1. NICKO SIA STEPHANIE NG ISABEL MIRANDA MATTHEUI TADEO

2. PROBLEM #1 Justin grossed $435 one week by working 52 hours. Her employees pay time-a-half for all hours. With this information, can you determine Justin’s regular hourly wage?

3. Step 1: We are looking for an hourly wage. Our answer will be in dollars per hour. Step 2: Let x represent the regular hourly wage; x is measured in dollars per hour. Step 3: We set up the table: HOURS WORKEDHOURLY WAGESalary Regular40x40x Day time121.5x12(1.5) = 18x Step 4: 40x+18x = 435 18x = 435 x=7.50 Answer: Justin’s regular hourly wage is $7.50 per hour.

4. Miguel is 46 years old. He is 4 years older than thrice his son’s age. Find the age of his son.

5. Age of Miguel = 46 years Age of son = x years So, 46=4+3x Subtracting 4 on both sides, 42 = 3x Dividing by 3 on both sides x = 14 Therefore the Son is 14 years old.

6. A total of $18,000 is invested, some in stocks and some in bonds. If the amount invested in bonds is half that invested in stocks, how much is invested in each category?

7. Step 1: We are being asked to find the amount of two inventions. These amounts must total $18,000. Step 2: Let x represents the equal amount invested in stocks then 18,000 – x is the amount invested in bonds. Step 3: We set up the table

8. Amount of stocksAmount in BondsReason x18,000 - xTotal invested is $18,000 Total amount is invested in bonds is one half that in stocks 18,000 – x = ½ x Step 4: 18,000-x = ½ x 18,000 = x + ½ x; add x to both sides 18,000 = 3/2 x; simplify (2/3)18,00= (2/3) (2/2 x); multiply both sides by 2/3 12,000 = x; simplify Answer: So $12,000 is invested in stocks and $18,000 - $12,000 = $6000. The total invested in bonds is $12,000 +6,000 = 18,000, and the amount in bonds, $6,000, is half that in stocks $12,000.

9. Source: Sheldon Jay Axler, Linear Algebra done Wight, published 1996 in New York, Chapter 3 page 91-92