Presentation on theme: "1 Chapter 5 Data representation. 2 Learning outcomes By the end of this Chapter you will be able to: Explain how integers are represented in computers."— Presentation transcript:
1 Chapter 5 Data representation
2 Learning outcomes By the end of this Chapter you will be able to: Explain how integers are represented in computers using: Unsigned, signed magnitude, excess, and twos complement notations Explain how fractional numbers are represented in computers Floating point notation (IEEE 754 single format) Calculate the decimal value represented by a binary sequence in: Unsigned, signed notation, excess, twos complement, and the IEEE 754 notations. Explain how characters are represented in computers E.g. using ASCII and Unicode Explain how colours, images, sound and movies are represented
4 Introduction In Chapter 3 How information is stored in the main memory, magnetic memory, and optical memory In Chapter 4: We studied how information is processed in computers How the CPU executes instructions In Chapter 5 We will be looking at how data is represented in computers Integer and fractional number representation Characters, colours and sounds representation
5 Binary numbers Binary number is simply a number comprised of only 0's and 1's. Computers use binary numbers because it's easy for them to communicate using electrical current -- 0 is off, 1 is on. You can express any base 10 (our number system -- where each digit is between 0 and 9) with binary numbers. The need to translate decimal number to binary and binary to decimal. There are many ways in representing decimal number in binary numbers. (later)
6 How does the binary system work? It is just like any other system In decimal system the base is 10 We have 10 possible values 0-9 In binary system the base is 2 We have only two possible values 0 or 1. The same as in any base, 0 digit has non contribution, where 1s has contribution which depends at there position.
7 Example = = 3* * * = =1*2 4 +1*2 2 +1*2 0
8 Examples: decimal -- binary Find the binary representation of Find the decimal value represented by the following binary representations:
9 Examples: Representing fractional numbers Find the binary representations of: = = 0.11 Using only 8 binary digits find the binary representations of:
10 Number representation Representing whole numbers Representing fractional numbers
12 Unsigned Representation Represents positive integers. Unsigned representation of 157: Addition is simple: = position Bit pattern contribution
13 Advantages and disadvantages of unsigned notation Advantages: One representation of zero Simple addition Disadvantages Negative numbers can not be represented. The need of different notation to represent negative numbers.
14 Representation of negative numbers Is a representation of negative numbers possible? Unfortunately: you can not just stick a negative sign in front of a binary number. (it does not work like that) There are three methods used to represent negative numbers. Signed magnitude notation Excess notation notation Twos complement notation
15 Signed Magnitude Representation Unsigned: - and + are the same. In signed magnitude the left-most bit represents the sign of the integer. 0 for positive numbers. 1 for negative numbers. The remaining bits represent to magnitude of the numbers.
16 Example Suppose is a signed magnitude representation. The sign bit is 1, then the number represented is negative The magnitude is with a value = 29 Then the number represented by is –29. position Bit pattern contribution
17 Exercise has in signed magnitude notation. Find the signed magnitude of –37 10 ? 2. Using the signed magnitude notation find the 8-bit binary representation of the decimal value and Find the signed magnitude of –63 using 8-bit binary sequence?
18 Disadvantage of Signed Magnitude Addition and subtractions are difficult. Signs and magnitude, both have to carry out the required operation. They are two representations of = = To test if a number is 0 or not, the CPU will need to see whether it is or is always performed in programs. Therefore, having two representations of 0 is inconvenient.
19 Signed-Summary In signed magnitude notation, The most significant bit is used to represent the sign. 1 represents negative numbers 0 represents positive numbers. The unsigned value of the remaining bits represent The magnitude. Advantages: Represents positive and negative numbers Disadvantages: two representations of zero, Arithmetic operations are difficult.
20 Excess Notation In excess notation: The value represented is the unsigned value with a fixed value subtracted from it. For n-bit binary sequences the value subtracted fixed value is 2 (n-1). Most significant bit: 0 for negative numbers 1 for positive numbers
21 Excess Notation with n bits 1000…0 represent 2 n-1 is the decimal value in unsigned notation. Therefore, in excess notation: 1000…0 will represent 0. Decimal value In unsigned notation Decimal value In excess notation - 2 n-1 =
22 Example (1) - excess to decimal Find the decimal number represented by in excess notation. Unsigned value = = = Excess value: excess value = 153 – 2 7 = 152 – 128 = 25.
