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Application Equipment and Calibration G. S. Manual - Chap. 7 Workbook - pp. 22-26 Application Calibration & Calculations 1998-99.

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Presentation on theme: "Application Equipment and Calibration G. S. Manual - Chap. 7 Workbook - pp. 22-26 Application Calibration & Calculations 1998-99."— Presentation transcript:

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2 Application Equipment and Calibration G. S. Manual - Chap. 7 Workbook - pp. 22-26 Application Calibration & Calculations 1998-99

3 Application Equipment and Calibration Calibrating The Sprayer: Selecting Nozzle Size Variables 1. Nozzle flow rate (GPM) 2. Ground speed (MPH) 3. Effective sprayed width (W)-inches 4. Application rate (GPA)

4 Application Equipment and Calibration Measuring Ground Speed Where 1 MPH = traveling 88 feet in 60 seconds

5 Application Equipment and Calibration Application Rate Equation Equation # 1 Calculates for application rate Represents total amount applied for an acre Calculates for application rate Represents total amount applied for an acre

6 Application Equipment and Calibration Flow Rate Equation Equation # 2 Calculates for amount of flow from one nozzle Represents the size of nozzle to put on the sprayer Calculates for amount of flow from one nozzle Represents the size of nozzle to put on the sprayer

7 Application Equipment and Calibration Where: gallons per acre gallons per minute miles per hour GPA = ______________________ GPM = ______________________ MPH = ______________________ W = ______________________ nozzle spacing - inches 5940 = a constant to convert gallons per minute, miles per hour, and inches to gallons per acre 5940 = a constant to convert gallons per minute, miles per hour, and inches to gallons per acre

8 Application Equipment and Calibration Affect of variables on rate: Pressure How would the listed variables be adjusted to double the flow in gallons per minute from a spray nozzle or to double the application rate in gallons per acre? Decrease by 1/2 (GPA) Nozzle spacing Increase 4 times (GPM) Travel speed Decrease by 1/2 (GPA)

9 Application Equipment and Calibration 1. Select application rate from the label 2. Select an appropriate ground speed 3. Determine effective sprayed width 4. Determine the flow rate required 5. Select nozzle that will give the required flow rate 6. Convert flow rate from GPM to OPM 7. Collect the output from one or all nozzles 8. Determine the amount of pesticide needed - label 9. Operate the sprayer at speed from step 2 10. Check flow frequently- compare all nozzles Calibration Steps:

10 Application Equipment and Calibration Calculations GPA= 5940 #$!@&%!

11 Application Equipment and Calibration 4. Determining MPH Example #1: A sprayer takes 22 seconds for the first pass and 24 seconds for the return pass to travel a measured course of 200 feet, what is the speed in MPH? 2224 200 23 5.9

12 Application Equipment and Calibration 5. GPA Example #2: Your sprayer is set up with flat fan nozzles spaced at 20-inches and have a measured flow rate of.51 gpm at 35 psi. What would be the application rate when using these nozzles at 35 psi traveling 7 MPH? Which equation should you use? To calculate for application rate or flow rate? Application Rate

13 Application Equipment and Calibration GPA Example Solution: GPA=? GPM=? MPH=? W=? GPA=? GPM=.51 MPH=7 W=20

14 Application Equipment and Calibration GPA Example Solution: Answer 21.6

15 Application Equipment and Calibration 6. GPM Example #3: You want to broadcast a soil applied herbicide at 15 GPA traveling 7 MPH using flooding nozzles on 40-inch spacing. Which equation should you use? To calculate for application rate or flow rate? Flow Rate

16 Application Equipment and Calibration GPA Example Solution: GPM=? GPA=? MPH=? W=? GPM=? GPA=15 MPH=7 W=40

17 Application Equipment and Calibration GPM Example Solution: Answer.71

18 Application Equipment and Calibration Convert to OPM: OPM = GPM x 128 = OPM =.71 x 128 = 91 ounces

19 Application Equipment and Calibration MIXING PROCEDURE THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS: Active ingredient (a.i.) Product or Formulation

20 Application Equipment and Calibration MIXING PROCEDURE THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS: Active ingredient (a.i.) Product or Formulation needs adjustment!

21 Application Equipment and Calibration MIXING PROCEDURE: THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS: Active ingredient (a.i.) Product or Formulation ready to use!

22 Application Equipment and Calibration 8A.Dry Ingredient example #4: A recommendation of 2 lb. active ingredient (a.i.) per acre is given for benefluralin. The sprayer has a 400-gallon tank and is calibrated to apply 75 GPA. Determine the amount of Balan 60DF to be added to the tank. key word - active ingredient (a.i.) How many acres per tank? How much product per acre? How much product per tank?

23 Application Equipment and Calibration Answer Dry ingredient example solution: 5.3 A/tank X 3.3 lbs. product/A = 17.5 lbs

24 Application Equipment and Calibration 8B. Liquid ingredient example #5: An applicator needs to apply a broadleaf herbicide using a 400 gallon sprayer at a rate of 2 pounds (a.i.) active ingredient per acre. A 4EC material will be used. With a calibrated rate of 20 gallons per acre - how much herbicide will be needed to be added to the spray tank? key word - (a.i.) How many acres per tank? How much product per acre? How much product per tank?

25 Application Equipment and Calibration Liquid a.i. example solution: Answer 20 A/tank X 0.5 gpa product/A = 10 gal.

26 Application Equipment and Calibration 8C. Liquid formulation example #6: You are to spray a 4EC herbicide to a 5 acre turf area. The rate to apply is 1.5 quarts formulation in 20 gallons of water per acre. How much herbicide should be added to the tank? keyword - formulation Size of area? 5 acres

27 Application Equipment and Calibration Solution: What is the rate? 1.5 quarts/acre 1.5 quarts x 5 acres = 7.5 quarts

28 Application Equipment and Calibration 8D. Liquid formulation/area - #7: You have a product which is a 4E and recommended at the rate of 3.2 qts. per acre. How much of this product is needed to treat an area measuring 250 ft. by 575 ft.? _____ ft. X _____ ft. = ________ square feet 250575 143,750 3.3 ________ acres X 3.2 qts. =3.3 ______ qts 10.56

29 Application Equipment and Calibration Good Luck on Your Test!

30 Click to return to menu End of module


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