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Chapters 2 and 3 Review Worksheet
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Problem 1: First find the volume: V = ℓ w h V = (3.54 yd)(6.39 yd)(11.8 yd) V = 267 yd 3
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Problem 1 (continued): Convert the answer (267 yd 3 ) to nm 3 10 27 nm 3 1m3m3 1m3m3 1.3079yd 3 267yd 3 = 2.04 x 10 29 nm 3
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Problem 2: Convert 9.04 x 10 8 in 3 to Tm 3 Tm 3 1 10 42 cm 3 9.04 x 10 8 1 cm 3 in 3 16.4 in 3 = 1.48 x 10 48 Tm 3
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Problem 3: Convert 947,200 m 3 to mi 3 1mi 3 1.47 x 10 11 ft 3 1 1728 in 3 1 = 2.274 x 10 22 mi 3 cm 3 16.4 1cm 3 m3m3 10 12 947,200 m3m3
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Problem 4: D = m/V D = (5.36 kg)/(640 mL) D = 0.0084 kg/mL
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Problem 5: First convert 453 hm 3 to mL mL1 1cm 3 453 1 cm 3 hm 3 10 12 hm 3 = 4.53 x 10 14 mL then....................
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Problem 5: (continued) Now find the volume: D = m/V so M=D V M = (0.537 g/mL) (4.53 x 10 14 mL) M = 2.43 x 10 14 g
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Problem 6: 1 calorie = 4.184 J 4.184J 1cal 135cal = 565 J Problem 7:
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Problem 8: cal1 4.184J 1.94 x 10 14 1 J MJ 10 6 MJ = 4.64 x 10 9 cal
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Problem 9: Kelvin = Celsius + 273 Kelvin = 43 + 273 Kelvin = 230 K
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Problem 10: Kelvin = Celsius + 273 293 K = Celsius + 273 293 K 273 = Celsius 20 C = Celsius
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Problem 11: (i) chemical change (ii) chemical property (iii) physical change (iv) physical property
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12. During electrolysis, an electric current is passed through a substance. If the substance is a compound, it may be broken down into the separate elements that form it. 13. filtration 14. distillation, crystallization, and chromatography 15. kinetic, radiant, and potential
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16. solid, liquid, gas, and plasma 17. chemical, electrical, and gravitational 18. Dalton, schoolteacher 19. Democritus, philosopher 20. scanning tunneling microscope 21. Faraday, chemist
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22. “elektron” is the Greek word for amber (fossilized tree sap which when rubbed with cloth would attract dust and other particles – static electricity) 23. Ben Franklin, He flew a kite with a key on its string during a thunderstorm. 24. J.J. Thomson, physicist, He discovered electrons.
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25. Henri Becquerel, physicist 26. Ernest Rutherford, scientist, He discovered the nucleus (positively charged) 27. The plum-pudding model states that negative charges are distributed evenly throughout an atom’s positively-charged interior. Rutherford found that the positive charges were centrally located in a core.
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28. number of protons = atomic number 29. mass number = protons + neutrons 30. Average atomic mass is a weighted average of all of the isotopes of an element. Multiply the abundance percentage by the mass number for all the isotopes and add them together.
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Problem 31: (i) 194 Os +4 P = 76, N = 118, E = 72 (ii) 116 In +3 P = 49, N = 67, E = 46 (iii) 129 Te 2 P = 52, N = 77, E = 54 (iv) 227 Ra P = 88, N = 139, E = 88
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Problem 32: (i) 97 Mo +6 (ii) 33 P 3 (iii) 244 Pu +5
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Problem 33: Average Atomic Mass = 51(.9975) + 50(.0025) Average Atomic Mass = 50.9975
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Problem 34: Average Atomic Mass = 90(.5145) 91(.1122) 92(.1715) 94(.1738) 96(.0280) Average Atomic Mass = 91.3184 +______________
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Problem 35: Ga-69 Ga-71 Abundance = x 69x + 71(1 x) = 69.72 Abundance = 1 x 69x + 71 71x = 69.72 2x = 1.28 x = 0.64 Ga-69 = 64% Ga-71 = 36%
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Problem 36: K-39 K-41 Abundance = x 39x + 41(1 x) = 39.0983 Abundance = 1 x 39x + 41 41x = 39.0983 2x = 1.9017 x =.95085 K-39 = 95.085% K-41 = 4.915%
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37. 217 Rn 4 2 He + 213 Po 38. 138 Cs 0 –1 e + 138 Ba 39. 17 F 0 1 e + 17 O 40. 7 Be + 0 –1 e 7 Li 41. 212 At 4 2 He + 208 Bi 42. 117 Ag 0 –1 e + 117 Cd
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43. Ba yellow-green 44. Co not visible 45. K violet 46. Cu turquoise-green 47. Na yellow 48. Sr red49. Ca orange-red
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