23 Example (2) - decimal to excess Represent the decimal value 24 in 8-bit excess notation. We first add, 2 8-1, the fixed value = = 152 then, find the unsigned value of = (unsigned notation) = (excess notation)
24 example (3) Represent the decimal value -24 in 8-bit excess notation. We first add, 2 8-1, the fixed value = = 104 then, find the unsigned value of = (unsigned notation) = (excess notation)
25 Example (4) (10101) Unsigned = = The value represented in unsigned notation is 21 Sign Magnitude The sign bit is 1, so the sign is negative The magnitude is the unsigned value = 5 10 So the value represented in signed magnitude is Excess notation As an unsigned binary integer = subtracting = 2 4 = 16, we get = So the value represented in excess notation is 5 10.
26 Advantages of Excess Notation It can represent positive and negative integers. There is only one representation for 0. It is easy to compare two numbers. When comparing the bits can be treated as unsigned integers. Excess notation is not normally used to represent integers. It is mainly used in floating point representation for representing fractions (later floating point rep.).
27 Exercise 2 1. Find is an 8-bit binary sequence. Find the decimal value it represents if it was in unsigned and signed magnitude. Suppose this representation is excess notation, find the decimal value it represents? 2. Using 8-bit binary sequence notation, find the unsigned, signed magnitude and excess notation of the decimal value ?
28 Excess notation - Summary In excess notation, the value represented is the unsigned value with a fixed value subtracted from it. i.e. for n-bit binary sequences the value subtracted is 2 (n-1). Most significant bit: 0 for negative numbers. 1 positive numbers. Advantages: Only one representation of zero. Easy for comparison.
29 Twos Complement Notation The most used representation for integers. All positive numbers begin with 0. All negative numbers begin with 1. One representation of zero i.e. 0 is represented as 0000 using 4-bit binary sequence.
30 Twos Complement Notation with 4-bits Binary pattern Value in 2s complement
31 Properties of Twos Complement Notation Positive numbers begin with 0 Negative numbers begin with 1 Only one representation of 0, i.e Relationship between +n and –n
32 Advantages of Twos Complement Notation It is easy to add two numbers Subtraction can be easily performed. Multiplication is just a repeated addition. Division is just a repeated subtraction Twos complement is widely used in ALU
33 Evaluating numbers in twos complement notation Sign bit = 0, the number is positive. The value is determined in the usual way. Sign bit = 1, the number is negative. three methods can be used: Method 1decimal value of (n-1) bits, then subtract 2 n-1 Method 2- 2 n-1 is the contribution of the sign bit. Method 3 Binary rep. of the corresponding positive number. Let V be its decimal value. - V is the required value.
34 Example in Twos Complement The most significant bit is 1, hence it is a negative number. Method = +5 (+5 – = 5 – 2 4 = 5-16 = -11) Method = -11 Method 3 Corresponding + number is = = 11 the result is then –11.
35 Twos complement-summary In twos complement the most significant for an n-bit number has a contribution of –2 (n-1). One representation of zero All arithmetic operations can be performed by using addition and inversion. The most significant bit: 0 for positive and 1 for negative. Three methods can the decimal value of a negative number: Method 1decimal value of (n-1) bits, then subtract 2 n-1 Method 2- 2 n-1 is the contribution of the sign bit. Method 3 Binary rep. of the corresponding positive number. Let V be its decimal value. - V is the required value.
36 Exercise Determine the decimal value represented by in each of the following four systems. 1. Unsigned notation? 2. Signed magnitude notation? 3. Excess notation? 4. Tows complements?
37 Fraction Representation To represent fraction we need other representations: Fixed point representation Floating point representation.
38 Fixed-Point Representation old position New position Bit pattern Contribution = Radix-point
39 Limitation of Fixed-Point Representation To represent large numbers or very small numbers we need a very long sequences of bits. This is because we have to give bits to both the integer part and the fraction part.
