1 ECE3055 Computer Architecture and Operating Systems Lecture 3 MIPS ISA Prof. Hsien-Hsin Sean Lee School of Electrical and Computer Engineering Georgia.

Slides:



Advertisements
Similar presentations
Henk Corporaal TUEindhoven 2011
Advertisements

Goal: Write Programs in Assembly
Review of the MIPS Instruction Set Architecture. RISC Instruction Set Basics All operations on data apply to data in registers and typically change the.
1 ECE462/562 ISA and Datapath Review Ali Akoglu. 2 Instruction Set Architecture A very important abstraction –interface between hardware and low-level.
1 ECE369 ECE369 Chapter 2. 2 ECE369 Instruction Set Architecture A very important abstraction –interface between hardware and low-level software –standardizes.
CS1104 – Computer Organization PART 2: Computer Architecture Lecture 5 MIPS ISA & Assembly Language Programming.
Systems Architecture Lecture 5: MIPS Instruction Set
1 INSTRUCTIONS: LANGUAGE OF THE MACHINE CHAPTER 3.
Chapter 2 Instructions: Language of the Computer
Chapter 2.
MIPS ISA-I: The Instruction Set
1 Chapter 3: Instructions: Language of the Machine More primitive than higher level languages e.g., no sophisticated control flow Very restrictive e.g.,
1 Instructions: Language of the Machine More primitive than higher level languages e.g., no sophisticated control flow Very restrictive e.g., MIPS Arithmetic.
1 Chapter Introduction Language of the Machine We’ll be working with the MIPS instruction set architecture –similar to other architectures developed.
331 W02.1Spring 05 Announcements  HW1 is due on this Friday  Appendix A (on CD) is very helpful to HW1.
1 CSE SUNY New Paltz Chapter 3 Machine Language Instructions.
S. Barua – CPSC 440 CHAPTER 2 INSTRUCTIONS: LANGUAGE OF THE COMPUTER Goals – To get familiar with.
RISC Concepts, MIPS ISA and the Mini–MIPS project
Recap.
Lecture 5 Sept 14 Goals: Chapter 2 continued MIPS assembly language instruction formats translating c into MIPS - examples.
1  1998 Morgan Kaufmann Publishers Chapter 3 Text in blue is by N. Guydosh Updated 1/27/04 Instructions: Language of the Machine.
Text-book Slides Chapters 1-2 Prepared by the publisher (We have not necessarily followed the same order)
1  2004 Morgan Kaufmann Publishers Chapter 2. 2  2004 Morgan Kaufmann Publishers Instructions: Language of the Machine We’ll be working with the MIPS.
Processor Design 5Z032 Instructions: Language of the Computer Henk Corporaal Eindhoven University of Technology 2011.
©UCB CPSC 161 Lecture 5 Prof. L.N. Bhuyan
ISA-2 CSCE430/830 MIPS: Case Study of Instruction Set Architecture CSCE430/830 Computer Architecture Instructor: Hong Jiang Courtesy of Prof. Yifeng Zhu.
Computer Organization and Architecture (AT70.01) Comp. Sc. and Inf. Mgmt. Asian Institute of Technology Instructor: Dr. Sumanta Guha Slide Sources: Patterson.
Computing Systems Instructions: language of the computer.
1  2004 Morgan Kaufmann Publishers Instructions: bne $t4,$t5,Label Next instruction is at Label if $t4≠$t5 beq $t4,$t5,Label Next instruction is at Label.
순천향대학교 정보기술공학부 이 상 정 1 2. Instructions: Language of the Computer.
1 EGRE 426 Fall 09 Handout Pipeline examples continued from last class.
