using inverse matrices

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1 using inverse matrices
Solving systems of equations using inverse matrices

2 Matrices: Inverses and Systems of equations
KUS objectives BAT solve systems of equations using inverse matrices – modelling with matrices Starter: find the determinant of each matrix 3 2 − − 5 2 3𝑎 6𝑎 −2𝑎 −4𝑎 2𝑘 𝑘+2 𝑘 𝑘+1

3 a) −𝑥+6𝑦−2𝑧=21 6𝑥−2𝑦−𝑧=−16 −2𝑥+3𝑦+5𝑧=24
WB11a Use an inverse matrix to solve the simultaneous equations a) −𝑥+6𝑦−2𝑧=21 6𝑥−2𝑦−𝑧=−16 −2𝑥+3𝑦+5𝑧=24 Write as a matrix multiplication −1 6 −2 6 −2 −1 − 𝑥 𝑦 𝑧 = 21 −16 24 𝑖𝑛𝑣𝑒𝑟𝑠𝑒 𝑖𝑠 − Find the inverse matrix (using calc) Multiply through by the inverse 𝑥 𝑦 𝑧 = − − = − = −1 4 2 So the solution is 𝒙=−𝟏 𝒚=𝟒 𝒛=𝟐

4 WB11b Use an inverse matrix to solve the simultaneous equations
3𝑦+3𝑧=2 −3𝑥−𝑦+3𝑧=−2 Write as a matrix multiplication 3 0 − −3 − 𝑥 𝑦 𝑧 = 0 2 −2 𝑖𝑛𝑣𝑒𝑟𝑠𝑒 𝑖𝑠 (18) −12 −6 − −9 −3 −9 Find the inverse matrix (using calc) Multiply through by the inverse 𝑥 𝑦 𝑧 = 1 (18) −12 −6 − −9 −3 − −2 = = So the solution is 𝒙= 𝟒 𝟑 𝒚=𝟎 𝒛= 𝟐 𝟑

5 The savings account increased in value by 1.5%
WB 12 Tyler invested a total of £5000 across three different accounts; a savings account; a property bond and a share dealing account Tyler invested £400 more in the property bond account than in the saving account After one year The savings account increased in value by 1.5% The property bond account had increased in value by 3.5% The share dealing account had decreased in value by 2.5% The total value across Tylers three accounts had increased by £79 Form and solve a matrix equation to find out how much money was invested by Tyler in each account 𝒙 Saccount 𝒚 PB account 𝒛 SD account Total at start is 𝒙 𝒚 𝒛=𝟓𝟎𝟎𝟎 100 more males at start 𝒙 − 𝒚 = −𝟒𝟎𝟎 Question from Specimen materials 2018 After 1 year 1.015𝒙+1.035𝒚+0.975𝒛=𝟒𝟗𝟐𝟏 − 𝑥 𝑦 𝑧 = −

6 WB12 (cont) Form and solve a matrix equation to find out how much money was invested by Tyler in each account − 𝑥 𝑦 𝑧 = − 𝑖𝑛𝑣𝑒𝑟𝑠𝑒 𝑖𝑠 − −9.75 − −0.2 −20 Find the inverse matrix (using calc) Multiply through by the inverse 𝑥 𝑦 𝑧 = − −9.75 − −0.2 − − = So the solution is £𝟐𝟐𝟎 Saccount £𝟔𝟐𝟎 PB account £𝟒𝟏𝟔𝟎 SD account Check this works in the original question

7 WB13 A colony of 1000 mole rats is made up of adult males, adult females and youngsters. Originally there were 100 more adult females than adult males After one year The number of adult males had increased by 2% The number of adult females had increased by 3% The number of youngsters had decreased by 4% The total number mole-rats had decreased by 20 Form and solve a matrix equation to find out how many of each type of mole-rat were in the original colony 𝒙 adult males 𝒚 adult females 𝒛 youngsters Total at start is 𝒙 𝒚 𝒛=𝟏𝟎𝟎𝟎 100 more males at start 𝒙 − 𝒚 = −𝟏𝟎𝟎 After 1 year 1.02𝒙+1.03𝒚+0.96𝒛=𝟗𝟖𝟎 − 𝑥 𝑦 𝑧 = −

