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Mindjog 9/11 Describe and find the roots: Describe and find the roots: 5x 2 + 2x – 4 = 0 5x 2 + 2x – 4 = 0 x 2 – 10x = -25 x 2 – 10x = -25 2x 2 – x + 1.

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Presentation on theme: "Mindjog 9/11 Describe and find the roots: Describe and find the roots: 5x 2 + 2x – 4 = 0 5x 2 + 2x – 4 = 0 x 2 – 10x = -25 x 2 – 10x = -25 2x 2 – x + 1."— Presentation transcript:

1 Mindjog 9/11 Describe and find the roots: Describe and find the roots: 5x 2 + 2x – 4 = 0 5x 2 + 2x – 4 = 0 x 2 – 10x = -25 x 2 – 10x = -25 2x 2 – x + 1 = 0 2x 2 – x + 1 = 0

2 OBJECTIVE SWBAT SWBAT Write and solve problems involving quadratic equations Write and solve problems involving quadratic equations

3 Geometric A piece of machinery produces rectangular sheets of metal such that the length is 3 times the width. Equal-sized squares measuring 5in. on one side can be cut from the corners so that the metal can be folded to form a box. If the volume of the box has to be 1,435in 3, what should the dimensions of the metal be? A piece of machinery produces rectangular sheets of metal such that the length is 3 times the width. Equal-sized squares measuring 5in. on one side can be cut from the corners so that the metal can be folded to form a box. If the volume of the box has to be 1,435in 3, what should the dimensions of the metal be?

4 Geometric 1,435 = (3x – 10) (x – 10)(5) 1,435 = (3x – 10) (x – 10)(5) x = -11/3 or 17 x = -11/3 or 17

5 Pythagorean Theorem Mike buys a piece of property in the shape of a right triangle. The longer leg is 20yds longer than twice the length of the shorter leg. The hypotenuse is 10yds longer than the longer leg. Find the lengths of his property. Mike buys a piece of property in the shape of a right triangle. The longer leg is 20yds longer than twice the length of the shorter leg. The hypotenuse is 10yds longer than the longer leg. Find the lengths of his property.

6 Pythagorean Theorem s 2 + (2s +20) 2 = (2s + 30) 2 s 2 + (2s +20) 2 = (2s + 30) 2 s = 50 or -10 s = 50 or -10

7 Projectiles s = -16t 2 + v 0 t + s 0 s = -16t 2 + v 0 t + s 0 s = height s = height s 0 = initial height s 0 = initial height v 0 = initial velocity v 0 = initial velocity t = time t = time

8 Projectiles A projectile is shot vertically upward from the ground with an initial velocity of 100ft/sec. A projectile is shot vertically upward from the ground with an initial velocity of 100ft/sec. After how many seconds will it be 50ft above the ground? After how many seconds will it be 50ft above the ground? How long will it take for the projectile to return to the ground? How long will it take for the projectile to return to the ground?

9 Projectiles s = -16t 2 + 100t s = -16t 2 + 100t t =.55 and 5.70 t =.55 and 5.70 t = 0 and 6.25 t = 0 and 6.25

10 CLASSWORK (9/14) Handout Handout #’s 173-180, pick 3 #’s 173-180, pick 3 #’s 181-185, pick 3 #’s 181-185, pick 3 #’s 186-190, pick 3 #’s 186-190, pick 3

11 HOMEWORK p. 128, #’s 20-22, 32-34, 43, 46 p. 128, #’s 20-22, 32-34, 43, 46 Quiz tomorrow!!! Quiz tomorrow!!!


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