Training Objective: students will be able to evaluate expressions using the order of operations.

Slides:



Advertisements
Similar presentations
1 Radio Maria World. 2 Postazioni Transmitter locations.
Advertisements

Números.
Un percorso realizzato da Mario Malizia
1 A B C
Trend for Precision Soil Testing % Zone or Grid Samples Tested compared to Total Samples.
Trend for Precision Soil Testing % Zone or Grid Samples Tested compared to Total Samples.
AGVISE Laboratories %Zone or Grid Samples – Northwood laboratory
Trend for Precision Soil Testing % Zone or Grid Samples Tested compared to Total Samples.
5.1 Rules for Exponents Review of Bases and Exponents Zero Exponents
Reflection nurulquran.com.
EuroCondens SGB E.
Worksheets.
& dding ubtracting ractions.
Addition and Subtraction Equations
Multiplication X 1 1 x 1 = 1 2 x 1 = 2 3 x 1 = 3 4 x 1 = 4 5 x 1 = 5 6 x 1 = 6 7 x 1 = 7 8 x 1 = 8 9 x 1 = 9 10 x 1 = x 1 = x 1 = 12 X 2 1.
Division ÷ 1 1 ÷ 1 = 1 2 ÷ 1 = 2 3 ÷ 1 = 3 4 ÷ 1 = 4 5 ÷ 1 = 5 6 ÷ 1 = 6 7 ÷ 1 = 7 8 ÷ 1 = 8 9 ÷ 1 = 9 10 ÷ 1 = ÷ 1 = ÷ 1 = 12 ÷ 2 2 ÷ 2 =
Fraction IX Least Common Multiple Least Common Denominator
David Burdett May 11, 2004 Package Binding for WS CDL.
Add Governors Discretionary (1G) Grants Chapter 6.
CALENDAR.
1 1  1 =.
27  9 =.
1  1 =.
CHAPTER 18 The Ankle and Lower Leg
Summative Math Test Algebra (28%) Geometry (29%)
Around the World AdditionSubtraction MultiplicationDivision AdditionSubtraction MultiplicationDivision.
Who Wants To Be A Millionaire?
The 5S numbers game..
突破信息检索壁垒 -SciFinder Scholar 介绍
A Fractional Order (Proportional and Derivative) Motion Controller Design for A Class of Second-order Systems Center for Self-Organizing Intelligent.
Objective The student will be able to:
Algebra I 1.2 Order of Operations.
Use the order of operations to evaluate expressions. Objective The student will be able to: Designed by Skip Tyler, Varina High School and redesigned by.
Order of Operations Lesson
Break Time Remaining 10:00.
The basics for simulations
Factoring Quadratics — ax² + bx + c Topic
PP Test Review Sections 6-1 to 6-6
Look at This PowerPoint for help on you times tables
Copyright © 2012, Elsevier Inc. All rights Reserved. 1 Chapter 7 Modeling Structure with Blocks.
Progressive Aerobic Cardiovascular Endurance Run
Chapter 1: Expressions, Equations, & Inequalities
Fraction IX Least Common Multiple Least Common Denominator
MaK_Full ahead loaded 1 Alarm Page Directory (F11)
Least Common Multiples and Greatest Common Factors
TCCI Barometer September “Establishing a reliable tool for monitoring the financial, business and social activity in the Prefecture of Thessaloniki”
2011 WINNISQUAM COMMUNITY SURVEY YOUTH RISK BEHAVIOR GRADES 9-12 STUDENTS=1021.
Before Between After.
2011 FRANKLIN COMMUNITY SURVEY YOUTH RISK BEHAVIOR GRADES 9-12 STUDENTS=332.
Slide R - 1 Copyright © 2009 Pearson Education, Inc. Publishing as Pearson Prentice Hall Active Learning Lecture Slides For use with Classroom Response.
12 October, 2014 St Joseph's College ADVANCED HIGHER REVISION 1 ADVANCED HIGHER MATHS REVISION AND FORMULAE UNIT 2.
Subtraction: Adding UP
Numeracy Resources for KS2
1 hi at no doifpi me be go we of at be do go hi if me no of pi we Inorder Traversal Inorder traversal. n Visit the left subtree. n Visit the node. n Visit.
Static Equilibrium; Elasticity and Fracture
Converting a Fraction to %
Resistência dos Materiais, 5ª ed.
Clock will move after 1 minute
& dding ubtracting ractions.
Maths Warm Up Term 1.
Using Lowest Common Denominator to add and subtract fractions
Select a time to count down from the clock above
1 Dr. Scott Schaefer Least Squares Curves, Rational Representations, Splines and Continuity.
1 Non Deterministic Automata. 2 Alphabet = Nondeterministic Finite Accepter (NFA)
Multiplication Facts Practice
Graeme Henchel Multiples Graeme Henchel
0 x x2 0 0 x1 0 0 x3 0 1 x7 7 2 x0 0 9 x0 0.
Schutzvermerk nach DIN 34 beachten 05/04/15 Seite 1 Training EPAM and CANopen Basic Solution: Password * * Level 1 Level 2 * Level 3 Password2 IP-Adr.
Presentation transcript:

