Unit 13: Solutions & Equilibrium

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Unit 13: Solutions & Equilibrium Dilutions Dilutions Calculations print 1-3,5-7

A. Dilutions M = mol L Dilution same total mol solute lowers conc. (molarity) mol L mol L M = M = 6 mol in 100 mL 6 mol in 200 mL same total mol solute

A. Dilutions Dilution initial Molarity Molarity of dilute solution initial Volume Molarity of dilute solution Volume of dilute solution

B. Calculations V1 = (0.400 M) x (100 mL) (2.00 M) (2.00 M) x V1 = Finding Volume (V1) How many mL of 2.00 M MgSO4 must be diluted to prepare 100 mL of 0.400 M MgSO4? V1 = (0.400 M) x (100 mL) (2.00 M) V1 M1 V2 M2 (2.00 M) x V1 = (0.400 M) x (100 mL) bleach V1 = 20.0 mL

B. Calculations M2 = (10.0 M) x (200 mL) (500 mL) Finding Molarity (M2) 200 mL of 10.0 M NaOH is diluted to 500 mL, what is the molarity of the dilute solution? M2 = (10.0 M) x (200 mL) (500 mL) V1 M1 V2 M2 (10.0 M) x (200 mL) = M2 x (500 mL) M2 = 4.00 M