of solutions.

6 Example #2: No Solution Solve the system of equations. 6x + 12y – 8z = 24 A 9x + 18y – 12z = 30 B 4x + 8y – 7z = 26 C Eliminate x using A and B. 6x + 12y – 8z = 24 3(6x + 12y – 8z) = 3(24) A 18x + 36y – 24z = 72 –2(9x + 18y – 12z) = –2(30) 9x + 18y – 12z = 30 B –18x – 36y + 24z = –60 0 = 12 The equation 0 = 12 is never true. Therefore, there is no solution of this system.

7 Solving Radical Equations
Solve each equation for the variable. Be sure to check for extraneous solutions. Recall: An extraneous solution is a solution of the simplified form of an equation that does not satisfy the original equation. For example, sometimes we had to eliminate answers when we solved logarithmic equations. Example #1: Step #1: Leave the radicals isolated on both sides. Step #2: Eliminate the radicals by squaring both sides. Step #3: Solve for x.

8 Solving Radical Equations
Example #2: Step #1: Leave the radical isolated on the right hand side. Step #2: Eliminate the radical by squaring both sides. Step #3: Solve for x. Check: Check: CHECK!!! Does NOT work.

9 Solving Radical Equations
Example #3: Step #1: Leave the radical isolated on left hand side. Step #2: Eliminate the radical by squaring both sides. Step #3: Solve for x. Check: Check: CHECK!!! Does NOT work.

10 Complete the worksheets
and the CST practice.


Download ppt "4/16/13 Have out: Bellwork: Solve the system of equations. A"

Similar presentations


Ads by Google