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Ch. 15 & 16 - Acids & Bases III. Titration (p. 493 - 503)

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Presentation on theme: "Ch. 15 & 16 - Acids & Bases III. Titration (p. 493 - 503)"— Presentation transcript:

1 Ch. 15 & 16 - Acids & Bases III. Titration (p )

2 A. Neutralization Chemical reaction between an acid and a base.
Products are a salt (ionic compound) and water. Video #20 (Buffers, the acid)

3 ACID + BASE  SALT + WATER
A. Neutralization ACID + BASE  SALT + WATER HCl + NaOH  NaCl + H2O strong strong neutral HC2H3O2 + NaOH  NaC2H3O2 + H2O weak strong basic Salts can be neutral, acidic, or basic. Neutralization does not mean pH = 7.

4 B. Titration video #21(Setting up )
standard solution unknown solution Titration Analytical method in which a standard solution is used to determine the concentration of an unknown solution.

5 B. Titration Equivalence point (endpoint)
Point at which equal amounts of H3O+ and OH- have been added. Determined by… indicator color change dramatic change in pH

6 moles H3O+ = moles OH- MV n = MV n B. Titration M: Molarity
V: volume n: # of H+ ions in the acid or OH- ions in the base

7 B. Titration 42.5 mL of 1.3M KOH are required to neutralize 50.0 mL of H2SO4. Find the molarity of H2SO4. H3O+ M = ? V = 50.0 mL n = 2 OH- M = 1.3M V = 42.5 mL n = 1 MV# = MV# M(50.0mL)(2) =(1.3M)(42.5mL)(1) M = 0.55M H2SO4

8 Video #19(pH and pOH: CC) pH and pOH


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