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**Potential and Kinetic Energy Problems**

What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?

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**Potential and Kinetic Energy Problems**

What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh

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**Potential and Kinetic Energy Problems**

What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m

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**Potential and Kinetic Energy Problems**

What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m

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**Potential and Kinetic Energy Problems**

What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m PE = 30,000J

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE = ½ mv2

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE = ½ mv2 KE = ½ (14kg)(3m/s)2 Square 1st

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) Multiply 2nd

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m Kg*m/s2

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m Divide last

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**Potential and Kinetic Energy Problems**

2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? KE= ½ mv2 KE = ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m KE = 63 Joules

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE = ½ mv2

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg 100 m2/s2 = v2

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**Potential and Kinetic Energy Problems**

3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2 x 2 2 100kg*m2/s2 = (1kg)v2 1 kg kg 100 m2/s2 = v2 10m/s = v

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock?

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? Given in kg, not Newtons…must multiply mass times gravity

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? PE = mgh

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m)

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m PE = 93,100 N*m

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**Potential and Kinetic Energy Problems**

4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s kg*m/s2 = N *m PE = 93,100 N*m PE = 93,100 J

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes?

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m)

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m PE = 58.8 J

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m)

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m PE = 19.6 J

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**Potential and Kinetic Energy Problems**

5. What is the approximate difference in gravitational potential energy of the two shaded boxes? 58.8J – 19.6J = 39.2J

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