8 WB 13 (cont) Form and solve a matrix equation to find out how many of each type of mole-rat were in the original colony − 𝑥 𝑦 𝑧 = − 𝑖𝑛𝑣𝑒𝑟𝑠𝑒 𝑖𝑠 − −96 − −1 −200 Find the inverse matrix (using calc) Multiply through by the inverse 𝑥 𝑦 𝑧 = − −96 − −1 − − = = So the solution is 𝟏𝟎𝟎 adult males 𝟐𝟎𝟎 adult females 𝟕𝟎𝟎 youngsters Check this works in the original question

9 1) If the determinant ≠ 0 then the system has a unique solution
Notes To determine if a system of equations is consistent or inconsistent 1) If the determinant ≠ 0 then the system has a unique solution and is consistent Three planes intersect at a single point 2) If the determinant = 0 the matrix is singular then there are two cases i) the matrix is singular and consistent and has infinite solutions Three planes intersect at a line The planes form a ‘SHEAF’ ii) the matrix is singular and inconsistent and has NO solutions You will meet this more in the chapter on Vectors and planes Three planes do not intersect at the same points anywhere or are parallel

10 3𝑥−𝑘𝑦−6𝑧=𝑘 𝑘𝑥+3𝑦+3𝑧=2 −3𝑥−𝑦+3𝑧=−2
WB 15a For each of the following values of k, determine whether the system of equations below is consistent or inconsistent. If consistent, determine whether there is a unique solution or an infinity of solutions. In each case, identify the geometric configuration of the planes corresponding to each value of k a) k = b) k = c) k = -6 3𝑥−𝑘𝑦−6𝑧=𝑘 𝑘𝑥+3𝑦+3𝑧=2 −3𝑥−𝑦+3𝑧=−2 3 −𝑘 −6 𝑘 3 3 −3 − 𝑥 𝑦 𝑧 = 𝑘 2 −2 a) If k = − −3 − 𝑥 𝑦 𝑧 = 0 2 −2 3 0 − −3 −1 3 = −1 3 −0+ − −3 −1 =3 12 −6 9 =−18 1) If the determinant ≠ 0 then the system has a unique solution and is consistent Three planes intersect at a single point

11 WB 15b For each of the following values of k, determine whether the system of equations below is consistent or inconsistent. If consistent, determine whether there is a unique solution or an infinity of solutions. In each case, identify the geometric configuration of the planes corresponding to each value of k a) k = b) k = c) k = -6 b) If k = −1 − −3 − 𝑥 𝑦 𝑧 = 1 2 −2 3 −1 − −3 −1 3 = −1 3 − − − −3 −1 =3 12 −1(12)−6 8 =0 2) If the determinant = 0 the matrix is singular then there are two cases You need to determine if the system is consistent: Eliminate one of the variables from the set of equations. If the resulting two equations are consistent then the system is consistent 3𝑥−𝑦−6𝑧= (1) 𝑥+3𝑦+3𝑧= (2) −3𝑥−𝑦+3𝑧=−2 (3) 5𝑥+5𝑦= (1)+2x(2) 4𝑥+4𝑦= (2) – (3) the system is consistent: equations (4) and (5) are consistent because one is a linear multiple of the other. Any values of x and y that satisfy (4) also satisfy (5)

12 WB 15b For each of the following values of k, determine whether the system of equations below is consistent or inconsistent. If consistent, determine whether there is a unique solution or an infinity of solutions. In each case, identify the geometric configuration of the planes corresponding to each value of k a) k = b) k = c) k = -6 c) If k = −6 −6 3 3 −3 − 𝑥 𝑦 𝑧 = −6 2 −2 3 6 −6 −6 3 3 −3 −1 3 = −1 3 −6 −6 3 − −6 −6 3 −3 −1 =3 12 −6(−9)−6 15 =0 2) If the determinant = 0 the matrix is singular then there are two cases You need to determine if the system is consistent: Eliminate one of the variables from the set of equations. If the resulting two equations are consistent then the system is consistent 3𝑥+6𝑦−6𝑧=− (1) −6𝑥+3𝑦+3𝑧= (2) −3𝑥−𝑦+3𝑧=− (3) 5𝑦−3𝑧=− (1)+ (3) 15𝑦−9𝑧=− x(1) + (2) the system is Inconsistent and has no solutions: equations (4) and (5) are inconsistent because they are not solvable. No values of y and z satisfy both simultaneously

13 One thing to improve is –
KUS objectives BAT solve systems of equations using inverse matrices – modelling with matrices self-assess One thing learned is – One thing to improve is –

14 END


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