1 CS/EE 362 Hardware Fundamentals Lecture 10 (Chapter 3: Hennessy and Patterson) Winter Quarter 1998 Chris Myers.
1 (Based on text: David A. Patterson & John L. Hennessy, Computer Organization and Design: The Hardware/Software Interface, 3 rd Ed., Morgan Kaufmann,
1  1998 Morgan Kaufmann Publishers Machine Instructions: Language of the Machine Lowest level of programming, control directly the hardware Assembly instructions.
6.S078 - Computer Architecture: A Constructive Approach Introduction to SMIPS Li-Shiuan Peh Computer Science & Artificial Intelligence Lab. Massachusetts.
April 23, 2001Systems Architecture I1 Systems Architecture I (CS ) Lecture 9: Assemblers, Linkers, and Loaders * Jeremy R. Johnson Mon. April 23,
Computer Architecture (CS 207 D) Instruction Set Architecture ISA.
Small constants are used quite frequently (50% of operands) e.g., A = A + 5; B = B + 1; C = C - 18; Solutions? Why not? put 'typical constants' in memory.
 1998 Morgan Kaufmann Publishers MIPS arithmetic All instructions have 3 operands Operand order is fixed (destination first) Example: C code: A = B +
RISC Processor Design RISC Instruction Set Virendra Singh Indian Institute of Science Bangalore Lecture 8 SE-273: Processor Design.
Chapter 2 CSF 2009 The MIPS Assembly Language. Stored Program Computers Instructions represented in binary, just like data Instructions and data stored.
Computer Organization CS224 Fall 2012 Lessons 7 and 8.
Computer Organization Rabie A. Ramadan Lecture 3.
EE472 – Spring 2007P. Chiang, with Slide Help from C. Kozyrakis (Stanford) ECE472 Computer Architecture Lecture #3—Oct. 2, 2007 Patrick Chiang TA: Kang-Min.
MIPS Instructions Instructions: Language of the Machine
DR. SIMING LIU SPRING 2016 COMPUTER SCIENCE AND ENGINEERING UNIVERSITY OF NEVADA, RENO Session 7, 8 Instruction Set Architecture.
Instruction Set Architecture Chapter 3 – P & H. Introduction Instruction set architecture interface between programmer and CPU Good ISA makes program.
1  1998 Morgan Kaufmann Publishers Instructions: Language of the Machine More primitive than higher level languages e.g., no sophisticated control flow.
Today’s Agenda MIPS ISA Microcomputer without Interlocked Pipeline Stages !
MIPS Assembly.
ECE3055 Computer Architecture and Operating Systems Chapter 2: Procedure Calls & System Software These lecture notes are adapted from those of Professor.
ECE3055 Computer Architecture and Operating Systems MIPS ISA
RISC Concepts, MIPS ISA Logic Design Tutorial 8.
Computer Architecture (CS 207 D) Instruction Set Architecture ISA
ECE/CS 552: Instruction Sets – MIPS
Instructions - Type and Format
CS170 Computer Organization and Architecture I
Systems Architecture I (CS ) Lecture 5: MIPS Instruction Set*
Systems Architecture Lecture 5: MIPS Instruction Set
Henk Corporaal TUEindhoven 2010
ECE232: Hardware Organization and Design
Computer Architecture
September 17 Test 1 pre(re)view Fang-Yi will demonstrate Spim
COMS 361 Computer Organization
UCSD ECE 111 Prof. Farinaz Koushanfar Fall 2018
COMS 361 Computer Organization
COMS 361 Computer Organization
The Instruction Set Architecture (ISA)
Machine Instructions.
Systems Architecture I (CS ) Lecture 5: MIPS Instruction Set*
Presentation transcript:

