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Chapter 7: Chemical Nomenclature

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1 Chapter 7: Chemical Nomenclature
OBJECTIVES Name compounds given a formula Write formulas given a name Calculate moles, mass, and particles (CH 3) Find oxidation states of atoms Calculate molecular and empirical formulas Determine percent composition of a substance Calculate solution concentration (molarity)

2 A. The Formula What’s in a name? Well, way more than you think IUPAC
_________ Systematic rules for naming Ionic and Covalent molecules governed by this organization. International Union of Pure and Applied Chemists. C8H18 Al2(SO4)3

3 A. The Formula C H C8H18 SO4 S O SO4 Al2(SO4)3 Al Al SO4

4 B. Naming – Ionic Compounds
cation followed by anion Formulas have a system:___________________ What are cations? What are anions? + charged; usually metals - charged; usually nonmetals How do you name cations? Easy: name of the metal (or other element) Al+3 = C+4 = Aluminum cation Carbon cation

5 B. Naming - Ionic Compounds
How do you name anions? Drop last syllable (or 2) and add ‘-ide’ suffix Anion Name F- Cl- O-2 S-2 N-3 P-3 Fluoride Chloride Oxide Sulfide Nitride Phosphide

6 B. Naming - Ionic Compounds
NaCl SrF2 Al2O3 Li3N sodium chloride Na Cl strontium fluoride F Sr Al O aluminum oxide Li N lithium nitride

7 B. Naming - Ionic Compounds
Formula Writing – Rubidium sulfide 1. Write symbols Rb S Rb S +1 -2 2. Write valence above 3. Ignore signs, criss-cross 1 2 Rb S 4. Ignore 1’s and reduce charge should = 0 Rb2S Rb S 2Rb = +2; S = -2

8 B. Naming - Ionic Compounds
FORMULAS rubidium selenide cesium sulfide radium silicide

9 C. Naming – Polyatomic Ions
Some groups of atoms occur so often, they are named. -1 +1 NH4 C2H3O2 orCH3COO CN HCO3 OH NO3 NO2 PO4 Ammonium Acetate Cyanide Bicarbonate Hydroxide Nitrate Nitrite Phosphate ClO3 ClO2 ClO ClO4 MnO4 CrO4 CO3 SO4 SO3 Chlorate Chlorite Hypochlorite Perchlorate Permanganate Chromate Carbonate Sulfate Sulfite -1 -1 -1 -1 -1 -1 -1 -1 -1 -2 -1 -2 -1 -2 -2 -3

10 C. Naming – Polyatomic Ions
Rb2SO4 Rubidium Sulfate H2CO3 Hydrogen Carbonate (AKA carbonic acid) Calcium Cyanide Ammonium Hydroxide

11 D. Naming – Transition metals, tin and lead
These elements have more than 1 valence. We name them using the STOCK SYSTEM. Use roman numerals to give the charge of the metal. +2 -2 Cu SO4 Copper (II) sulfate Cu SO4 +1 -2 Cu2 SO4 Copper (I) sulfate Cu SO4 Tells you the charge Two Exceptions: Zn = +2 Ag =+1

12 D. Naming – Transition metals, tin and lead
Pb(NO3)2 Sn(SO3)2 lead (III) nitrate

13 E. Naming covalent compounds
What is a covalent compound? Ionic Covalent Covalent compounds are made of non metals with no polyatomic ions! (NH4)2S H2O TiCl4 NO PtSi P4O10 MgBr2 Cl2F2 Na2SO3 N2O6 What’s the diff?

14 D. Naming covalent compounds
Covalent compounds use a prefix system: Mono Di Tri Tetra Penta Hexa Hepta Octa Nona Deca 1 – used only for Oxygen when it’s last 2 3 4 5 6 7 8 9 10

15 E. Naming covalent Compounds
dinitrogen monoxide N2O oxygen trifluoride OF3 N2O4 dinitrogen tetroxide NOT TETRAOXIDE

16 F. Common Names HCl HNO3 H2SO4 HCH3COO NH3 NaHCO3 CaCO3 NaClO NaOH
Formula Common Name IUPAC Name HCl HNO3 H2SO4 HCH3COO NH3 NaHCO3 CaCO3 NaClO NaOH SiO2 Hydrochloric acid Nitric Acid Battery Acid Sulfuric Acid Vinegar Acetic Acid Ammonia Azane Sodium bicarbonate Baking soda Chalk Calcium carbonate Bleach Sodium hypochlorite Lye/Caustic Soda Sodium hydroxide Sand/Quartz Silicon dioxide

17 G. Percent Composition the percentage by mass of each element in a compound

18 28 g 36 g %Fe =  100 = 78% Fe 8.0 g 36 g %O =  100 = 22% O
G. Percent Composition Find the percentage composition of a sample that is 28 g Fe and 8.0 g O. 28 g 36 g %Fe =  100 = 78% Fe 8.0 g 36 g %O =  100 = 22% O

19 G. Percent Composition Find the % composition of Cu2S. g Cu g Cu2S %Cu =  100 = 79.852% Cu 32.07 g S g Cu2S %S =  100 = 20.15% S

20 C2H6 CH3 H. Empirical Formula
Smallest whole number ratio of atoms in a compound C2H6 reduce subscripts CH3

21 1. If % given, assume you have 100g and the percents become masses.
H. Empirical Formula 1. If % given, assume you have 100g and the percents become masses. 2. Find moles of each element. 3. Divide moles by the smallest # to find subscripts. 4. When necessary, multiply subscripts by 2, 3, or 4 to get whole #’s.

22 Find the empirical formula for a sample of 25.9% N and 74.1% O.
H. Empirical Formula Find the empirical formula for a sample of 25.9% N and 74.1% O. Assume 100g; therefore: 25.9 g N and 74.1 g O 2. Convert to moles: 1 mol 25.9 g = 1.85 mol N 14.01 g 1 mol 74.1 g = 4.63 mol O 16.00 g

23 N1O2.5 N2O5 H. Empirical Formula
Find the empirical formula for a sample of 25.9% N and 74.1% O. 3. Divide by lowest number of moles: 1.85 mol N 4.63 mol O = 1 N = 2.5 O 1.85 mol 1.85 mol N1O2.5 4. Multiply to get whole numbers (by 2 here) N2O5

24 H. Empirical Formula Find the empirical formula of a compound if a sample is 3.65 g sodium, 2.54 g sulfur, and 3.81 g oxygen.

25 CH3 C2H6 I. Molecular Formula
“True Formula” - the actual number of atoms in a compound CH3 empirical formula ? C2H6 molecular formula

26 (CH2)2  C2H4 empirical mass = 14.03 g/mol 28.1 g/mol 14.03 g/mol
I. Molecular Formula The empirical formula for ethylene is CH2. Find the molecular formula if the molecular mass is g/mol? empirical mass = g/mol 28.1 g/mol 14.03 g/mol = 2.00 (CH2)2  C2H4

27 I. Molecular Formula 1. Find the empirical formula. 2. Find the empirical formula mass. 3. Divide the molecular mass by the empirical mass. 4. Multiply each subscript by the answer from step 3.

28 J. Molarity _________ Moles of solute dissolved in MOLARITY
Liters of solvent (concentration) MOLARITY n = number of moles L = number of Liters 𝑀= 𝑛 𝐿 Unit is the MOLAR How many moles of sodium fluoride are needed to make 400 ml of a 1.5 M solution    What is the molarity of 35 g of calcium phosphate when dissolved in 800 ml of water?


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