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Stoichiometry. Stoichiometry Stoy – key – ohm – e - tree.

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Presentation on theme: "Stoichiometry. Stoichiometry Stoy – key – ohm – e - tree."— Presentation transcript:

1 Stoichiometry

2 Stoichiometry Stoy – key – ohm – e - tree

3 9.1 Introduction to Stoichiometry 1. Define Stoichiometry. 2. Describe the importance of the mole ratio in stoichiometric calculations. 3. Write a mole ratio relating two substances in a chemical equation. 4. Calculate the amount in moles of a reactant or product from the amount in moles of a different reactant or product.

4 Obj 1: What is Stoichiometry? Stoichiometry means Stoicheio = element Metron = measure Stoichiometry is the quantitative study of chemical reactions using balanced equations.

5 Obj 2: Mole Ratio Mole Ratios come from the coefficients in a balanced equation. Mole Ratios are used to convert moles of one substance (X) into moles of another substance (Y).

6 Obj 3: Mole Ratios from Balanced Equations 1 N H 2 2 NH 3 1 N H 2 2 NH 3 The Possible Mole Ratios are: The Possible Mole Ratios are:

7 Obj 3: Mole Ratios from Balanced Equations 1 N H 2 2 NH 3 1 N H 2 2 NH 3 The Possible Mole Ratios are: The Possible Mole Ratios are: 1 mol N 2 1 mol N 2 3 mol H 2 1 mol N 2 1 mol N 2 3 mol H 2 3 mol H 2 2 mol NH 3 2 mol NH 3 3 mol H 2 2 mol NH 3 2 mol NH 3

8 Obj 3: Mole Ratios from Balanced Equations 1 N H 2 2 NH 3 1 N H 2 2 NH 3 Other Possible Mole Ratios: Other Possible Mole Ratios: 1 mol N 2 1 mol N 2 3 mol H 2 1 mol N 2 1 mol N 2 3 mol H 2 3 mol H 2 2 mol NH 3 2 mol NH 3 3 mol H 2 2 mol NH 3 2 mol NH 3 1 mol N 2 1 mol N 2 3 mol H 2 1 mol N 2 1 mol N 2 3 mol H 2

9 Obj 4: Using a Mole Ratio 1 N H 2 2 NH 3 1 N H 2 2 NH mol N 2 ? mol H 2 ? mol NH mol N 2 ? mol H 2 ? mol NH 3

10 Obj 4: Using a Mole Ratio 1 N H 2 2 NH 3 1 N H 2 2 NH mol N 2 ? mol H 2 ? mol NH mol N 2 ? mol H 2 ? mol NH mol N 2 (3 mol H 2 ) = ? 7.5 mol N 2 (3 mol H 2 ) = ? (1 mol N 2 ) (1 mol N 2 )

11 Obj 4: Using a Mole Ratio 1 N H 2 2 NH 3 1 N H 2 2 NH mol N 2 ? mol H 2 ? mol NH mol N 2 ? mol H 2 ? mol NH mol N 2 (3 mol H 2 ) = 22.5 mol H mol N 2 (3 mol H 2 ) = 22.5 mol H 2 (1 mol N 2 ) (1 mol N 2 )

12 Using a Mole Ratio 1 N H 2 2 NH 3 1 N H 2 2 NH mol N mol H 2 ? mol NH mol N mol H 2 ? mol NH mol N 2 (2 mol NH 3 ) = ? 7.5 mol N 2 (2 mol NH 3 ) = ? (1 mol N 2 ) (1 mol N 2 )

13 Obj 4: Using a Mole Ratio 1 N H 2 2 NH 3 1 N H 2 2 NH mol N mol H 2 ? mol NH mol N mol H 2 ? mol NH mol N 2 (2 mol NH 3 ) = 15.0 mol NH mol N 2 (2 mol NH 3 ) = 15.0 mol NH 3 (1 mol N 2 ) (1 mol N 2 )

14 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: _ N 2 + _ H 2 _ NH 3 Double Batch: _ N 2 + _ H 2 _ NH 3

15 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: 2 N H 2 4 NH 3 Double Batch: 2 N H 2 4 NH 3

16 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: 2 N H 2 4 NH 3 Double Batch: 2 N H 2 4 NH 3 Triple Batch: _ N 2 + _ H 2 _ NH 3 Triple Batch: _ N 2 + _ H 2 _ NH 3

17 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: 2 N H 2 4 NH 3 Double Batch: 2 N H 2 4 NH 3 Triple Batch: 3 N H 2 6 NH 3 Triple Batch: 3 N H 2 6 NH 3

18 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: 2 N H 2 4 NH 3 Double Batch: 2 N H 2 4 NH 3 Triple Batch: 3 N H 2 6 NH 3 Triple Batch: 3 N H 2 6 NH 3 Half Batch: _ N 2 + _ H 2 _ NH 3 Half Batch: _ N 2 + _ H 2 _ NH 3

19 Obj 4: Cookie Stiochiometry One Batch: 1 N H 2 2 NH 3 One Batch: 1 N H 2 2 NH 3 Double Batch: 2 N H 2 4 NH 3 Double Batch: 2 N H 2 4 NH 3 Triple Batch: 3 N H 2 6 NH 3 Triple Batch: 3 N H 2 6 NH 3 Half Batch: 0.5 N H 2 1 NH 3 Half Batch: 0.5 N H 2 1 NH 3

20 Lets Look at Our Problem Again We want 7.5 batch ! 1 N H 2 2 NH 3 1 N H 2 2 NH 3 __ mol N 2 ___ mol H 2 __ mol NH 3 __ mol N 2 ___ mol H 2 __ mol NH 3

21 Lets Look at Our Problem Again We want 7.5 batch ! 1 N H 2 2 NH 3 1 N H 2 2 NH mol N mol H mol NH mol N mol H mol NH 3

22 The End The Final Curtain


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