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NICKO SIA STEPHANIE NG ISABEL MIRANDA MATTHEUI TADEO

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PROBLEM #1 Justin grossed $435 one week by working 52 hours. Her employees pay time-a-half for all hours. With this information, can you determine Justin’s regular hourly wage?

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Step 1: We are looking for an hourly wage. Our answer will be in dollars per hour. Step 2: Let x represent the regular hourly wage; x is measured in dollars per hour. Step 3: We set up the table: HOURS WORKEDHOURLY WAGESalary Regular40x40x Day time121.5x12(1.5) = 18x Step 4: 40x+18x = 435 18x = 435 x=7.50 Answer: Justin’s regular hourly wage is $7.50 per hour.

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Miguel is 46 years old. He is 4 years older than thrice his son’s age. Find the age of his son.

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Age of Miguel = 46 years Age of son = x years So, 46=4+3x Subtracting 4 on both sides, 42 = 3x Dividing by 3 on both sides x = 14 Therefore the Son is 14 years old.

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A total of $18,000 is invested, some in stocks and some in bonds. If the amount invested in bonds is half that invested in stocks, how much is invested in each category?

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Step 1: We are being asked to find the amount of two inventions. These amounts must total $18,000. Step 2: Let x represents the equal amount invested in stocks then 18,000 – x is the amount invested in bonds. Step 3: We set up the table

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Amount of stocksAmount in BondsReason x18,000 - xTotal invested is $18,000 Total amount is invested in bonds is one half that in stocks 18,000 – x = ½ x Step 4: 18,000-x = ½ x 18,000 = x + ½ x; add x to both sides 18,000 = 3/2 x; simplify (2/3)18,00= (2/3) (2/2 x); multiply both sides by 2/3 12,000 = x; simplify Answer: So $12,000 is invested in stocks and $18,000 - $12,000 = $6000. The total invested in bonds is $12,000 +6,000 = 18,000, and the amount in bonds, $6,000, is half that in stocks $12,000.

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Source: Sheldon Jay Axler, Linear Algebra done Wight, published 1996 in New York, Chapter 3 page 91-92

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