Recrystallization Impure benzoic acid Benzoic acid after recrystallization
Purification of Organic Compounds Solids: Recrystallization Liquids: Distillation Solids and Liquids: Gas or liquid chromotography
Types of impurities Soluble Insoluble Partly Soluble
Solubility of benzoic acid in water
Dissolve sample in hot solvent Compound crystallizes upon cooling
Impure benzoic acid in hot water
Add water and heat until all soluble material dissolves Insoluble material is removed by filtration
The hot solution is filtered to remove insoluble impurities
Use fluted filter paper to maximize surface area.
Use GLASS funnel. Put flask on hot plate. To avoid crystallization in the funnel: Use GLASS funnel. Put flask on hot plate.
Boil off excess solvent
Boiling Sticks
Hot solution after filtration: Cool Seed Scratch
Cool, filter, wash, dry, weigh, mp Crystals form in the warm solution Next: Cool, filter, wash, dry, weigh, mp
.. Buchner funnel Heavy-walled tubing Filter flask Vacuum
Put filter paper in Buchner funnel .. Put filter paper in Buchner funnel
Filter and wash with cold solvent
Purified benzoic acid Insoluble impurities Soluble impurities
Solubility Example Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0
A I1 I2 dissolves dissolves 100 mL water at 1000 insoluble Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 A I1 I2 dissolves dissolves insoluble
Cool to 25o A dissolves I1 dissolves I2 insoluble A I1 Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 Cool to 25o A dissolves I1 dissolves I2 insoluble A I1 9.0 g crystallize 0 g crystallize Yield = 100 * 9.0/12.0 = 75%
50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble
NOT PURE! Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves I2 insoluble A I1 9.5 g crystallize 0.25 g crystallize Yield = 100 * 9.75/12.0 = 81% NOT PURE!
What volume of solvent is needed to give the maximum yield of pure A? Solubility of I1 = 1.5 g/100 mL 1.5 g 100 mL 1.0 g x mL = X = (100 mL * 1.0 g)/1.5 g = 67 mL
What is the yield of pure A from 67 mL solvent? Solubility of A = 1.0 g/100 mL 1.0 g 100 mL X g 67 mL = X = (67 mL x 1.0 g) / 100 mL = 0.67 g Yield = 10.0 g - 0.67 g = 9.33 g % yield = 100 * 9.33 / 12 = 78%