Measuring Temperature Chapter 1 Measuring Temperature

LecturePLUS Timberlake Temperature Particles are always moving. When you heat water, the water molecules move faster. When molecules move faster, the substance gets hotter. When a substance gets hotter, its temperature goes up. LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check Suppose you place water in a freezer. A. The water particles move 1) faster 2) slower 3) the same B. The water will get 1) hotter 2) colder 3) stay the same C. The temperature of the water will be 1) higher 2) lower 3) the same LecturePLUS Timberlake

LecturePLUS Timberlake Temperature Measures the hotness or coldness of an object Determined by using a thermometer that contains a liquid that expands with heat and contracts with cooling. LecturePLUS Timberlake

LecturePLUS Timberlake Temperature Scales Fahrenheit Celsius Kelvin Water boils _____°F _____°C ______K Water freezes _____°F _____°C ______K LecturePLUS Timberlake

LecturePLUS Timberlake Temperature Scales Fahrenheit Celsius Kelvin Water boils 212°F 100°C 373 K Water freezes 32°F 0°C 273 K LecturePLUS Timberlake

Units of Temperature between Boiling and Freezing Fahrenheit Celsius Kelvin Water boils 212°F 100°C 373 K 180° 100°C 100K Water freezes 32°F 0°C 273 K LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check A. Temperature of freezing water 1) 0°F 2) 0°C 3) 0 K B. Temperature of boiling water 1) 100°F 2) 32°F 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 100 2) 180 3) 273 LecturePLUS Timberlake

LecturePLUS Timberlake Fahrenheit Formula °F = 9/5 T°C + 32 or °F = 1.8 T°C + 32 LecturePLUS Timberlake

Temperature Conversions A person with hypothermia has a body temperature of 29.1°C. What is the body temperature in °F? °F = 1.8 (29.1°C) + 32 = 52.4 + 32 = 84.4°F LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check The normal temperature of a chickadee is 105.8°F. What is that temperature in °C? 1) 73.8 °C 2) 58.8 °C 3) 41.0 °C LecturePLUS Timberlake

LecturePLUS Timberlake Solution 3) 41.0 °C Solution: °F = 1.8 T°C + 32 105.8 °F = 1.8 T °C + 32 105.8 °F - 32 = 1.8 T °C 73.8 = 1.8 T 41.0 °C = T LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check Pizza is baked at 455°F. What is that in °C? 1) 437 °C 2) 235°C 3) 221°C LecturePLUS Timberlake

LecturePLUS Timberlake Solution Pizza is baked at 455°F. What is that in °C? 2) 235°C Solution: °F = 1.8 T°C + 32 455 °F = 1.8 T °C + 32 455 °F - 32 = 1.8 T °C 423 = 1.8 T 235 °C = T LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check On a cold winter day, the temperature falls to -15°C. What is that temperature in °F? 1) 19 °F 2) 59°F 3) 5°F LecturePLUS Timberlake

LecturePLUS Timberlake Solution 3) 5°F Solution: T°F = 1.8(-15°C) + 32 T °F = -27 + 32 T = 5°F LecturePLUS Timberlake

LecturePLUS Timberlake Kelvin Scale On the Kelvin Scale 1K = 1°C 0 K is the lowest temperature (Absolute Zero) K °C K = °C + 273 LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check What is normal body temperature of 37°C in kelvins? 1) 236 K 2) 310 K 3) 342 K LecturePLUS Timberlake

LecturePLUS Timberlake Solution What is normal body temperature of 37°C in kelvins? 2) 310 K K = °C + 273 = 37 °C + 273 = 310. K LecturePLUS Timberlake