1 ECE3055 Computer Architecture and Operating Systems Lecture 3 MIPS ISA Prof. Hsien-Hsin Sean Lee School of Electrical and Computer Engineering Georgia Institute of Technology

2 Instructions:  Language of the Machine  More primitive than higher level languages e.g., no sophisticated control flow  Very restrictive e.g., MIPS Arithmetic Instructions MIPS  We’ll be working with the MIPS instruction set architecture (some of you have done this in 2030) a representative of Reduced Instruction Set Computer (RISC) similar to other architectures developed since the 1980's used by NEC, Nintendo, Silicon Graphics, Sony Design goals Design goals: Maximize performance and Minimize cost, Reduce design time

3 MIPS arithmetic  All instructions have 3 operands  Operand order is fixed (destination first) Example: C code: A = B + C MIPS code: add $s0, $s1, $s2 (associated with variables by compiler)

4 MIPS arithmetic  Design Principle: simplicity favors regularity.  Of course this complicates some things... C code: A = B + C + D; E = F - A; MIPS code: add $t0, $s1, $s2 add $s0, $t0, $s3 sub $s4, $s5, $s0  Operands must be registers, only 32 registers provided  All memory accesses are accomplished via loads and stores A common feature of RISC processors

5 Registers vs. Memory ProcessorI/O Control Datapath Memory Input Output  Arithmetic instructions operands must be registers, — only 32 registers provided  Compiler associates variables with registers  What about programs with lots of variables

6 Memory Organization  Viewed as a large, single-dimension array, with an address.  A memory address is an index into the array  "Byte addressing" means that the index points to a byte of memory bits of data

7 Memory Organization  Bytes are nice, but most data items use larger "words“  MIPS provides lw/lh/lb and sw/sh/sb instructions  For MIPS, a word is 32 bits or 4 bytes. (Intel’s word=16 bits and double word or dword=32bits)  2 32 bytes with byte addresses from 0 to  2 30 words with byte addresses 0, 4, 8,  Words are aligned i.e., what are the least 2 significant bits of a word address? bits of data Registers hold 32 bits of data

8 Endianness [defined by Danny Cohen 1981] word  Byte ordering  How a multiple byte data word stored in memory  Endianness (from Gulliver ’ s Travels) Big Endian  Mostlowest  Most significant byte of a multi-byte word is stored at the lowest memory address  e.g. Sun Sparc, PowerPC Little Endian  Leastlowest  Least significant byte of a multi-byte word is stored at the lowest memory address  e.g. Intel x86  Some embedded & DSP processors would support both for interoperability

9 Example of Endian  Store 0x at address 0x0000, byte-addressable 0x87 0x65 0x43 0x21 Lower Memory Address Higher Memory Address 0x0000 0x0001 0x0002 0x0003 BIG ENDIAN 0x21 0x43 0x65 0x87 Lower Memory Address Higher Memory Address 0x0000 0x0001 0x0002 0x0003 LITTLE ENDIAN

10 Instructions  Load and store instructions  Example: C code: long A[100]; A[9] = h + A[8]; MIPS code: lw $t0, 32($s3) add $t0, $s2, $t0 sw $t0, 36($s3)  Store word has destination last  Remember arithmetic operands are registers, not memory! 32 bits of data A[0] A[1] A[2] 4 bytes

11 Our First Example  MIPS Software Convention $4, $5, $6, $7 are used for passing arguments swap(int v[], int k); { int temp; temp = v[k] v[k] = v[k+1]; v[k+1] = temp; } swap: muli $2, $5, 4 add $2, $4, $2 lw $15, 0($2) lw $16, 4($2) sw $16, 0($2) sw $15, 4($2) jr $31

12 So far we’ve learned:  MIPS — loading words but addressing bytes — arithmetic on registers only  InstructionMeaning add $s1, $s2, $s3$s1 = $s2 + $s3 sub $s1, $s2, $s3$s1 = $s2 – $s3 lw $s1, 100($s2)$s1 = Memory[$s2+100] sw $s1, 100($s2)Memory[$s2+100] = $s1

13 Software Conventions for MIPS Registers RegisterNamesUsage by Software Convention $0$zeroHardwired to zero $1$atReserved by assembler $2 - $3$v0 - $v1Function return result registers $4 - $7$a0 - $a3Function passing argument value registers $8 - $15$t0 - $t7Temporary registers, caller saved $16 - $23$s0 - $s7Saved registers, callee saved $24 - $25$t8 - $t9Temporary registers, caller saved $26 - $27$k0 - $k1Reserved for OS kernel $28$gpGlobal pointer $29$spStack pointer $30$fpFrame pointer $31$raReturn address (pushed by call instruction) $hi High result register (remainder/div, high word/mult) $lo Low result register (quotient/div, low word/mult)

14 Instruction Format  InstructionMeaning add $s1,$s2,$s3$s1 = $s2 + $s3 sub $s1,$s2,$s3$s1 = $s2 – $s3 lw $s1,100($s2)$s1 = Memory[$s2+100] sw $s1,100($s2)Memory[$s2+100] = $s1 bne $s4,$s5,LabelNext instr. is at Label if $s4  $s5 beq $s4,$s5,LabelNext instr. is at Label if $s4 = $s5 j LabelNext instr. is at Label  Formats: op rs rt rdshamtfunct op rs rt 16 bit address op 26 bit address RIJRIJ

15 Machine Language  Instructions, like registers and words of data, are also 32 bits long Example: add $t0, $s1, $s2 registers have numbers, $t0=9, $s1=17, $s2=18  Instruction Format: op rs rt rdshamtfunct  Can you guess what the field names stand for?

