Download presentation

Presentation is loading. Please wait.

Published byBryce Wolffe Modified about 1 year ago

1
Summary of Sampling, Line Codes and PCM Prepared for ELE 745 Xavier Fernando Ryerson Communications Lab

2
Signal Sampling Sampling is converting a continuous time signal into a discrete time signal Categories: – Impulse (ideal) sampling – Natural Sampling – Sample and Hold operation

3
Impulse Sampling

4
Impulse train spaced at T s multiplies the signal x(t) in time domain, creating – discrete time, – continuous amplitude signal x s (t) Impulse train spaced at f s convolutes the signal X(f) in frequency domain, creating – Repeating spectrum X s (f) – spaced at f s

5
The Aliasing Effect f s > 2f m f s < 2f m Aliasing happens

6
Aliasing Under sampling will result in aliasing that will create spectral overlap

7
Ideal Sampling and Aliasing Sampled signal is discrete in time domain with spacing T s Spectrum will repeat for every f s Hz Aliasing (spectral overlapping) if f s is too small (f s < 2f m ) Nyquist sampling rate f s = 2f m Generally oversampling is done f s > 2f m

8
Natural Sampling

9
Sampling pulse train has a finite width τ Sampled spectrum will repeat itself with a ‘Sinc’ envelope More realistic modeling Distortion after recovery depends on τ/T s

10
Different Sampling Models

11
Quantization Quantization is done to make the signal amplitude discrete Analog Signal Sampling Discrete Time Cont. Ampl. Signal Quantization Discrete Time & Discrete Ampl Signal Mapping Binary Sequence

12
Linear Quantization L levels (L-1)q = 2V p = V pp For large L Lq ≈ V pp

13
PCM Mapping

14
Linear Quantization Summary Mean Squared Error (MSE) = q 2 /12 Mean signal power = E[m 2 (t)] Mean SNR = 12 E[m 2 (t)]/q 2 For binary PCM, L = 2 n n bits/sample Let signal bandwidth = B Hz – If Nyquist sampling 2B samples/sec – If 20% oversampling 1.2(2B) samples/sec Bit rate = 2nB bits/sec Required channel bandwidth = nB Hz

15
Non-Uniform Quantization In speech signals, very low speech volumes predominates – Only 15% of the time, the voltage exceeds the RMS value These low level signals are under represented with uniform quantization – Same noise power (q 2 /12) but low signal power The answer is non uniform quantization

16
UniformNon-Uniform

17
Non-uniform Quantization Compress the signal first Then perform linear quantization Result in nonlinear quantization

18
µ-law and A-law Widely used compression algorithms

19
Line Coding Digital output of the PCM coder is converted to an appropriate waveform for transmission over channel line coding or transmission coding Different line codes have different attributes Best line code has to be selected for a given application and channel condition

20
Line Coded Waveforms - I NRZ – Non Return to Zero -Level NRZ – Non Return to Zero -Mark (0 no change, 1 change) NRZ – Non Return to Zero -Space (1 no change, 0 change) Bipolar Return to Zero AMI – Alternate Mark Inversion (zero zero, 1 alternating pulse)

21
Bi-Phase level (1 +v-v, 0 -v+v) Bi Phase Mark Bi-Phase Space Delay Modulation Dicode NRZ Dicode RZ

22
Line Coding Requirements Favorable power spectral density (PSD) Low bandwidth (multilevel codes better) No/little DC power Error detection and/or correction capability Self clocking (Ex. Manchester) Transparency in generating the codes (dependency on the previous bit?) Differential encoding (polarity reversion) Noise immunity (BER for a given SNR)

23
Some Power Spectral Densities

24
Polar Signalling {p(t) or –p(t)} Polar signalling is not bandwidth efficient (best case BW = R b. Theoretical min is R b /2) Non-zero DC No error detection (each bit is independent) Efficient in power requirement Transparent Clock can be recovered by rectifying the received signal

25
On-Off Signalling On-off is a sum of polar signal and periodic clock signal (Fig. 7.2) spectrum has discrete freq. Components Polar amplitude is A/2 PSD is scaled by ¼ No error detection Excessive zeros cause error in timing extraction Excessive BW Excessive DC

26
AMI (bipolar) Signalling DC null Single error detection (violation) capability Clock extraction possible Twice as much power as polar signalling Not transparent Excessive zeros cause timing extraction error HDB or B8ZS schemes used to overcome this issue

27
Bipolar with 8 Zeros Substitution B8ZS uses violations of the Alternate Mark Inversion (AMI) rule to replace a pattern of eight zeros in a row V 1 0 V 1 Example: (-) OR (+) B8ZS is used in the North American telephone systems at the T1 rate

