# Potential and Kinetic Energy Problems

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Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?

Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh

Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m

Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m

Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m PE = 30,000J

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE = ½ mv2

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE = ½ mv2 KE = ½ (14kg)(3m/s)2 Square 1st

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) Multiply 2nd

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m Kg*m/s2

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m Divide last

Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m KE = 63 Joules

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE = ½ mv2

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg 100 m2/s2 = v2

Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg 100 m2/s2 = v2 10m/s = v

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? Given in kg, not Newtons…must multiply mass times gravity

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? PE = mgh

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m)

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m PE = 93,100 N*m

Potential and Kinetic Energy Problems
4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m PE = 93,100 N*m PE = 93,100 J

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m)

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m PE = 58.8 J

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m)

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m PE = 19.6 J

Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes? 58.8J – 19.6J = 39.2J

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