16 MIPS Encoding: R-Type 31 opcodersrtrd shamtfunct opcodersrtrd shamtfunct add $4, $3, $2 rt rs rd Encoding = 0x

17 MIPS Encoding: R-Type 31 opcodersrtrd shamtfunct sll $3, $5, 7 shamt rt rd opcodersrtrd shamtfunct Encoding = 0x000519C0

18  Consider the load-word and store-word instructions, What would the regularity principle have us do? New principle: Good design demands a compromise  Introduce a new type of instruction format I-type for data transfer instructions other format was R-type for register  Example: lw $t0, 32($s2) op rs rt 16 bit number  Where's the compromise? Machine Language

19 MIPS Encoding: I-Type 31 opcodersrtImmediate Value lw $5, 3000($2) Immediate rs rt Encoding = 0x8C450BB opcodersrt Immediate Value

20 MIPS Encoding: I-Type 31 opcodersrtImmediate Value sw $5, 3000($2) Immediate rs rt Encoding = 0xAC450BB opcodersrt Immediate Value

21  Instructions are bits  Programs are stored in memory — to be read or written just like data  Fetch & Execute Cycle Instructions are fetched and put into a special register Bits in the register "control" the subsequent actions Fetch the “next” instruction and continue ProcessorMemory memory for data, programs, compilers, editors, etc. Stored Program Concept

22  Decision making instructions alter the control flow, i.e., change the "next" instruction to be executed  MIPS conditional branch instructions: bne $t0, $t1, Label beq $t0, $t1, Label  Example: if (i==j) h = i + j; bne $s0, $s1, Label add $s3, $s0, $s1 Label:.... Control

23  MIPS unconditional branch instructions: j label  Example: if (i!=j) beq $s4, $s5, Lab1 h=i+j;add $s3, $s4, $s5 else j Lab2 h=i-j;Lab1:sub $s3, $s4, $s5 Lab2:...  Can you build a simple for loop? Control

24 BEQ/BNE uses I-Type 31 opcodersrtSigned Offset Value (encoded in words, e.g. 4-bytes) beq $0, $9, 40 Offset Encoded by 40/4 = 10 rt rs Encoding = 0x A opcodersrt Immediate Value

25 MIPS Encoding: J-Type 31 opcodeTarget Address 260 jal 0x Target Encoding = 0x0C10000C opcode Target Address X Instruction=4 bytes Target Address jal will jump and push return address in $ra ($31) Use “jr $31” to return

26 JALR and JR uses R-Type  JALR (Jump And Link Register) and JR (Jump Register) Considered as R-type Unconditional jump JALR used for procedural call opcoders0 rd (default=31) funct jalr r2 Or jalr r31, r2 jr r opcoders funct 0

27  We have: beq, bne, what about Branch-if-less-than?  New instruction: if $s1 < $s2 then $t0 = 1 slt $t0, $s1, $s2 else $t0 = 0  Can use this instruction to build " blt $s1, $s2, Label " — can now build general control structures  For ease of assembly programmers, the assembler allows “blt” as a “pseudo-instruction” — assembler substitutes them with valid MIPS instructions — there are policy of use conventions for registers blt $4 $5 loop  slt $1 $4 $5 bne $1 $0 loop 2 Control Flow

28  Small constants are used quite frequently (50% of operands) e.g., A = A + 5; B = B + 1; C = C - 18;  Solutions? Why not? put 'typical constants' in memory and load them. create hard-wired registers (like $zero) for constants like one. Use immediate values  MIPS Instructions: addi $29, $29, 4 slti $8, $18, 10 andi $29, $29, 6 ori $29, $29, 4 3 Constants

29  We'd like to be able to load a 32 bit constant into a register  Must use two instructions, new "load upper immediate" instruction lui $t0,  Then must get the lower order bits right, i.e., ori $t0, $t0, ori filled with zeros How about larger constants?

30 Input/Output  Place proper arguments (e.g. system call code) to corresponding registers and place a ‘syscall’  Print string  li $v0, 4  la $a0, var  syscall  Print integer  li $v0, 1  add $a0, $t0, $0  syscall  Read integer  li $v0, 5 # result in $v0  Syscall  See Appendix A for more.

