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Section 9.3 Limiting Reactants and Percent Yield Double Cheeseburgers and Stoichiometry 1 Double Cheeseburger needs 1 bun, 2 patties, 2 slices of cheese, 4 strips of bacon For 5 Double Cheeseburgers how many units of each ingredient do I need? Fill in the final column below with how many complete burgers I can make: BunsPattiesCheese Slices Bacon Strips How Many Burgers? 2448 44816 303248

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Section 9.3 Limiting Reactants and Percent Yield 1.To understand the concept of limiting reactants 2.To learn to recognize the limiting reactant in a reaction 3.To learn to use the limiting reactant to do stoichiometric calculations 4.To learn to calculate percent yield Objectives

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Section 9.3 Limiting Reactants and Percent Yield A. The Concept of Limiting Reactants Stoichiometric mixture –N 2 (g) + 3H 2 (g) 2NH 3 (g)

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Section 9.3 Limiting Reactants and Percent Yield Limiting reactant mixture A. The Concept of Limiting Reactants –N 2 (g) + 3H 2 (g) 2NH 3 (g)

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Section 9.3 Limiting Reactants and Percent Yield For a Limiting reactant mixture the number of moles are not balanced to match the reaction equation –N 2 (g) + 3H 2 (g) 2NH 3 (g) A. The Concept of Limiting Reactants –Limiting reactant is the reactant that runs out first –When the limiting reactant is exhausted, then the reaction stops

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Section 9.3 Limiting Reactants and Percent Yield B. Calculations Involving a Limiting Reactant

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Section 9.3 Limiting Reactants and Percent Yield Method 1: LAURA CHANG METHOD OF LR DETERMINATION Grams of reactant A- convert to moles and divide by the coefficient g/(g/mol)= x/coeff Grams of reactant B- convert to moles and divide by the coefficient (g/(g/mol)= x/coeff) The smaller value is the limiting reactant!

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Section 9.3 Limiting Reactants and Percent Yield Method 2: Calculations Involving a Limiting Reactant

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