28
High Density Bipolar 3 code HDB3 encodes any pattern of more than four bits as B00V (or 100V; 1B (Bit)) Ex: The pattern of bits (AMI) Encoded in HDB3 is: + - B 0 0 V - + B 0 0 V 0 0, which is:

29
M-Ary Coding (Signaling) In binary coding: – Data bit ‘1’ has waveform 1 – Data bit ‘0’ has waveform 2 – Data rate = bit rate = symbol rate In M-ary coding, take M bits at a time (M = 2 k ) and create a waveform (or symbol). – ‘00’ waveform (symbol) 1 – ‘01’ waveform (symbol) 2 – ‘10’ waveform (symbol) 3 – ‘11’ waveform (symbol) 2 – Symbol rate = bit rate/k

30
M-Ary Coding Advantages: – Required transmission rate is low (bit rate/M) – Low bandwidth Disadvantages: – Low signal to noise ratio (due to multiple amplitude pulses)

31
M-ary Signaling 8-level signaling 2-level signaling

32
M-ary (Multilevel) Signaling M-ary signals reduce required bandwidth Instead of transmitting one pulse for each bit (binary PCM), we transmit one multilevel pulse a group of k-bits (M=2 k ) Bit rate = R b bits/s min BW = R b /2 Symbol rate = R/k sym/s min BW = R b /2k Needed bandwidth goes down by k Trade-off is relatively high bit error rate (BER)

33
Inter Symbol Interference (ISI) Unwanted interference from adjacent (usually previous) symbols

34
Nyquist's First Criterion for Zero lSI In the first method Nyquist achieves zero lSI by choosing a pulse shape that has a nonzero amplitude at its center (t=0) and zero amplitudes at (t=±nT" (n = I )).

35
Min. BW Pulse satisfying the first criteria

36
Zero ISI Pulse

37
Vestigial Spectrum

38
Raised Cosine Pulse r=0 (f x =0) r=0.5 (f x =Rb/4) r=1 (f x =Rb/2)

39
Raised Cosine Filter Transfer Function in the f domain

40
Raised Cosine Filter Impulse Response (time domain) Note pulse rapidly decays for r = 1

41
Equalization The residual ISI can be removed by equalization Estimate the amount of ISI at each sampling instance and subtract it

42
Eye Diagram Ideal (perfect) signal Real (average) signal Bad signal

43
Eye Diagram Run the oscilloscope in the storage mode for overlapping pulses X-scale = pulse width Y-Scale = Amplitude Close Eye bad ISI Open Eye good ISI

44
Time Division Multiplexing (TDM) TDM is widely used in digital communication systems to maximum use the channel capacity Digit Interleaving

45
TDM – Word Interleaving

46
TDM When each channel has R b bits/sec bit rate and N such channels are multiplexed, total bit rate = NR b (assuming no added bits) Before Multiplexing the bit period = T b After Multiplexing the bit period = T b /N Timing and bit rate would change if you have any added bits

47
North American PCM Telephony Twenty four T1 carriers (64kb/s) are multiplexed to generate one DS1 carrier (1.544 Mb/s)

48
Each channel has 8 bits – 24 Channels Each frame has 24 X 8 = 192 information bits Frame time = 1/8000 = 125 μs.

49
T1 System Signalling Format 193 framing bits plus more signalling bits final bit rate = Mb/s

50
North American Digital Hierarchy

51
Delta Modulation Why transmit every sample? You know the next amplitude will differ by only ‘delta’

52
Delta Modulation Why transmit every sample? You know the next amplitude will differ by only ‘delta’ Only transmit the error

53
LPC Coding In modern communicatio n system, the voice is artificially generated at the receiver mimicking the original voice using the appropriate coefficients Transmit only few gain coefficients!

54
Example -1 Sklar 3.8: (a) What is the theoretical minimum system bandwidth needed for a 10 Mb/s signal using 16-level PAM without ISI? (b) How large can the filter roll-off factor (r) be if the applicable system bandwidth is MHz?

55
Solution

56
Example - 2 Sklar 3.10: Binary data at 9600 bits/s are transmitted using 8-ary PAM modulation with a system using a raised cosine roll-off filter characteristics. The system has a frequency response out to 2.4 kHz. (a) What is the symbol rate (b) What is the roll o® factor r

57
Example 3 Sklar 3.11: A voice signal in the range 300 to 3300 Hz is sampled at 8000 samples/s. We may transmit these samples directly as PAM pulses or we may first convert each sample to a PCM format and use binary (PCM) waveform for transmission. (a)What is the minimum system bandwidth required for the detection of PAM with no ISI and with a filter roll-off factor of 1. (b) Using the same roll-off, what is the minimum bandwidth required for the detection of binary PCM waveform if the samples are quantized to 8-levels (c) Repeat part (b) using 128 quantization levels.

58

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google