Kinetic Energy m d v F KE = 1/2mv2 KE - Kinetic energy v- velocity

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Presentation transcript:

Kinetic Energy m d v F KE = 1/2mv2 KE - Kinetic energy v- velocity m - mass

What is the kinetic energy of a 4.20 g bullet going 965 m/s? (units?) Ek = 1/2mv2 = 1/2(.0042 kg)(965 m/s)2 = 1955.5725 (1960 J) 1955.5725 ≈ 1960 J

Ex1 - What speed must a .563 kg hammer move to store 34 J of energy? Ek = 1/2mv2 v = (2 Ek/m) = (2(34 J)/(.563 kg)) = 11 m/s 10.99 ≈ 11 m/s

Ex2 - A European swallow has 2 Ex2 - A European swallow has 2.055 J of kinetic energy when it is flying at 14.23 m/s. What is its mass in grams? Ek = 1/2mv2 m = 2 Ek/v2 = 2(2.055 J)/(14.23 m/s)2 = .020297… (20.29 g) 20.29 g

Ex3 - A 4. 0 kg shot is sped up from 6. 0 m/s to 9. 0 m/s Ex3 - A 4.0 kg shot is sped up from 6.0 m/s to 9.0 m/s. What is the change in kinetic energy? initial: Ek = 1/2mv2 = 1/2(4.0 kg)(6.0 m/s)2 = 72 J final: Ek = 1/2mv2 = 1/2(4.0 kg)(9.0 m/s)2 = 162 J So the increase is 162 – 72 = 90. J increase 90. J