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Solutions & Chemical Equilibrium

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Presentation on theme: "Solutions & Chemical Equilibrium"— Presentation transcript:

1 Solutions & Chemical Equilibrium
Section 2: Concentration Concentration Molarity Calculations mol L M =

2 A. Concentration Concentration
the amount of solute dissolved in a given amount of solvent Dilute – less solute Concentrated – more solute

3 B. Molarity Molarity (M) moles of solute per liter of solution
Example: 3 M HCl molar HCl mol HCl 1 L

4 B. Molarity Preparing a Solution
(in lab later) To make a 0.5 M (0.5 molar) solution, first add 0.5 mol of solute to a 1 L volumetric flask half filled with distilled water.

5 B. Molarity Preparing a Solution
(in lab later) Swirl the flask carefully to dissolve the solute.

6 B. Molarity Preparing a Solution
(in lab later) Fill the flask with water exactly to the 1 L mark.

7 C. Calculations Finding Molarity
What is the molarity of a solution containing g NaCl in 100 mL of solution? 1 mol NaCl 58.44 g NaCl 0.900 g NaCl x = mol NaCl IV saline solution mol NaCl L 0.150 M NaCl = 100 mL = L

8 C. Calculations Finding Molarity
What is the molarity of a solution with a volume of 2.00 L containing 36.0 g of C6H12O6 (glucose)? 1 mol C6H12O6 g C6H12O6 36.0 g C6H12O6 x = 0.200 mol C6H12O6 0.200 mol C6H12O L = 0.100 M C6H12O6

9 C. Calculations Finding Moles
How many moles of solute are in 3.80 L of M NaClO (bleach)? 0.700 mol NaClO 1 L 3.80 L x = 2.66 mol NaClO 0.700 M written as mol/L bleach

10 C. Calculations Finding Moles
How many moles of solute are in 250 mL of M CaCl2? 0.250 L x mol CaCl2 = 1 L 0.550 mol CaCl2 250 mL = L

11 C. Calculations Finding Mass (g)
What mass of sodium hydroxide (NaOH) is needed to make 200 mL of a M solution? 0.200 L x mol NaOH = 1 L mol NaOH x g NaOH = 1 mol mol NaOH bleach 1.20 g NaOH

12 C. Calculations Finding Volume (L)
How many liters of a 1.15 M solution are needed to give moles of solute? 0.805 mol x L = 1.15 mol How many mL are needed? 0.700 L bleach 0.700 L = 700 mL


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