Presentation on theme: "Chapter 10 Rotational Motion"— Presentation transcript:
1Chapter 10 Rotational Motion 10-1 Angular Quantities10-2 Vector Nature of Angular Quantities10-3 Constant Angular Acceleration10-4 TorqueChapter Opener. Caption: You too can experience rapid rotation—if your stomach can take the high angular velocity and centripetal acceleration of some of the fasteramusement park rides. If not, try the slower merry-go-round or Ferris wheel. Rotating carnival rides have rotational kinetic energy as well as angular momentum. Angular acceleration is produced by a net torque, and rotating objects have rotational kinetic energy.
2Two objects are sitting on a horizontal table that is undergoing uniform circular motion. Assuming the objects don’t slip, which of the following statements is true?A) Objects 1 and 2 have the same linear velocity, v.B) Object 1 has a faster linear velocity than object 2.C) Object 1 has a slower linear velocity than object 2.Question12
310-1 Angular QuantitiesObjects farther from the axis of rotation will move faster.They have different R, RB>RASo vB>vA even with the same ω.Figure Caption: A wheel rotating uniformly counterclockwise. Two points on the wheel, at distances RA and RB from the center, have the same angular velocity ω because they travel through the same angle θ in the same time interval. But the two points have different linear velocities because they travel different distances in the same time interval. Since RB > RA, then vB > vA (because v = Rω).
410-1 Angular QuantitiesIf the angular velocity of a rotating object changes, it has a tangential acceleration:Even if the angular velocity is constant, each point on the object has a centripetal acceleration:Figure Caption: On a rotating wheel whose angular speed is increasing, a point P has both tangential and radial (centripetal) components of linear acceleration. (See also Chapter 5.)
510-1 Angular QuantitiesHere is the correspondence between linear and rotational quantities:
610-1 Angular QuantitiesExample 10-3: Angular and linear velocities and accelerations.A carousel is initially at rest. At t = 0 it is given a constant angular acceleration α = rad/s2, which increases its angular velocity for 8.0 s. At t = 8.0 s, determine the magnitude of the following quantities: (a) the angular velocity of the carousel; (b) the linear velocity of a child located 2.5 m from the center; (c) the tangential (linear) acceleration of that child; (d) the centripetal acceleration of the child; and (e) the total linear acceleration of the child.Figure Caption: Example 10–3. The total acceleration vector a = atan + aR, at t = 8.0 s.Solution: a. The angular velocity increases linearly; at 8.0 s it is 0.48 rad/s.b. The linear velocity is 1.2 m/s.c. The tangential acceleration is 0.15 m/s2.d. The centripetal acceleration at 8.0 s is 0.58 m/s2.e. The total acceleration is 0.60 m/s2, at an angle of 15° to the radius.
710-1 Angular QuantitiesThe frequency is the number of complete revolutions per second:Frequencies are measured in hertz:The period is the time one revolution takes:
810-2 Vector Nature of Angular Quantities The angular velocity vector points along the axis of rotation, with the direction given by the right-hand rule. If the direction of the rotation axis does not change, the angular acceleration vector points along it as well.Figure Caption: (a) Rotating wheel. (b) Right-hand rule for obtaining direction of ω.
910-3 Constant Angular Acceleration The equations of motion for constant angular acceleration are the same as those for linear motion, with the substitution of the angular quantities for the linear ones.
1010-3 Constant Angular Acceleration Example 10-6: Centrifuge acceleration.A centrifuge rotor is accelerated from rest to 20,000 rpm in 30 s. (a) What is its average angular acceleration? (b) Through how many revolutions has the centrifuge rotor turned during its acceleration period, assuming constant angular acceleration?Solution: a. The final angular velocity is 2100 rad/s, so the acceleration is 70 rad/s2.b. The total angle is 3.15 x 104 rad, which is 5000 rev.
1110-4 TorqueTo make an object start rotating, a force is needed; the position and direction of the force matter as well.The perpendicular distance from the axis of rotation to the line along which the force acts is called the lever arm.Figure Caption: Top view of a door. Applying the same force with different lever arms, RA and RB. If RA = 3RB, then to create the same effect (angular acceleration), FB needs to be three times FA, or FA = 1/3 FB.