Chapter 10: Lesson 5 -Titration- Chapter 10: Lesson 5 -Titration-

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Chapter 10: Lesson 5 -Titration- Chapter 10: Lesson 5 -Titration-

Need Right Combo To Create Balance = + But which blue? = + But which blue? green yellow

Titration  Uses neutralization to find concentration of acid or base  Equivalence point is when acid balances base and solution is a neutral pH of 7  Uses neutralization to find concentration of acid or base  Equivalence point is when acid balances base and solution is a neutral pH of 7

Moles H+ = Moles of OH-  How many moles of HCl are needed to exactly neutralize 5 moles of NaOH?  How many moles of LiOH are needed to exactly neutralize 2 moles of H 2 SO 4 ?  How many moles of HCl are needed to exactly neutralize 5 moles of NaOH?  How many moles of LiOH are needed to exactly neutralize 2 moles of H 2 SO 4 ?

If Not Simple Mole # M A V A = M B V B  M A V A = concentration acid x volume acid  M B V B = concentration base x volume base  M =mol/L M A V A = M B V B  M A V A = concentration acid x volume acid  M B V B = concentration base x volume base  M =mol/L

M = mol/L  How many moles of HCl are needed to neutralize 0.1 L of 2 M solution of NaOH?

M A V A = M B V B  It takes 15 mL of 0.4 M NaOH to neutralize 5 mL of HCl. What is the concentration of the HCl?

M A V A = M B V B  How many mL of 0.1 M Ca(OH) 2 are required to neutralize 25 mL of 0.5 M HNO 3 ?

For The Rest Of Class  Work on practice packet, especially titration questions  Have pages completed for Thursday  Work on practice packet, especially titration questions  Have pages completed for Thursday