1. Linear heat conduction experiment

2. Objectives
To show how heat conducts linearly along a solid bar of uniform dimensions and materials
To show how different materials in contact can affect liner heat transfer.
To show how you can calculate the experimental thermal conductivity of the material in a solid bar.
To show how thermal paste helps to give a good thermal connection.

3. Introduction
Linear temperature gradient:

4. Thermal conductivity
Thermal conductivity of a material can be defined as the rate of heat transfer through a unit thickness of the material per unit area per unit temperature difference.
Power = rate of heat transfer = KA (Temperature gradient)
Where Temperature gradient is(T1-T2)/L
And K= 𝑄 L/(T1-T2(*A

5. Equipment's
Base unit:TD1002 Heat Transfer Experiments Base Unit

6. TD1002 a Linear Heat Conduction Experiment

7. Procedure Standard brass material
Connect and setup the liner heat conduction experiment (TD1002A).
Fit the brass middle section, using the heat transfer paste as described in using the thermal paste .

8. Create a blank results table.
Experiment:
Middle Section Material:
Ambient Temperature:
power (W)
T1(C)
T2(C)
T3(C)
T4(C)
T5(C)
T6(C)
T7(C)
Distance from
T1(m)
0.02
0.04
0.06
0.08
0.10
0.12

9. Use accurate thermometer to check the local ambient air temperature for reference.
Open the water outlet valve to start the water flowing, then switch on the heater and set to 30 watts power.
Wait for the temperature to stabilize and then record T1 to T7.
For the comparison, repeat the test at one or more heater powers greater than 30 W.
Switch off the heater and the water supply.

10. Results
The relationship between the Temperature and Distance at power 30watt

11. The relationship between the Temperature and Distance at power 40watt

12. Calculation the thermal conductivity at power 30 and 40 watt
K= 𝑄 L/(T1-T2*A)
At L=0.12m , area A= 𝑚 2 and temperature different between T7 and T1
Comparison between the theatrical and experimental thermal conductivity

13. The relationship between the Temperature and Thermal conductivity at power 30watt only at length =0.02m