31  Assembly provides convenient symbolic representation much easier than writing down numbers e.g., destination first  Machine language is the underlying reality e.g., destination is no longer first  Assembly can provide 'pseudoinstructions' e.g., “move $t0, $t1” exists only in Assembly would be implemented using “add $t0,$t1,$zero”  When considering performance you should count real instructions Assembly Language vs. Machine Language

32  Things we are not going to cover support for procedures linkers, loaders, memory layout stacks, frames, recursion manipulating strings and pointers interrupts and exceptions system calls and conventions  Some of these we'll talk about later  We've focused on architectural issues basics of MIPS assembly language and machine code we’ll build a processor to execute these instructions. Other Issues

33  simple instructions all 32 bits wide  very structured  only three instruction formats  rely on compiler to achieve performance — what are the compiler's goals?  help compiler where we can op rs rt rdshamtfunct op rs rt 16 bit address op 26 bit address RIJRIJ Summary of MIPS

34  Instructions: bne $t4,$t5,Label Next instruction is at Label if $t4  $t5 beq $t4,$t5,Label Next instruction is at Label if $t4 = $t5 j Label Next instruction is at Label  Formats:  Addresses are not 32 bits — How do we handle this with load and store instructions? op rs rt 16 bit address op 26 bit address IJIJ Addresses in Branches and Jumps

35  Instructions: bne $t4,$t5,Label Next instruction is at Label if $t4  $t5 beq $t4,$t5,Label Next instruction is at Label if $t4=$t5  Formats:  Could specify a register (like lw and sw) and add it to address use Instruction Address Register (PC = program counter) most branches are local (principle of locality)  Jump instructions just use high order bits of PC address boundaries of 256 MB op rs rt 16 bit address I Addresses in Branches

36 To Summarize

37 Addressing Mode Operand is constant Operand is in register lb $t0, 48($s0) bne $4, $5, Label (label will be assembled into a distance) j Label Concatenation w/ PC[31..28]

38 Supplementary Materials

39  Design alternative: provide more powerful operations goal is to reduce number of instructions executed danger is a slower cycle time and/or a higher CPI  Sometimes referred to as “RISC vs. CISC” virtually all new instruction sets since 1982 have been RISC VAX: minimize code size, make assembly language easy instructions from 1 to 54 bytes long!  We’ll look at PowerPC and 80x86 Alternative Architectures

40 PowerPC  Indexed addressing example: lw $t1,$a0+$s3 #$t1=Memory[$a0+$s3] What do we have to do in MIPS?  Update addressing update a register as part of load (for marching through arrays) example: lwu $t0,4($s3) #$t0=Memory[$s3+4];$s3=$s3+4 What do we have to do in MIPS?  Others: load multiple/store multiple a special counter register “ bc Loop ” decrement counter, if not 0 goto loop

41 80x86  1978: The Intel 8086 is announced (16 bit architecture)  1980: The 8087 floating point coprocessor is added  1982: The increases address space to 24 bits, +instructions  1985: The extends to 32 bits, new addressing modes  : The 80486, Pentium, Pentium Pro add a few instructions (mostly designed for higher performance)  1997: MMX (SIMD-INT) is added (PPMT and P-II)  1999: SSE (single prec. SIMD-FP and cacheability instructions) is added in P-III  2001: SSE2 (double prec. SIMD-FP) is added in P4  2004: Nocona introduced (compatible with AMD64 or once called x86-64) “This history illustrates the impact of the “golden handcuffs” of compatibility “adding new features as someone might add clothing to a packed bag” “an architecture that is difficult to explain and impossible to love”

42 A Dominant Architecture: 80x86  See your textbook for a more detailed description  Complexity: Instructions from 1 to 17 bytes long one operand must act as both a source and destination one operand can come from memory complex addressing modes e.g., “base or scaled index with 8 or 32 bit displacement”  Saving grace: the most frequently used instructions are not too difficult to build compilers avoid the portions of the architecture that are slow “what the 80x86 lacks in style is made up in quantity, making it beautiful from the right perspective”

43  Instruction complexity is only one variable lower instruction count vs. higher CPI / lower clock rate  Design Principles: simplicity favors regularity smaller is faster good design demands compromise make the common case fast  Instruction set architecture a very important abstraction indeed! Summary