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Math 2 Warm Up 2x2 – 4x(3x – 5) 3x(x – 2) (x – 2)(x + 5)

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Presentation on theme: "Math 2 Warm Up 2x2 – 4x(3x – 5) 3x(x – 2) (x – 2)(x + 5)"— Presentation transcript:

1 Math 2 Warm Up 2x2 – 4x(3x – 5) 3x(x – 2) (x – 2)(x + 5)
Simplify each expression: 2x2 – 4x(3x – 5) 3x(x – 2) (x – 2)(x + 5) (-4x + 3)(2x – 7) 3x(2x – 7) + 6x(4x + 5) x(1 – x) – (1 – 2x2) (5x + 3) 2 -7x(5x2 – 4x) (4x – 5) (-2x2 + 3x – 9)

2 Unit 5: “Quadratic Functions” Lesson 1 - Properties of Quadratics
Objective: To find the vertex & axis of symmetry of a quadratic function then graph the function. quadratic function – is a function that can be written in the standard form: y = ax2 + bx + c, where a ≠ 0. Examples: y = 5x2 y = -2x2 + 3x y = x2 – x – 3

3 Properties of Quadratics
parabola – the graph of a quadratic equation. It is in the form of a “U” which opens either upward or downward. vertex – the maximum or minimum point of a parabola.

4 Properties of Quadratics
axis of symmetry – the line passing through the vertex about which the parabola is symmetric (the same on both sides).

5 Properties of Quadratics
Find the coordinates of the vertex, the equation for the axis of symmetry of each parabola. Find the coordinates points corresponding to P and Q.

6 Graphing a Quadratic Equation y = ax2 + bx + c
1) Direction of the parabola? If a is positive, then the graph opens up. If a is negative, then the graph opens down.

7 Graphing a Quadratic Equation y = ax2 + bx + c
2) Find the vertex and axis of symmetry. The x-coordinate of the vertex is 𝐱= −𝐛 𝟐𝐚 (also the equation for the axis of symmetry). Substitute the value of x into the quadratic equation and solve for the y-coordinate. Write vertex as an ordered pair (x , y).

8 Graphing a Quadratic Equation y = ax2 + bx + c
3) Table of Values. Choose two values for x that are one side of the vertex (either right or left). Substitute those values into the quadratic equation to find y values. Graph the two points. Graph the reflection of the two points on the other side of the parabola (same y-values and same distance away from the axis of symmetry).

9 y = 2x2 + 4x + 3 Direction: _____ Vertex: ______ Axis: _______
Find the vertex and axis of symmetry of the following quadratic equation. Then, make a table of values and graph the parabola. y = 2x2 + 4x + 3 Direction: _____ Vertex: ______ Axis: _______

10 y = – x2 + 3x – 1 Direction: _____ Vertex: ______ Axis: _______
Find the vertex and axis of symmetry of the following quadratic equation. Then, make a table of values and graph the parabola. y = – x2 + 3x – 1 Direction: _____ Vertex: ______ Axis: _______

11 y = – 𝟏 𝟐 x2 + 2x + 5 Direction: _____ Vertex: ______ Axis: _______
Find the vertex and axis of symmetry of the following quadratic equation. Then, make a table of values and graph the parabola. y = – 𝟏 𝟐 x2 + 2x + 5 Direction: _____ Vertex: ______ Axis: _______

12 y = 3x2 – 4 Direction: _____ Vertex: ______ Axis: _______
Find the vertex and axis of symmetry of the following quadratic equation. Then, make a table of values and graph the parabola. y = 3x2 – 4 Direction: _____ Vertex: ______ Axis: _______

13 Apply! The number of widgets the Woodget Company sells can be modeled by the equation -5p2 + 10p + 100, where p is the selling price of a widget. What price for a widget will maximize the company’s revenue? What is the maximum revenue?

14 End of Day 1 P 244 #10-21, 28-32

15 where (h, k) is the vertex.
Math 2 Unit 5 Lesson 2 Unit 5:"Quadratic Functions" Title: Translating Quadratic Functions Objective: To use the vertex form of a quadratic function. y = a(x – h)2 + k where (h, k) is the vertex.

