1. LecturePLUS Timberlake1 Chapter 1 Measuring Temperature

2. LecturePLUS Timberlake2 Temperature Particles are always moving. When you heat water, the water molecules move faster. When molecules move faster, the substance gets hotter. When a substance gets hotter, its temperature goes up.

3. LecturePLUS Timberlake3 Learning Check Suppose you place water in a freezer. A. The water particles move 1) faster 2) slower 3) the same B. The water will get 1) hotter 2) colder 3) stay the same C. The temperature of the water will be 1) higher 2) lower 3) the same

4. LecturePLUS Timberlake4 Solution Suppose you place water in a freezer. A. The water particles move 2) slower B. The water will get 2) colder C. The temperature of the water will be 2) lower

5. LecturePLUS Timberlake5 Temperature Measures the hotness or coldness of an object Determined by using a thermometer that contains a liquid that expands with heat and contracts with cooling.

6. LecturePLUS Timberlake6 Temperature Scales Fahrenheit Celsius Kelvin Water boils _____°F _____°C ______K Water freezes _____°F _____°C ______K

7. LecturePLUS Timberlake7 Temperature Scales Fahrenheit Celsius Kelvin Water boils 212°F 100°C 373 K Water freezes 32°F 0°C 273 K

8. LecturePLUS Timberlake8 Units of Temperature between Boiling and Freezing FahrenheitCelsius Kelvin Water boils 212°F 100°C 373 K 180° 100°C 100K Water freezes 32°F 0°C 273 K

9. LecturePLUS Timberlake9 Learning Check A. Temperature of freezing water 1) 0°F 2) 0°C 3) 0 K B. Temperature of boiling water 1) 100°F 2) 32°F 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 1002) 180 3) 273

10. LecturePLUS Timberlake10 Solution A. Temperature of freezing water 2) 0°C B. Temperature of boiling water 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 100

11. LecturePLUS Timberlake11 Fahrenheit Formula 180°F = 9°F =1.8°F 100°C 5°C 1°C Zero point: 0°C = 32°F °F = 9/5 T°C + 32 or °F = 1.8 T°C + 32

12. LecturePLUS Timberlake12 Celsius Formula Rearrange to find T°C °F = 1.8 T°C + 32 °F - 32 = 1.8T°C ( +32 - 32) °F - 32 = 1.8 T°C 1.8 1.8 °F - 32 = T°C 1.8

13. LecturePLUS Timberlake13 Temperature Conversions A person with hypothermia has a body temperature of 29.1°C. What is the body temperature in °F? °F = 1.8 (29.1°C) + 32 exact tenth's exact = 52.4 + 32 = 84.4°F tenth’s

14. LecturePLUS Timberlake14 Learning Check The normal temperature of a chickadee is 105.8°F. What is that temperature in °C? 1) 73.8 °C 2) 58.8 °C 3) 41.0 °C

15. LecturePLUS Timberlake15 Solution 3) 41.0 °C Solution: °C = (°F - 32) 1.8 =(105.8 - 32) 1.8 =73.8°F 1.8°= 41.0°C

16. LecturePLUS Timberlake16 Learning Check Pizza is baked at 455°F. What is that in °C? 1) 437 °C 2) 235°C 3) 221°C

17. LecturePLUS Timberlake17 Solution Pizza is baked at 455°F. What is that in °C? 2) 235°C (455 - 32) = 235°C 1.8

18. LecturePLUS Timberlake18 Learning Check On a cold winter day, the temperature falls to -15°C. What is that temperature in °F? 1) 19 °F 2) 59°F 3) 5°F

19. LecturePLUS Timberlake19 Solution 3) 5°F Solution: °F = 1.8(-15°C) + 32 = -27 + 32 = 5°F

20. LecturePLUS Timberlake20 Kelvin Scale On the Kelvin Scale 1K = 1°C 0 K is the lowest temperature 0 K = - 273°C K °C K = °C + 273

21. LecturePLUS Timberlake21 Learning Check What is normal body temperature of 37°C in kelvins? 1) 236 K 2) 310 K 3)342 K

22. LecturePLUS Timberlake22 Solution What is normal body temperature of 37°C in kelvins? 2) 310 K K = °C + 273 =37 °C + 273 =310. K