4 m + 2 6 m – 3 = Apply cross product property 4 6 = (m – 3) (m + 2) 4m + 8 = 6m – 18 Distribute Subtract – 6m − 2m + 8 = − 18 Subtract − 2m = − 26 Divide.

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4 m m – 3 = Apply cross product property 4 6 = (m – 3) (m + 2) 4m + 8 = 6m – 18 Distribute Subtract – 6m − 2m + 8 = − 18 Subtract − 2m = − 26 Divide 13 = m Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 1.Solve: – 8 − 2 © by S-Squared, Inc. All Rights Reserved.

Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 2.Solve: │3x – 6│ + 2 = 11 Add x = 5 Divide x = 5 and x = x – 6 = 9 Add 3x = 15Divide Note: Isolate the absolute value. And 3x – 6 = − x = − − 1 x = − 1 │3x – 6│ + 2 = 11Subtract – 2 │3x – 6│ = 9 Note: Write the two related equations.

Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 3.Simplify: − 3│7 – 11│ + 5 − 3│− 4│ + 5 Subtract − 3( 4) + 5 Absolute Value − Multiply − 7 Add

Simplify: (Reduce whenever necessary) 4. = Reduce Common Denominator = 5. Subtract 7 9 – – − Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test

Simplify: Note: To divide fractions, we invert the fraction that follows the operation and multiply. 6. = Note: When multiplying, reduce any numerator with any denominator ÷ Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test

Simplify: 7. = Reduce Note: Rewrite 2 as fraction. Common Denominator = 8. Add Note: Rewrite mixed number as improper fraction Or 1 Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test

Note: To divide fractions, we invert and multiply. 9. = Note: When multiplying, reduce any numerator with any denominator ÷ = 7 3 Note: Rewrite mixed number as improper fraction ÷ 5 Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test

29.15 Simplify: Note: Line up decimal points and add – 9.15 Note: Line up decimal points and subtract –

Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 7 Simplify: Note: Multiply then place decimal point. x Note: Shift decimal point in numerator and denominator until the denominator is an integer Divide

− 56 5x + 49 = − Solve x + 7 = − x = − 105 Multiply each term by the LCD 7 7 – 49 x = − ( ( ( 7 Subtract Divide ( 15. Check your answer for #11. Substitute Simplify 7 5 (− 21) + 7 = − 8 − = − 8 − 8 = − 8 Answer checked Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test x5x=

6 5x 5x + 6 = 2x – 6 2x − 6 3x = − Solve x + 1 = (x – 3) 5 Multiply each term by the LCD 6 6 3x + 6 = − 6 – 2x x = − ( ( ( ( 6 Subtract − 6 Divide Distribute 3 x + 1 x – 1 = Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test = – +

17.What mathematical operation does the fraction bar represent? (Addition, Subtraction, Multiplication, or Division) DIVISION Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test Change the decimal to a fraction. (Please reduce) 0.72 Note: The 2 is in the hundredths column; rewrite as fraction with 100 in denominator. Reduce ÷ 4 18

19.Solve 1.5m – 8 = − 0.5 Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 10( ) ( )10 15m = 75 m = 5 Eliminate decimal by multiplying by 10 Divide Add m – 80 = − 5

Algebra I Concept Test # 3 – Fractions, Decimals and Eq. Practice Test 100( ) ( ) Solve and place answer in decimal form: 0.09p = 1 – 0.31p 9p = 30 – 31p p =.75 Eliminate decimal by multiplying by 100 Add Subtract 40 – p + 70 = 100 – 31p + 31p 40p = 30 Divide Reduce 3 4 Place in decimal form p = Have High Expectations!