Arithmetic Sequences as Linear Functions

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Presentation transcript:

Arithmetic Sequences as Linear Functions

Sequence: A set of numbers , or terms, in a specific order. (i. e Sequence: A set of numbers , or terms, in a specific order. (i.e. a pattern)

Term: a number in a pattern. Function Notation: f(x) is saying the function of x. With sequences, we say f(n). Term: a number in a pattern. 3, 6, 9, … We would say 3 is the 1st term, 6 is the 2nd term and so on. nth: the “nth” term of the pattern. Whatever term we want to find.

What are the next three terms of this sequence? 26, 22, 18, 14, ____, ____, ____ How do you know?

What are the next three terms of this sequence? 15, 9, 3, -3, ____, ____, ____ How do you know?

These sequences are what we call, Arithmetic Sequence. (they increases or decreases at a constant rate) How did you know? Is called the “Common Difference”. (difference between terms of an arithmetic sequence). We represent by d.

Is the sequence arithmetic? 1, 4, 9, 16, 25… If so, what is d?

Is the sequence arithmetic? -18, -8, 2, 12, 22… If so, what is d? What are the next three terms?

What does the graph of an arithmetic sequence look like? 3, 6, 9, 12… What is the slope? What is the y-intercept? Write an equation.

How do we find the equations of an arithmetic sequence? Let’s go back and look at the arithmetic sequence 26, 22, 18, 14, ____, ____, ____ We already found that d = -4. Can you write TWO equation for this sequence? Let’s compare it to our formulas.

How do we find the formula of an arithmetic sequence? There are two different kinds. Recursive formula: depends on the previous term. It’s the previous answer or f(n-1) plus the common difference. f(n) = f(n-1) + d Think “What it is = what it was + the difference” Explicit formula: Find the nth term without knowing the previous term. You will need to know the 0 term or f(0). f(n) = f(0) + dx This should look like y = mx + b

f(n) = f(n-1) + d f(n) = f(n-1) + - 4 f(n) = 30 + -4n Recursive formula: depends on the previous term. It’s the previous answer or f(n-1) plus the common difference. f(n) = f(n-1) + d Think “What it is = what it was + the difference” f(n) = f(n-1) + - 4 Explicit formula: Find the nth term without knowing the previous term. You will need to know the 0 term or f(0). f(n) = 30 + -4n Hmmm….looks like y = mx + b