2 Vocabulary Terms Stoichiometry: Limiting Reagent: Excess Reagent: the calculation of quantities in chemical equation.Limiting Reagent:the reactant that determines the amount of product in a reaction.Excess Reagent:A quantity of a reactant that is more than enough to react with a limiting reagent.
3 Percent Yield: Actual Yield: Theoretical Yield: the ratio of the actual yield to the theoretical yield.Actual Yield:the amount of product formed when a reaction is carried out in the lab.Theoretical Yield:the calculated amount of product formed during a reaction.
4 Important Things To Remember: Always start with a balanced equation!Remember that you have to go through moles to convert from substance A to substance B.
5 1. _1_ CaCl2 + _2_ AgNO3 _1_ Ca(NO3)2 + _2_ AgCl How many grams of silver chloride are produced when 45 g of calcium chloride react with excess silver nitrate?=45 g CaCl21 mol CaCl2111 g CaCl20.405 mol CaCl20.811 mol AgCl0.405 mol CaCl22 mol AgCl1 mol CaCl2g AgCl0.811 mol AgCl143.5 g AgCl1 mol AgCl
6 __ C3H8 + _5_ O2 _4_H2O + _3_CO2How many moles of O2 should be supplied to burn 1 mol of C3H8 (propane) molecules in a camping stove?(write down the equation first; this is a simple Combustion equation and remember that it must be balanced before you continue.)If I had asked for grams instead of molecules, then the last step would be:1 mol C3H85 mol O2= 5 mol O25 mol O26.022 × molecules O21 mol O2= 𝟑.𝟎𝟏𝟏× 𝟏𝟎 𝟐𝟒 Molecules5 mol O232 g O21 mol O2= 160 g O2
7 _4_ Al + _3_ O _2_ Al2O3Calculate the mass of alumina (Al2O3) produced when 100 g of aluminum burns in oxygen.(write down the equation first; this is a simple Decomposition equation and remember that it must be balanced before you continue.)= 3.7 mol Al= 1.85 mol Al2O3= g Al2O3100 g Al1 mol Al27 g Al3.7 mol Al2 mol Al2O34 mol Al1.85 mol Al2O3102 g Al2O31 mol Al2O3
8 Review Answers Stoichiometry Practice Problems (Front) 2) 100 g CO2 1) g AgCl3) g I22) 2.21 g 𝐻 24) 343 mg H2O or g H2O3) 34.5 g Na5) 55 g H2O4) 292 g AgWorksheet # 2 Limiting Reactant5) mol NaBr1) g Cu / 𝐶𝑢𝑁𝑂 3 is limiting reagent6) 3.011× Molecules2) Yes, it is the limiting reagent7) 3 mol 𝑂 23) g CN2H4O / C 𝑂 2 is limiting8) g Al2O34.a) g NaCl / 67.42% yield9.a) 3214 g H2O or 3.2 kg H2O4.b) 11.9 g MgCl2 / 82.75% yield9.b) g Ca(OH) 2 or 13.2 kg Ca(OH) 24.c) 6.25 g AlCl3 / 157.6% yieldWorksheet # 1 Stoichiometry Practice5.a) 138 g 𝐻 3 𝑃𝑂 41) 770 g K2SO45.b) 91.46% yield