40 Floating Point Representation In decimal notation we can get around this problem using scientific notation or floating point notation. NumberScientific notationFloating-point notation 1,245,000,000,
41 Floating Point could be represented as * * A calculator might display 159 E * SignExponent Base Mantissa
42 M B E Sign mantissa or base exponent significand Floating point format SignExponentMantissa
43 Floating Point Representation format The exponent is biased by a fixed value b, called the bias. The mantissa should be normalised, e.g. if the real mantissa if of the form 1.f then the normalised mantissa should be f, where f is a binary sequence. SignExponentMantissa
44 IEEE 745 Single Precision The number will occupy 32 bits The first bit represents the sign of the number; 1= negative 0= positive. The next 8 bits will specify the exponent stored in biased 127 form. The remaining 23 bits will carry the mantissa normalised to be between 1 and 2. i.e. 1<= mantissa < 2
45 Representation in IEEE 754 single precision sign bit: 0 for positive and, 1 for negative numbers 8 biased exponent by bit normalised mantissa SignExponentMantissa
46 Basic Conversion Converting a decimal number to a floating point number. 1.Take the integer part of the number and generate the binary equivalent. 2.Take the fractional part and generate a binary fraction 3.Then place the two parts together and normalise.
47 IEEE – Example 1 Convert 6.75 to 32 bit IEEE format. 1. The Mantissa. The Integer first. 6 / 2 = 3 r 0 3 / 2= 1 r 1 1 / 2= 0 r 1 2. Fraction next..75 * 2 = * 2 = put the two parts together… Now normalise * 2 2 = =
48 = IEEE – Example 1 Convert 6.75 to 32 bit IEEE format. 1. The Mantissa. The Integer first. 6 / 2 = 3 r 0 3 / 2= 1 r 1 1 / 2= 0 r 1 2. Fraction next..75 * 2 = * 2 = put the two parts together… Now normalise * 2 2 = 110 2
49 IEEE – Example 1 Convert 6.75 to 32 bit IEEE format. 1. The Mantissa. The Integer first. 6 / 2 = 3 r 0 3 / 2= 1 r 1 1 / 2= 0 r 1 2. Fraction next..75 * 2 = * 2 = put the two parts together… Now normalise * 2 2 = =
50 IEEE Biased 127 Exponent To generate a biased 127 exponent Take the value of the signed exponent and add 127. Example then = and my value for the exponent would be 143 = So it is simply now an unsigned value....
51 Possible Representations of an Exponent
52 Why Biased ? The smallest exponent Only one exponent zero The highest exponent is To increase the exponent by one simply add 1 to the present pattern.
53 Back to the example Our original example revisited… * 2 2 Exponent is =129 or in binary. NOTE: Mantissa always ends up with a value of 1 before the Dot. This is a waste of storage therefore it is implied but not actually stored is stored in 32 bit floating point IEEE representation: sign(1) exponent(8) mantissa(23 )
54 Representation in IEEE 754 single precision sign bit: 0 for positive and, 1 for negative numbers 8 biased exponent by bit normalised mantissa SignExponentMantissa
55 Example (2) which number does the following IEEE single precision notation represent? The sign bit is 1, hence it is a negative number. The exponent is = It is biased by 127, hence the real exponent is 128 –127 = 1. The mantissa: It is normalised, hence the true mantissa is 1.01 = Finally, the number represented is: x 2 1 =
56 Single Precision Format The exponent is formatted using excess-127 notation, with an implied base of 2 Example: Exponent: Representation: 135 – 127 = 8 The stored values 0 and 255 of the exponent are used to indicate special values, the exponential range is restricted to to The number 0.0 is defined by a mantissa of 0 together with the special exponential value 0 The standard allows also values +/- (represented as mantissa +/-0 and exponent 255 Allows various other special conditions
57 In comparison The smallest and largest possible 32-bit integers in twos complement are only and PITT CS
58 Range of numbers Normalized (positive range; negative is symmetric) × (1+0) = × ( ) smallest largest ( ) Positive underflow Positive overflow PITT CS
59 Representation in IEEE 754 double precision format It uses 64 bits 1 bit sign 11 bit biased exponent 52 bit mantissa SignExponentMantissa
60 IEEE 754 double precision Biased = bit exponent with an excess of For example: If the exponent is -1 we then add 1023 to it = 1022 We then find the binary representation of 1022 Which is The exponent field will now hold This means that we just represent -1 with an excess of 1023.
