Download presentation

Presentation is loading. Please wait.

Published byLonnie Noseworthy Modified over 2 years ago

1
CHEM.B.1.1.1 Apply the mole concept to representative particles (e.g., counting, determining mass of atoms, ions, molecules, and/or formula units). CHEM.B.2.1.2 Use stoichiometric relationships to calculate the amounts of reactants and products involved in a chemical reaction. CHEM.B.2.1.1 Describe the roles of limiting and excess reactants in chemical reactions. CHEM.B.2.1.4 Predict products of simple chemical reactions (e.g., synthesis, decomposition, single replacement, double replacement, combustion).

2
What is Stoichiometry? Section 12.1

3
Define stoichiometry Identify mole ratios in a balanced chemical equation

4
Stoichiometry Mole ratios

5
Study of quantitative relationships between amounts of reactants used and products formed by a chemical reaction Based on law of conservation of mass

6
Ratio between number of moles of any 2 substances in a balanced chemical equation. 2Al + 3Br 2 2AlBr 3

7
Stoichiometric Calculations Section 12.2

8
Identify and apply the steps to solving stoichiometry problems

9
1. Write a balanced chemical equation 2. Convert grams of known to mols of known 3. Convert mols of known to mols of unknown (using mole ratios) 4. Convert mols of unknown to grams of unknown

10
25.0 g of NH 4 NO 3 produces N 2 O gas and H 2 O. Determine the mass of water produced. Known:Unknown: Mass of NH 4 NO 3 = 25.0 gMass of H 2 O = ?

11
1. Write the balanced chemical equation: NH 4 NO 3(s) N 2 O (g) + 2H 2 O (g) 2. Convert grams of NH 4 NO 3 to mol using the molar mass: 25.0 g NH 4 NO 3 x 1 mol NH 4 NO 3 = 0.3123 mol NH 4 NO 3 80.06 NH 4 NO 3 3. Determine the mole ratio of H2O to NH4NO3: 2 mol H 2 O 1 mol NH 4 NO 3 4. Multiply mol NH 4 NO 3 by the mole ratio: 0.3123 mol NH 4 NO 3 x 2 mol H 2 O = 0.6246 mol H 2 O 1 mol NH 4 NO 3 5. Calculate the mass of H 2 O using the molar mass: 0.6246 mol H 2 O x 18.02 g H 2 O = 11.3 g H 2 O 1 mol H 2 O

12
Page 363 #13

13
Stoichiometry worksheet

14
Limiting Reactants Section 12.3

15
Define limiting reactant Solve stoichiometry problems that incorporate limiting reactants

16
Limiting reactant: ◦ totally consumed during a chemical reaction ◦ limits the extent of the reaction ◦ determines the amount of product Excess reactant: ◦ NOT completely consumed in reaction ◦ Some remains after the reaction stops (limiting reactant runs out)

17
1. Convert grams of each reactant to mols 2. Divide mols by stoichiometric coefficient 3. The smaller number is the LR 4. Use the LR to do stoichiometric calculations

18
S 8 + 4Cl 2 4S 2 Cl 2 If 200. g of S reacts with 100. g of Cl, what mass of S 2 Cl 2 is produced? 1. Convert both masses to moles: 200. g S 8 x 1 mol S 8 = 0.7795 mol S 8 256.56 g S 8 100. g Cl 2 x 1 mol Cl 2 = 1.4104 mol Cl 2 70.90g Cl 2

19
2. Divide mols by coefficient from the equation: 1.4104 mol Cl 2 = 0.3526 0.7795 mol S 8 = 0.7795 4 mol Cl 2 1 mol S 8 3. The smaller one is the limiting reactant (Cl 2 )

20
4. Use the limiting reactant to determine the mass of S 2 Cl 2 as a stoichiometry problem from section 12.2: 100. g Cl 2 x 1 mol Cl 2 x 4 mol S 2 Cl 2 x 135.04 g S 2 Cl 2 70.90 g Cl 2 4 mol Cl 2 1 mol S 2 Cl 2 = 190. g S 2 Cl 2

21
The reaction between phosphorus and oxygen produced tetraphosphorus decaoxide. a. Determine the mass of P 4 O 10 formed if 25.0 g of P 4 and 50.0g of O 2 are combined. b. How much of the excess reactant remains after the reaction stops?

22
Limiting Reactants Worksheet

23
Percent Yield Section 12.4

24
Define theoretical, actual, and percent yield Solve stoichiometry problems for percent yields

25
Theoretical Yield: The maximum amount of product that can mathematically be produced Actual Yield: The amount of product produced in an experiment Percent Yield: The ratio of actual yield to theoretical yield

26
actual yield (from exp) x 100 theoretical yield (from calc)

27
14.0 g aluminum hydroxide reacts with hydrochloric acid, producing aluminum chloride and water. If the actual yield of aluminum chloride from this tablet is 22.0 g, what is the percent yield?

28
When 20.0 g copper wire is placed into a silver nitrate solution, a single replacement reaction occurs. If 60. g silver is actually recovered from the reaction, determine the percent yield of the reaction.

29
Percent Yield Worksheet

Similar presentations

OK

Quantitative Analysis. Deals with mass relationships of elements in compounds Formula (molar) mass Converting grams to moles to atoms/molecules Find.

Quantitative Analysis. Deals with mass relationships of elements in compounds Formula (molar) mass Converting grams to moles to atoms/molecules Find.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on statistics and probability letters Ppt on polynomials and coordinate geometry formulas Ppt on principles of peace building fund Ppt on regular expression validator Seven segment display ppt on tv Convert pdf ppt to ppt online shopping Ppt on recycling waste materials Easy ppt on bluetooth Ppt on regular expression reference Ppt on fire extinguisher types and sizes