# Section 9.3 Limiting Reactants and Percent Yield Double Cheeseburgers and Stoichiometry 1 Double Cheeseburger needs 1 bun, 2 patties, 2 slices of cheese,

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Section 9.3 Limiting Reactants and Percent Yield Double Cheeseburgers and Stoichiometry 1 Double Cheeseburger needs 1 bun, 2 patties, 2 slices of cheese, 4 strips of bacon For 5 Double Cheeseburgers how many units of each ingredient do I need? Fill in the final column below with how many complete burgers I can make: BunsPattiesCheese Slices Bacon Strips How Many Burgers? 2448 44816 303248

Section 9.3 Limiting Reactants and Percent Yield 1.To understand the concept of limiting reactants 2.To learn to recognize the limiting reactant in a reaction 3.To learn to use the limiting reactant to do stoichiometric calculations 4.To learn to calculate percent yield Objectives

Section 9.3 Limiting Reactants and Percent Yield A. The Concept of Limiting Reactants Stoichiometric mixture –N 2 (g) + 3H 2 (g)  2NH 3 (g)

Section 9.3 Limiting Reactants and Percent Yield Limiting reactant mixture A. The Concept of Limiting Reactants –N 2 (g) + 3H 2 (g)  2NH 3 (g)

Section 9.3 Limiting Reactants and Percent Yield For a Limiting reactant mixture the number of moles are not balanced to match the reaction equation –N 2 (g) + 3H 2 (g)  2NH 3 (g) A. The Concept of Limiting Reactants –Limiting reactant is the reactant that runs out first –When the limiting reactant is exhausted, then the reaction stops

Section 9.3 Limiting Reactants and Percent Yield B. Calculations Involving a Limiting Reactant

Section 9.3 Limiting Reactants and Percent Yield Method 1: LAURA CHANG METHOD OF LR DETERMINATION Grams of reactant A- convert to moles and divide by the coefficient g/(g/mol)= x/coeff Grams of reactant B- convert to moles and divide by the coefficient (g/(g/mol)= x/coeff) The smaller value is the limiting reactant!

Section 9.3 Limiting Reactants and Percent Yield Method 2: Calculations Involving a Limiting Reactant

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