16 y = 2(x – 1) 2 + 2 Direction: _____ Vertex: ______ Axis: _______
Example 1: Graphing from Vertex Form y = 2(x – 1) 2 + 2 Direction: _____ Vertex: ______ Axis: _______

17 y = (x + 3) 2 – 1 Direction: _____ Vertex: ______ Axis: _______
Example 2: Graphing from Vertex Form y = (x + 3) 2 – 1 Direction: _____
 Vertex: ______ Axis: _______

18 y = −1 2 (x – 3) 2 – 2 Direction: _____ Vertex: ______ Axis: _______
Example 3: Graphing from Vertex Form y = −1 2 (x – 3) 2 – 2 Direction: _____
 Vertex: ______ Axis: _______

19 Example 4: Write quadratic equation in vertex form.

20 Example 5: Write quadratic equation in vertex form.

21 y = x2 - 4x + 6 Example 6: Converting Standard Form to Vertex Form.
Step 1: Find the Vertex x = -b = y = Step 2: Substitute into Vertex Form: y = x2 - 4x + 6 2a

22 y = 6x2 – 10 Example 7: Converting Standard Form to Vertex Form.
Step 1: Find the Vertex x = -b = y = Step 2: Substitute into Vertex Form: y = 6x2 – 10 2a

23 y = 2(x – 1) 2 + 2 Example 8: Converting Vertex Form to Standard Form.
Step 1: Square the Binomial. Step 2: Simplify to y = 2(x – 1) 2 + 2

24 Example 9: Converting Vertex Form to Standard Form.
Step 1: Square the Binomial. Step 2: Simplify to y = −1 2 (x – 3) 2 – 2

25 Honors Math 2 Assignment:
In the Algebra 2 textbook: pp #3, 6, 9, 17-20, 25, 27, 31, 34, 52, 54

26 End of Day 2 P 251 #3, 6, 17-19, 27, 31, 34, 43, 45, 52, 54

27 Factoring Quadratic Expressions
Objective: To find common factors and binomial factors of quadratic expressions. factor – if two or more polynomials are multiplied together, then each polynomial is a factor of the product. (2x + 7)(3x – 5) = 6x2 + 11x – 35 FACTORS PRODUCT (2x – 5)(3x + 7) = 6x2 – x – 35 “factoring a polynomial” – reverses the multiplication!

28 Finding Greatest Common Factor
greatest common factor (GCF) – the greatest of the common factors of two or more monomials. 𝟕 𝒙 𝟐 + 𝟐𝟏 𝟒 𝒙 𝟐 + 20x − 12 𝟗 𝒙 𝟐 − 24x

29

30 Finding Binomial Factors
𝒙 𝟐 + 14x + 40

31 Finding Binomial Factors
𝒙 𝟐 + 12x + 32

32 Finding Binomial Factors
𝒙 𝟐 − 11x + 24

33 Finding Binomial Factors
𝒙 𝟐 − 17x + 72

34 Finding Binomial Factors
𝒙 𝟐 − 14x − 32

35 Finding Binomial Factors
𝒙 𝟐 + 3x − 28

36 Finding Binomial Factors
𝟐𝒙 𝟐 + 11x + 12

37 Finding Binomial Factors
𝟔𝒙 𝟐 − 31x + 35

38 Finding Binomial Factors
𝟏𝟐𝒙 𝟐 + 32x − 35

39 Finding Binomial Factors
𝟑𝒙 𝟐 − 16x − 12

40 Finding Binomial Factors*
𝟏𝟎𝒙 𝟐 + 35x − 45

41 Finding Binomial Factors*
𝟗𝒙 𝟐 + 42x + 𝟒𝟗

42 Finding Binomial Factors*
𝟐𝟓𝒙 𝟐 − 90x + 𝟖𝟏

43 Factoring Special Expressions*
𝟒𝒙 𝟐 − 49 𝟐𝟓𝒙 𝟐 − 9 𝟑𝒙 𝟐 − 192 𝟗𝒙 𝟐 − 36

44 Math 2 Assignment pp #7-21 odd, odd, 48 End of Day 3

45 Factor. 𝟏𝟎𝒙 𝟐 + 35x − 45 𝟗𝒙 𝟐 − 36 𝟑𝒙 𝟐 − 16x − 12

46 Solving Quadratics Equations: Factoring and Square Roots
Objective: To solve quadratic equations by factoring and by finding the square root.

