Oct. 29, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation.

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Presentation transcript:

Oct. 29, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation to apply in each situation Homework 1. Pages 4-5

CHAMPS for Bell Ringer C – Conversation – No Talking H – Help – RAISE HAND for questions A – Activity – Solve Bell Ringer on binder paper. Homework out on desk M – Materials and Movement – Pen/Pencil, Notebook or Paper P – Participation – Be in assigned seats, work silently S – Success – Get a stamp! I will collect!

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

4 MINUTES REMAINING…

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

3 MINUTES REMAINING…

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

2 MINUTES REMAINING…

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

1minute Remaining…

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

30 Seconds Remaining…

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

BELL- RINGER TIME IS UP!

October 29th (p. 13) Objective: Students will be able to identify which kinematic equation to apply in each situation Bell Ringer: Let’s say two people are racing: The first person has a large initial velocity (20 m/s) but a slow acceleration (1 m/s 2 ). The other has a small initial velocity (0 m/s) but a large Acceleration (5 m/s 2 ). Who will win the race and why?

Shout Outs Period 5 – Period 7 –

Oct. 29, 2012 AGENDA: 1 – Bell Ringer 2 – Kinematics Equations 3 – Exit Ticket Today’s Goal: Students will be able to identify which kinematic equation to apply in each situation Homework 1. Pages 4-5

Week 8 Weekly Agenda Monday – Kinematic Equations I Tuesday – Kinematic Equations II Wednesday – Kinematic Equations III Thursday – Review Friday – Review Unit Test in 2 weeks!

CHAMPS for Problems p. 4-6 C – Conversation – No Talking unless directed to work in groups H – Help – RAISE HAND for questions A – Activity – Solve Problems on Page 4-6 M – Materials and Movement – Pen/Pencil, Packet Pages 4-6 P – Participation – Complete Page 4-6 S – Success – Understand all Problems

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner?

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner?

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds

Solving Problems (p. 4) 1. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. What is the final velocity of the Road Runner? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds vf = ?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval?

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds

Solving Problems (p. 4) 2. Starting from rest, the Road Runner accelerates at 3 m/s 2 for ten seconds. How far does the Road Runner travel during the ten second time interval? vi = 0 m/s a = 3 m/s 2 Δt = 10 seconds Δx = ?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/s a = 40,000 m/s 2 Δx = 0.5 m

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/s a = 40,000 m/s 2 Δx = 0.5 m

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/s a = 40,000 m/s 2 Δx = 0.5 m vf = ?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 3. A bullet starting from rest accelerates at 40,000 m/s 2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun? vi = 0 m/s a = 40,000 m/s 2 Δx = 0.5 m vf = ?

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 4) 4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car? vi = 20 m/s vf = 0 m/s Δt = 4 seconds a = ?

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Notes: Kinematic Equations The Four Kinematic Equations: v f = v i + a Δ t Δx = v i Δt + aΔt 2 2 v f 2 = v i 2 + 2a Δx Δx = (v f + v i )Δt 2

Solving Problems (p. 5) 5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 5) 5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?

Solving Kinematics Problems Step 1: Read the Problem, underline key quantities Step 2: Assign key quantities a variable Step 3: Identify the missing variable Step 4: Choose the pertinent equation: Step 5: Solve for the missing variable. Step 6: Substitute and solve.

Solving Problems (p. 5) 6. The USS Enterprise accelerates from rest at 100,000 m/s 2 for a time of four seconds. How far did the ship travel in that time?

Exit Ticket (p. 14) 12, Calvin tosses a water balloon to Hobbes. As Hobbes is about to catch it the balloon has a speed of 1 m/s. Hobbes catches the balloon, and the balloon experiences an acceleration of -0.5 m/s 2 as it comes to rest. How far did Hobbes' hands move back while catching the balloon? Write the given variables, the missing variable, and the equation you will use.