61 IEEE 754 Encoding Single PrecisionDouble PrecisionRepresented Object ExponentFractionExponentFraction non-zero0 +/- denormalized number 1~254anything1~2046anything +/- floating-point numbers /- infinity 255non-zero2047non-zeroNaN (Not a Number)
62 Floating Point Representation format (summary) the sign bit represents the sign 0 for positive numbers 1 for negative numbers The exponent is biased by a fixed value b, called the bias. The mantissa should be normalised, e.g. if the real mantissa if of the form 1.f then the normalised mantissa should be f, where f is a binary sequence. SignExponentMantissa
63 Character representation- ASCII ASCII (American Standard Code for Information Interchange) It is the scheme used to represent characters. Each character is represented using 7-bit binary code. If 8-bits are used, the first bit is always set to 0 See (table 5.1 p56, study guide) for character representation in ASCII.
64 ASCII – example Symbol decimal Binary : ; < = > ? A B C
65 Character strings How to represent character strings? A collection of adjacent words (bit-string units) can store a sequence of letters Notation: enclose strings in double quotes "Hello world" Representation convention: null character defines end of string Null is sometimes written as '\0' Its binary representation is the number 0 'H' 'e' 'l' 'l' o' ' ' 'W' 'o' 'r' 'l' 'd' '\0'
66 Layered View of Representation Text string Sequence of characters Character Bit string Information Data Information Data Information Data Information Data
67 Working With A Layered View of Representation Represent SI at the two layers shown on the previous slide. Representation schemes: Top layer - Character string to character sequence: Write each letter separately, enclosed in quotes. End string with \0. Bottom layer - Character to bit-string: Represent a character using the binary equivalent according to the ASCII table provided.
68 Solution SI S I \ The colors are intended to help you read it; computers dont care that all the bits run together.
69 exercise Use the ASCII table to write the ASCII code for the following: CIS110 6=2*3
70 Unicode - representation ASCII code can represent only 128 = 2 7 characters. It only represents the English Alphabet plus some control characters. Unicode is designed to represent the worldwide interchange. It uses 16 bits and can represents 32,768 characters. For compatibility, the first 128 Unicode are the same as the one of the ASCII.
71 Colour representation Colours can represented using a sequence of bits. 256 colours – how many bits? Hint for calculating To figure out how many bits are needed to represent a range of values, figure out the smallest power of 2 that is equal to or bigger than the size of the range. That is, find x for 2 x => bit colour – how many possible colors can be represented? Hints 16 million possible colours (why 16 millions?)
72 24-bits -- the True colour 24-bit color is often referred to as the true colour. Any real-life shade, detected by the naked eye, will be among the 16 million possible colours.
74 Image representation An image can be divided into many tiny squares, called pixels. Each pixel has a particular colour. The quality of the picture depends on two factors: the density of pixels. The length of the word representing colours. The resolution of an image is the density of pixels. The higher the resolution the more information information the image contains.
75 Bitmap Images Each individual pixel (pi(x)cture element) in a graphic stored as a binary number Pixel: A small area with associated coordinate location Example: each point below is represented by a 4-bit code corresponding to 1 of 16 shades of gray
76 Representing Sound Graphically X axis: time Y axis: pressure A: amplitude (volume) : wavelength (inverse of frequency = 1/ )
77 Sampling Sampling is a method used to digitise sound waves. A sample is the measurement of the amplitude at a point in time. The quality of the sound depends on: The sampling rate, the faster the better The size of the word used to represent a sample.
78 Digitizing Sound Zoomed Low Frequency Signal Capture amplitude at these points Lose all variation between data points
79 Summary Integer representation Unsigned, Signed, Excess notation, and Twos complement. Fraction representation Floating point (IEEE 754 format ) Single and double precision Character representation Colour representation Sound representation
80 Exercise 1. Represent +0.8 in the following floating-point representation: 1-bit sign 4-bit exponent 6-bit normalised mantissa (significand). 2. Convert the value represented back to decimal. 3. Calculate the relative error of the representation.