47 Solve by Factoring 𝒙 𝟐 + 7x − 18 = 0

48 Solve by Factoring 𝟑 𝒙 𝟐 − 20x − 7 = 0

49 Solve by Factoring 𝟖𝒙 𝟐 − 5 = 6x

50 Solve by Factoring 𝟔𝒙 𝟐 =𝟒𝟏𝐱 −𝟔𝟑

51 Solve by Factoring* 𝟒𝒙 𝟐 + 16x = 10x +𝟒𝟎

52 Solve by Factoring* 𝟏𝟔𝒙 𝟐 − 𝟖𝒙 =𝟎

53 Solve Using Square Roots
Quadratic equations in the form 𝒂 𝒙 𝟐 =𝒄 can be solved by finding square roots. 𝟑𝒙 𝟐 = 243

54 Solve Using Square Roots
𝟓𝒙 𝟐 − 200 = 0

55 Solve Using Square Roots*
𝟒𝒙 𝟐 − 25 = 0

56 Math 2 Assignment p. 266 #1-19 End of Day 4

57 Unit 4, Lesson 5: Complex Numbers Objective: To define imaginary and complex numbers and to perform operations on complex numbers

58 Introducing Imaginary Numbers
Find the solutions to the following equation:

59 Introducing Imaginary Numbers
Find the solutions to this equation:

60 Imaginary numbers offer solutions to this problem!
i1 = i i2 = -1 i3 = -i i4 = 1

61 Simplifying Complex Numbers

62 Adding/Subtracting Complex Numbers
(8 + 3i) – (2 + 4i) 7 – (3 + 2i) (4 - 6i) + (4 + 3i)

63 Multiplying Complex Numbers
(12i)(7i) (6 - 5i)(4 - 3i) (3 - 7i)(2 - 4i) (4 - 9i)(4 + 3i)

64 Now we can finally find ALL solutions to this equation!

65 Complex Solutions 3x² + 48 = 0 -5x² = 0 8x² + 2 = 0 9x² + 54 = 0

66 Math 2 Assignment P # 1-17 odd, odd, 41-46 End of Day 5

67

68 Completing the Square 1.) Move the constant to opposite side of the equation as the terms with variables in them. 2.) Take half of the coefficient with the x-term and square it 3.) Add the number found in step 2 to both sides of the equation. 4.) Factor side with variables into a perfect square. 5.) Square root both sides (put + in front of square root on side with only constant) 6.) Solve for x.

69 using completing the square
Solve the following, using completing the square 1.) x2 – 3x – 28 = ) x2 – 3x = ) x2 + 6x + 9 = 0

70 If a ≠ 1, then divide all the term by “a”.
1.) 2x2 + 6x = ) 3x2 – 12x + 7 = 0 3.) 5x2 + 20x + -50

71 Math 2 Assignment P # 15 – 25, 37, 39 End of Day 6

72 Solve using Completing the square
x2 + 4x = 21 x2 – 8x – 33 = 0 4x2 + 4x = 3

73 Solving Quadratic Equations: Quadratic Formula
Objective: To solve quadratic equations using the Quadratic Formula. Not every quadratic equation can be solved by factoring or by taking the square root! 𝟐𝒙 𝟐 + 5x − 𝟖 = 0

74 Solve using Quadratic Formula
𝟐𝒙 𝟐 + 5x − 8 = 0

75 Solve using Quadratic Formula
𝟑𝒙 𝟐 + 23x + 40 = 0

76 Solve using Quadratic Formula
𝟗𝒙 𝟐 +𝟔𝐱−𝟏=𝟎

77 Solve using Quadratic Formula*
𝟒𝒙 𝟐 −𝟖𝒙=− 𝟏𝟎

78 Solve using Quadratic Formula
𝟐𝟓𝒙 𝟐 −𝟑𝟎𝒙+𝟏𝟐=𝟎

79 Solve using Quadratic Formula
𝟑𝒙 𝟐 −𝟐𝒙+𝟒=𝟎

80 Solve using Quadratic Formula
𝟐𝒙 𝟐 = -6x – 7

81 Math 2 Assignment P 289 #1, 2, 22-30 End of day 7

82 Solving Quadratic Equations: Graphing
Objective: To solve quadratic equations and systems that contain a quadratic equation by graphing. When the graph of a function intersects the x-axis, the y-value of the function is 0. Therefore, the solutions of the quadratic equation ax2 + bx + c = 0 are the x-intercepts of the graph. Also known as the “zeros of the function” or the “roots of the function”.

83 Solve Quadratic Equations by Graphing
Solution

84 Solve Quadratic Equations by Graphing
Step 1: Quadratic equation must equal 0! ax2 + bx + c = 0 Step 2: Press [Y=]. Enter the quadratic equation in Y1. Enter 0 in Y2. Press [Graph]. MAKE SURE BOTH X-INTERCEPTS ARE ON SCREEN! ZOOM IF NEEDED! Step 3: Find the intersection of ax2 + bx + c and Press [2nd] [Trace]. Select [5: Intersection]. Press [Enter] 2 times for 1st and 2nd curve. Move cursor to one of the x-intercepts then press [Enter] for the 3rd time. Repeat Step 3 for the second x-intercept!