Training Objective: students will be able to evaluate expressions using the order of operations.

33? The Order of Operations ensures that we all arrive at the same destination by ordering us what to do next.

Order of Operations P arentheses () [] E xponents x 2, M ultiplication and D ivision (left to right) A ddition and S ubtraction (left to right)

Evaluate = (2 x 5 = 10, multiplication) = 27 (37 – 10 = 27, subtraction)

Evaluate 30 ÷ = (30 ÷ 6 = 5, division) = (4 7 = 28, multiplication) = 33 ( = 33, addition)

Evaluate (28 – 12) ÷ = 16 ÷ (parentheses) = 16 ÷ (exponents) = (division) = (multiplication) = 54 (addition)

Evaluate (6 + 1) 4 = (parentheses) = (exponents) = (multiplication) = (multiplication) = (subtraction) = (addition) = 130 (addition)

The parentheses in this equation serve a vital function: (8 - 3) + 7 = 12 TrueFalse

The parentheses in this equation serve a vital function: (2 + 4) 2 = 12 TrueFalse

The parentheses in this equation serve a vital function: 10 8 – (5 + 3) = 72 TrueFalse

The parentheses in this equation serve a vital function: [(2 3 ) 3] ÷ 6 = 4 TrueFalse

To evaluate an expression with variables, first plug in the value of each variable. Next, evaluate the expression using the order of operations.

Evaluate n + (13 - n) 5 for n = 8 = 8 + (13 – 8) 5 (plug in) = (parentheses) = (division) = 9 (addition)

Evaluate 8y – (2x 2 + 6z) for x = 5, y = 7, z =1 = 8 5 – ( ) (plug in)

Evaluate 8y – (2x 2 + 6z) for x = 5, y = 7, z =1 = 8 7 – ( ) (plug in) = 8 7 – ( )(parentheses/exponents) = 8 7 – ( )(parentheses/multiplication) = 8 7 – (50 + 6)(parentheses/multiplication) = 8 7 – 56(parentheses/addition) = 56 – 56(multiplication) = 0(subtraction)

,375

You are now ready to evaluate expressions using the order of operations.

Training Objective: Graduates will be able to evaluate expressions involving multiple grouping brackets.

[16÷(9 - 1) + 4] ÷ Thirty six

[8 x ( ) – ] ÷ x 10 – ÷ 3 Twenty Four

[(92 – ( ) ÷ 6 – 1) ÷ ( – 2)] ÷ 6 – – 2 81 ÷ 27 5 Two Hundred Forty Three

Evaluate the following expression [70 – ( ( ) ÷ 5) ÷ 9]

[70 – ( (1 + 49) ÷ 5) ÷ 9] [70 – ( ÷ 5) ÷ 9] ÷ [70 – ( ÷ 5) ÷ 9] ÷ [70 – ( ) ÷ 9] ÷ [70 – 63 ÷ 9] ÷ [70 – 7] ÷ ÷ Evaluate the following expression: [70 – ( ( ) ÷ 5) ÷ 9]