85 Solve by Graphing 𝒙 𝟐 + 6x + 4 = 0

86 Solve by Graphing 𝟐𝒙 𝟐 + 4x – 7 = 0

87 Solve by Graphing 𝟑𝒙 𝟐 + 5x = 20

88 Solve by Graphing 𝟓𝒙 𝟐 +𝟕 = 19x

89 Solve by Graphing 𝒙 𝟐 = -2x + 7

90 Solve by Graphing −𝟑𝒙 𝟐 + 2x – 6 = 0

91 Solve by Graphing 𝒙 𝟐 + 𝟖𝒙 + 16 = 0

92 P 266 #20-31, 54-56 End of Day 8

93 Solving Systems of Equations

94 Solve a System with a Quadratic Equation
𝒚= 𝒙 𝟐 + x − 𝟐 𝒚=−𝒙+𝟑

95 Solve a System with a Quadratic Equation
𝒚=𝟐𝒙 𝟐 + x 𝒚= 𝟒 𝟑 𝒙+𝟒

96 Solve a System with a Quadratic Equation
𝒚= 𝒙 𝟐 + 𝟒𝒙 + 𝟕 𝒚=−𝟐𝒙

97 Solve a System with a Quadratic Equation
𝒚= 𝒙 𝟐 −𝟔x + 𝟏𝟎 𝒚=𝟏

98 Solve a System with Quadratic Equations
𝒚= 𝒙 𝟐 − 𝟔𝒙+𝟓 𝒚=−𝟐𝒙 𝟐 +𝟓𝒙

99 Solve a System with Quadratic Equations
𝒚= 𝒙 𝟐 + 𝟕𝒙 𝐲= 𝟏 𝟒 𝒙 𝟐 −𝟓𝒙−𝟗 𝒚= 𝒙 𝟐 − 𝟔𝒙+𝟓 𝒚=−𝟐𝒙 𝟐 +𝟓𝒙

100 Worksheet Solve each quadratic equation or system by graphing.
Math 2 Assignment Worksheet Solve each quadratic equation or system by graphing. End of Day 9

101 Finding a Quadratic Model
1) Turn on plot: Press [2nd] [Y=], [ENTER], Highlight “On”, Press [ENTER]   2) Turn on diagnostic: Press [2nd] [0] (for catalog), Scroll down to find DiagonsticOn. Press [ENTER] to select. Press [ENTER] again to activate.

102 Finding a Quadratic Model
3) Enter data values: Press [STAT], [ENTER] (for EDIT), Enter x-values (independent) in L1 Enter y-values (dependent) in L2 Clear Lists (if needed): Highlight L1 or L2 (at top) Press [CLEAR], [ENTER].

103 Finding a Quadratic Model
4) Graph scatter plot: Press [ZOOM], 9 (zoomstat) 5) Find quadratic equation to fit data: Press [STAT], over to CALC, For Quadratic Model - Press 5: QuadReg Press [ENTER] 4 times, then Calculate. Write quadratic equation using the values of a, b, and c rounded to the nearest thousandths if needed. Write down the R2 value!

104 Find a quadratic equation to model the values in the table.
X Y -1 -8 2 1 3 8

105 𝑹 𝟐 is a measure of the “goodness-of-fit” of a regression model.
the value of R2 is between 0 and 1 (0 ≤ R2 ≤ 1) R2  = 1 means all the data points “fit” the model (lie exactly on the graph with no scatter) – “knowing x lets you predict y perfectly!” R2 = 0 means none of the data points “fit” the model – “knowing x does not help predict y!” An R2 value closer to 1 means the better the regression model “fits” the data.

106 Find a quadratic equation to model the values in the table.
X Y 2 3 13 4 29

107 Find a quadratic equation to model the values in the table.
X Y -5 -18 -4 2 -14

108 Find a quadratic equation to model the values in the table.
X Y -2 27 1 10 5 -10 7 12

109 Apply! The table shows data about the wavelength (in meters) and the wave speed (in meters per second) of the deep water ocean waves. Model the data with a quadratic function then use the model to estimate: the wave speed of a deep water wave that has a wavelength of 6 meters. the wavelength of a deep water wave with a speed of 50 meters per second. Wavelength (m) Wave Speed (m/s) 3 6 5 16 7 31 8 40

110 Apply! The table at the right shows the height of a column of water as it drains from its container. Model the data with a quadratic function then use the model to estimate: the water level at 35 seconds. the waver level at 80 seconds. the water level at 3 minutes. the elapsed time for the water level to reach 20 mm.

111 p 237 #16-22, 31 Write down the R² value for each equation!
Math 2 Assignment p 237 #16-22, 31 Write down the R² value for each equation! End of Day 10


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